How to display rows in PSA having count(wbs) 1

Hi there BW gurus.
I have a history in the SQL world, where it is quite easy to write a SQL code to get out the rows from a table with duplicates in one spesific field. (Beeing indexed or not)
I have tried to search for this option where we diplays the content in an PSA. but not found it.
Anyone having a good solution for this.
(I am not an ABAP-er)
Best Regards Ingrid

Hi Ingrid,
following ABAP returns all languages which more than one user is assigned to.
data: l_langu type usr01-langu.
data: l_Num type i.
SELECT count( * ) langu
into (l_Num, l_langu)
FROM usr01
GROUP BY langu
having count( * ) GT 1.
write: / l_langu, ' - ', l_num.
endselect.
e.g. language E is assigned to 27 users.
Hope this gives you an idea.
Regards,
Jürgen

Similar Messages

How to display row to columns without using pivot keyword

hi,
could someone help me how to dispaly rows into columns without using pivot keyword and actuall my scenario is,iam having two tables with names and sample data is shown below
ID PROJECT MID MINAME TASKID TASKNAME
1     PROJ1     1     AA     100     PR1_TASK1
1     PROJ1     3     CC     102     PR1_TASK3
1     PROJ1     4     DD     103     PR1_TASK4
1     PROJ1     5     EE     104     PR1_TASK5
1     PROJ1     6     FF     105     PR1_TASK6
2     PROJ2     5     EE     114     PR2_TASK1
2     PROJ2     6     FF     115     PR2_TASK2
2     PROJ2     7     GG     116     PR2_TASK3
2     PROJ2     8     HH     117     PR2_TASK4
2     PROJ2     9     JJ     118     PR2_TASK5
2     PROJ2     10     KK     119     PR2_TASK6
2     PROJ2     1     AA     120     PR2_TASK7
The output should display project and count of tasks in particular milestone as shown below
project AA BB CC DD EE FF GG HH JJ KK
1 2 0 1 5 3 2 0 2 1 0
2 1 2 0 2 1 0 2 4 3 1
Thanks in advance ,
vvr

WITH t1 AS
(SELECT 1 ID,
         'PROJ1' PROJECT,
         1 MID,
         'AA' MINAME,
         100 TASKID,
         'PR1_TASK1' TASKNAME
    FROM DUAL
UNION
SELECT 1, 'PROJ1', 3, 'CC', 102, 'PR1_TASK3'
    FROM DUAL
UNION
SELECT 1, 'PROJ1', 4, 'DD', 103, 'PR1_TASK4'
    FROM DUAL
UNION
SELECT 1, 'PROJ1', 5, 'EE', 104, 'PR1_TASK5'
    FROM DUAL
UNION
SELECT 1, 'PROJ1', 6, 'FF', 105, 'PR1_TASK6'
    FROM DUAL
UNION
SELECT 2, 'PROJ2', 5, 'EE', 114, 'PR2_TASK1'
    FROM DUAL
UNION
SELECT 2, 'PROJ2', 6, 'FF', 115, 'PR2_TASK2'
    FROM DUAL
UNION
SELECT 2, 'PROJ2', 7, 'GG', 116, 'PR2_TASK3'
    FROM DUAL
UNION
SELECT 2, 'PROJ2', 8, 'HH', 117, 'PR2_TASK4'
    FROM DUAL
UNION
SELECT 2, 'PROJ2', 9, 'JJ', 118, 'PR1_TASK5'
    FROM DUAL
UNION
SELECT 2, 'PROJ2', 10, 'KK', 119, 'PR1_TASK6'
    FROM DUAL
UNION
SELECT 2, 'PROJ2', 1, 'AA', 120, 'PR1_TASK7' FROM DUAL)
SELECT id project,
       NVL((SELECT mid
             FROM t1
            WHERE miname = 'AA'
              AND id = t_out.id),
           0) AA,
       NVL((SELECT mid
             FROM t1
            WHERE miname = 'BB'
              AND id = t_out.id),
           0) BB,
       NVL((SELECT mid
             FROM t1
            WHERE miname = 'CC'
              AND id = t_out.id),
           0) CC,
       NVL((SELECT mid
             FROM t1
            WHERE miname = 'DD'
              AND id = t_out.id),
           0) DD,
       NVL((SELECT mid
             FROM t1
            WHERE miname = 'EE'
              AND id = t_out.id),
           0) EE,
       NVL((SELECT mid
             FROM t1
            WHERE miname = 'FF'
              AND id = t_out.id),
           0) FF,
       NVL((SELECT mid
             FROM t1
            WHERE miname = 'GG'
              AND id = t_out.id),
           0) GG,
       NVL((SELECT mid
             FROM t1
            WHERE miname = 'HH'
              AND id = t_out.id),
           0) HH,
       NVL((SELECT mid
             FROM t1
            WHERE miname = 'JJ'
              AND id = t_out.id),
           0) JJ,
       NVL((SELECT mid
             FROM t1
            WHERE miname = 'KK'
              AND id = t_out.id),
           0) KK
FROM (SELECT DISTINCT id FROM t1) t_out
PROJECT     AA     BB     CC     DD     EE     FF     GG     HH     JJ     KK
1     1     0     3     4     5     6     0     0     0     0
2     1     0     0     0     5     6     7     8     9     10As I understand, you want MID of MINAMEs displayed ? But output is not like yours.. What is exactly your requirements?

OBIEE:How to display row/columns where no data is present in pivot results?

I have a request from some team members to provide an OBIEE report of 7 teams and the number of open incidents for each team by week.
I was able to create the pivot listing the teams vertically and the age (by week#: 1 week, 2 weeks, 3 weeks, 4 weeks & > 4weeks) horizontally.
The dilemma I have is that of the 7 teams that have incidents tickets only 4 of them have data, thus only those 4 teams that have ticket data show up in my pivot. I would like to be able to reflect ALL 7 teams even if representing a dash or null value across the pivot for those teams that don't have data.
Does anyone know if this is possible and if so, how would I do this? I've tried searching the internet and found out how to replace a null value with a dash in columns/rows when a cell is null. But not how to display an entire row (or column) where no data is present.
Edited by: coutya on May 22, 2012 11:01 AM
Edited by: coutya on May 22, 2012 11:02 AM

You are correct; if there are no data at all, those teams won't show in a pivot table. NULLs or dashes only work if a particular column is null. There are two ways to accomplish what you wish. The first example I thought when I wasn't aware of being able to do a LEFT OUTER JOIN in Answers using the Advanced tab. The first method works nicely, though and is simpler to execute.
Read my solution here:
Re: Section Values showing NULL in Pivot
To do the LEFT OUTER JOIN read this:
http://gerardnico.com/wiki/dat/obiee/multiple_subject_area
Both will get you what you want...

How to display rows of data in JSP?

Hi,
I am learning Servlet and JSP. There is an exercise which requires us to access a database from a Servlet and display the retrieved data in a JSP.
Now I am ok with the database connection. So how to display the data using some kind of loop?
Regards

They're called ResultSets and they are returned when you execute a query from a Statement. The next() method will tell you whether or not you have another row of data to read.

How to display Rows as Columns in JSF?

I am using dataTable component to get data for my Menu, i have one column in it which returns me the data, because its automatically adding <tr> and <td> tags to it, its showing data in tabular form.
I want to show output Horizontally instead of Vertically the way its showing.
Is their any way i can display Rows as Columns?
Code:
==============================================
<div class="bodyarea">
<div id="location">
<h:dataTable value="#{menuItem.breadCrumb}" var="bread" >
<f:verbatim><ol></f:verbatim>
<h:column>
<f:verbatim><li></f:verbatim>
<h:outputLink id="crumbID" value="#{bread.menuLink}">
<h:outputText id="crumpName" value="#{bread.menuLabel}"/>
</h:outputLink>
<f:verbatim></li></f:verbatim>
</h:column>
<f:verbatim></ol></f:verbatim>
</h:dataTable>
</div>
</div>
Thank you

Table is not the html element for you, in this situation.
I would use a dataList component (distributed with myfaces implementation).
dataList is able to return a list of item, and using css you will be able display in a horizontal grid. (otherwise you can use layout="grid" in dataList).
Anyway...my impression is that who made JSF was not really understanding how a html programmer like to write his code.
Why do JSF gives us only the possibility to write list of items throught tables?
Why do JSF prints error messages throught tables?
Why div is not a standard component?
This is an incredible lack...
I see also other incredible lasks...but they don't concern html ;) .

How to display Calendar view without having to select date

Hi there,
I would like to know can I display Calendar view without having user to select date first.
And also, how do I highlight the date in calendar view for example, to show that i have set a reminder on that date?
I have searched many threads before, but I could not get the final answer.

Hi,
Is there a way to display a full calendar popup with time stamp so the users can pick the timestamp from the popup?Date Picker doesn't have this feature. You can use Javascript to achieve the same. But at same time it's highly unrecommended to use javascript with OAF pages.
Regards,
Gyan

How to display row number in form?

Hi guys,
First I fll you in on the story so far..
I have a database data block named :V_PAYUPLOADHEADER_HP, in the property palette I set order by facility and warehouse.
I want to display row number for each fetched record, so I make :V_PAYUPLOADHEADER_HP.NUMB, which will contain the row number.
The following is some methods that I already tried:
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The result is the number jump around (3, 1, 2, 5, 4 etc. instead of 1, 2, 3, 4, 5) I think it is because of the order by that I set.
I have to keep this order by setting, so I look for another way to display the rownum.
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When I run it all the value of :V_PAYUPLOADHEADER_HP.NUMB is 1. For all the records fetched is 1, 1, 1, 1 instead of 1, 2, 3, 4.
- I also tried using POST-QUERY trigger attached to the block.
In the trigger I have this code:
:V_PAYUPLOADHEADER_HP.NUMB := :system.cursor_record;
When I run it all the value of :V_PAYUPLOADHEADER_HP.NUMB is 1. For all the records fetched is 1, 1, 1, 1 instead of 1, 2, 3, 4..
Is there something that I missed?
What can I do to display the rownum?

Hi
You can achieve this by adding new item named 'ROWNUM'. in the Data Block you are working on.
And it's 'BASE TABLE ITEM' property needs to be set as TRUE'. IN the property ,IN the post-query Trigger use...
SELECT ROWNUM
INTO :ROWNUM
FROM TABLE
WHERE EMP_ID =EMP_ID;Hope this helps...
Regards,
Abdetu...

How to display rows of data into different columns?

I'm new to SQL and currently this is what I'm trying to do:
Display multiple rows of data into different columns within the same row
I have a table like this:
    CREATE TABLE TRIPLEG(
        T#              NUMBER(10)      NOT NULL,
        LEG#            NUMBER(2)       NOT NULL,
        DEPARTURE       VARCHAR(30)     NOT NULL,
        DESTINATION     VARCHAR(30)     NOT NULL,
        CONSTRAINT TRIPLEG_PKEY PRIMARY KEY (T#, LEG#),
        CONSTRAINT TRIPLEG_UNIQUE UNIQUE(T#, DEPARTURE, DESTINATION),
        CONSTRAINT TRIPLEG_FKEY1 FOREIGN KEY (T#) REFERENCES TRIP(T#) );
    INSERT INTO TRIPLEG VALUES( 1, 1, 'Sydney', 'Melbourne');
    INSERT INTO TRIPLEG VALUES( 1, 2, 'Melbourne', 'Adelaide');
The result should be something like this:
> T# | ORIGIN | DESTINATION1 | DESTINATION2
> 1   | SYDNEY | MELBORUNE     | ADELAIDE
The query should include the `COUNT(T#) < 3` since I only need to display the records less than 3. How can I achieve the results that I want using relational views???
Thanks!!!

T#
LEG#
DEPARTURE
DESTINATION
1
1
Sydney
Melbourne
1
2
Melbourne
Adelaide
1
3
Adelaide
India
1
4
India
Dubai
2
1
India
UAE
2
2
UAE
Germany
2
3
Germany
USA
On 11gr2, you may use this :
SELECT t#,
         REGEXP_REPLACE (
            LISTAGG (departure || '->' || destination, ' ')
               WITHIN GROUP (ORDER BY t#, leg#),
            '([^ ]+) \1+',
            '\1')
    FROM tripleg
    where leg#<=3
GROUP BY t#;
Output:
1 Sydney->Melbourne->Adelaide->India
2 India->UAE->Germany->USA
Cheers,
Manik.

How to display rows from index 1 to all in a table

Hi,
I am facing a problem please help me.
I created a node in context with cardinality 1..n so that there will always be a element present for that node.
From one view i am providing data to this node and adding new blank element to this node.
I binded a table from view to this node so that it is displaying all the rows with a blank row at the start.
Now i want to display all the elements of that node except that blank first element in to a table

Hi Amol,
You can invalidate the node before and then add the elements from the second table or you can remove the blank element from the node.
you can use the following code to remove an element
int listSize = wdContext.node<Node Name>().size();
if(listSize > 0)
for(int i = listSize - 1; i >= 0; --i)
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wdContext.node<Node Name>().invalidate();

How to display rows as columns?

Hi,
I am simulating my problem with the following example.
I have two tables, book_info contains book_id(primary key), book_name and the other table is author_info contains id(primary key), book_id and author. One book may have maximum upto THREE authors.
BOOK_INFO
=========
book_id category book_name
1 a ABC
2 a PQR
3 b XYZ
AUTHOR_INFO
===========
id book_id author
1 1 aaaaaa
2 1 bbbbbb
3 1 cccccc
4 2 pppppp
5 2 qqqqqq
6 3 xxxxxx
I need output like different columns using a sql query WHERE category = 'a'.
book_id book_name author1 author2 author3
1 ABC aaaaaa bbbbbb cccccc
2 PQR pppppp pppppp
We are using Oracle 9i/NT environment. Urgent please.
Thank you.

Vijaya,
Looks like I just answered this question, though your table layout is pretty much the same. Here what I said ...
There actually is a couple ways to do this, but the term is called FLATTENING. The method I like is with a function and a view (I'm a huuuuge fan of views). It has some draw backs performance wise if doing this on allot of data, but the results are well worth it. Anyway the code is below. The table is T1, the view it makes is V1. The function is called FN_REC_FLAT. Some sample output is also included.
16:46:11 SQL> SELECT T1.N1,T1.N2,T1.C1 FROM TABLE_NAME_HERE T1 ORDER BY T1.N1,T1.N2;
N1 N2 C1
-1 1 TEST
1 1 THIS
1 2 IS RECORD
1 3 NUMBER 1.
2 1 THIS IS
2 2 RECORD
2 3 NUMBER 2.
3 1 AND THIS
3 2 IS RECORD
3 3 NUMBER 3.
10 rows selected.
CREATE OR REPLACE FUNCTION
FN_REC_FLAT(PI_FLAT_KEY IN NUMBER,PS_FLAT_DATA IN VARCHAR)
RETURN VARCHAR AS
CURSOR CUR_T1 IS SELECT * FROM TABLE_NAME_HERE T1 WHERE T1.N1 = PI_FLAT_KEY ORDER BY T
REC_T1 TABLE_NAME_HERE%ROWTYPE;
LS_FLAT_DATA VARCHAR2(2000);
LS_RETURN VARCHAR2(2000);
BEGIN
LS_FLAT_DATA := NULL;
OPEN CUR_T1;
FETCH CUR_T1 INTO REC_T1;
WHILE CUR_T1%FOUND LOOP
LS_FLAT_DATA := (LS_FLAT_DATA || ' ' || REC_T1.C1);
FETCH CUR_T1 INTO REC_T1;
END LOOP;
LS_RETURN := TRIM(LS_FLAT_DATA);
RETURN LS_RETURN;
END;
Function created.
CREATE OR REPLACE VIEW V1 (N1,C1) AS SELECT DISTINCT T1.N1,FN_REC_FLAT(T1.N1,T1.C1) FROM TABLE_NAME_HERE T1;
View created.
16:46:12 SQL>
16:46:12 SQL> SELECT T1.N1,T1.C1 FROM V1 T1 ORDER BY T1.N1,T1.C1;
N1 C1
-1 TEST
1 THIS IS RECORD NUMBER 1.
2 THIS IS RECORD NUMBER 2.
3 AND THIS IS RECORD NUMBER 3.
16:46:12 SQL>
Note that the function takes in N1 as the root level for the flatten key. N2 is the sort order. In you case this would be EMP_ID and EMP_INFO_SEQ_NUM. The C1 is EMP_INFO. T1 is the table alias and TABLE_NAME_HERE ... well I'll let you figure that part out ;).
Hope this helps,
Tyler D.

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2
3 and so on
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chk this code...
REPORT Z_TRANSPOSEALV                                    .
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<dynheader> TYPE ANY,
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wa_lvc_cat-ref_table = 'LVC_S_DETA'.
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wa_fieldcat-fieldname = 'COLUMNTEXT'.
wa_fieldcat-ref_tabname = 'LVC_S_DETA'.
wa_fieldcat-key = 'X'..
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lt_layout-no_colhead = 'X'..
lt_layout-colwidth_optimize ='X'.
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Hi,
I'm a relative newbie to APEX and would appreciate some help with the following:
I have an interactive report that will usually contain around 8000 rows.
I need to report the total number of distinct values in one of the columns - but I need to get around the limitation of APEX where it only counts the number of rows displayed on the screen.
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or, if not,
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or
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I do hope this makes sense. Thanks in advance for any help....
Helen

Hi all,
Thanks for your responses. They really are much appreciated.
I had hoped to spend some time on this over the weekend - but haven't got round to it. I'll work on it again tomorrow and will certainly look at the thread you mentioned Tony.
Sorry I'm not being very clear about what I want. Why are these things always so hard to explain in words :o)
I'll have another go....
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How to display a empty (non-existing) column and info in LAST row

Hello!
I´m trying to create the code that diplays all authors (author.name), empty COLUMN, NR_OF_BOOK_PER_AUTHOR.
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I can list all authors and NR_OF_BOOKS_PER_AUTHOR using this code:
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FROM AUTHOR A, BOOK B
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I can count the numbers of authors (should be displayed in last row column2) using:
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FROM author
and I can list the total amount of books (should be displayed in last row column3) using:
SELECT COUNT(title)
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Any suggestions?
Best regards,
Daniel

I want the LAST ROW to display: (column1) the word 'Sum:', (column2) nr of authors, (column3) total sum of all booksHave a look at GROUP BY with CUBE or ROLLUP.
Cheers, APC

How to display number of rows as columns in a select statement? This is on

How to display number of rows as columns in a select statement? This is on 10g R2.
Thanks,
R

For the current (ie. row 1 of 100)
row_number over (order by -pick_a_column_set) as rnfor the total number of columns returned in your query
count(*) over() as total_count

How to display the result of excutions(insert/update/delete rows)

Hello.
Does anyone know how to display the result of scenario executions just like a scenario executions tab of package (insert/update/delete rows) in other screen (in the intergated operating platform for operators using http)
In additional, I also like to show the hierarchy of scenario in the same view.
So, I need the query using the information of the ODI repository.
If it is possible, I also like to have the decription of the tables in the ODI repository.
Can anyone tell me how can I get the information of the counts of excution?
Thanks in advance.

Hi,
You can get that information from the API getPrevStepLog. Does it work for you?
Download the last API reference manual from:
http://www.oracle.com/technology/products/oracle-data-integrator/10.1.3/htdocs/1013_support.html#docs

How to display rows in PSA having count(wbs) 1

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