How to encode a string to base64 in java ?

Hi, I want to send my user name to my SMTP server encoded in base64 .
How do I do this ??
Ramesh

Ok I wait for you.
I guess the following covert a string to base 8
String userName ="Ramesh"
byte[] strBytes = userName.getBytes("UTF-8");
I do not know about base64.
I need this urgently because I am sending my user name and password to my SMTP server and they should be encoded in base64.
Please help.
Ramesh

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String - enc.Base64 - XML - dec.Base64 - String

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You are assuming that
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And you are
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corresponding code:
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If you want to debug something, don't try to debug two
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Do any one kown how to encoder pcm to alaw if you use jmf?

I'm have the problem about it how to encoder pcm to alaw?
I find some code about it, but not work in jmf.
A friend in forum tell me write it by myself , because jmf not support for alaw.
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code like this:
capture.java
* support : locator, datasource
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        VideoCaptureList = CaptureDeviceManager.getDeviceList(videoFormat);
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        AudioCaptureList = CaptureDeviceManager.getDeviceList(audioFormat);
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            source[0] = Manager.createDataSource(getAudioLocator());
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                DataSource MixDataSource = null;
                source[1] = Manager.createDataSource(getVideoLocator());
                MixDataSource = Manager.createMergingDataSource(source);
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            return null;
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        DataSource OutDataSource = null;
        DataSource InputSource = null;
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System.exit(-1);
if (!sh.realize(10000)) {
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System.exit(-1);
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test.java (get outputDatasource form capture.java)
package siphone.test;
import java.io.IOException;
import java.net.InetAddress;
import javax.media.Format;
import javax.media.Manager;
import javax.media.Player;
import javax.media.PlugInManager;
import javax.media.control.BufferControl;
import javax.media.format.UnsupportedFormatException;
import javax.media.protocol.DataSource;
import javax.media.protocol.PushBufferDataSource;
import javax.media.protocol.PushBufferStream;
import javax.media.rtp.InvalidSessionAddressException;
import javax.media.rtp.Participant;
import javax.media.rtp.RTPControl;
import javax.media.rtp.RTPManager;
import javax.media.rtp.ReceiveStream;
import javax.media.rtp.ReceiveStreamListener;
import javax.media.rtp.SendStream;
import javax.media.rtp.SendStreamListener;
import javax.media.rtp.SessionAddress;
import javax.media.rtp.SessionListener;
import javax.media.rtp.event.ByeEvent;
import javax.media.rtp.event.NewParticipantEvent;
import javax.media.rtp.event.NewReceiveStreamEvent;
import javax.media.rtp.event.NewSendStreamEvent;
import javax.media.rtp.event.ReceiveStreamEvent;
import javax.media.rtp.event.RemotePayloadChangeEvent;
import javax.media.rtp.event.SendStreamEvent;
import javax.media.rtp.event.SessionEvent;
import javax.media.rtp.rtcp.SourceDescription;
import siphone.decode.AlawRtpDecoder;
import siphone.device.Capture;
import siphone.gui.MainFrame;
* @author kaiser
public class Dial implements SessionListener, ReceiveStreamListener, SendStreamListener {
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                RTPControl rcl = (RTPControl) rData.getControl("javax.media.rtp.RTPControl");
                if (rcl != null) {
                    System.out.print(" - receive RTPControl info | the AudioFormat: " + rcl.getFormat());
                } else {
                    System.out.print(" - receive RTPControl info");
                if (rPart == null) {
                    System.out.print(" UNKNOWN");
                } else {
                    System.out.print("data form " + rPart.getCNAME());
                play = Manager.createRealizedPlayer(rData);
                if (play != null) {
                    play.start();
            } catch (Exception ex) {
                System.out.print("NewReceiveStreamEvent Exception " + ex.getMessage());
                return;
        } else if (rex instanceof ByeEvent) {
            System.out.print(" - receive bye message: " + rPart.getCNAME() + "   exit");
            stop();
            return;
}Anyone can tell me how to do?
Thank you very much!

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