How to extract data using xml datatype

Question

Hi,
I tried the following example using xml data type , but not getting the required output.
could you please correct the query so as to get the required one
CREATE TABLE TEST.EMP_DETAIL
  EMPNO       NUMBER,
  ENAME       VARCHAR2(32 BYTE),
  EMPDETAILS  SYS.XMLTYPE
Insert into EMP_DETAIL
   (EMPNO, ENAME, EMPDETAILS)
Values
   (7, 'Martin', XMLTYPE('<Dept>
  <Emp Empid="1">
    <EmpName>Kevin</EmpName>
    <Empno>50</Empno>
    <DOJ>20092008</DOJ>
    <Grade>E3</Grade>
    <Sal>3000</Sal>
  </Emp>
  <Emp Empid="2">
    <EmpName>Coster</EmpName>
    <Empno>60</Empno>
    <DOJ>01092008</DOJ>
    <Grade>E1</Grade>
    <Sal>1000</Sal>
  </Emp>
  <Emp Empid="3">
    <EmpName>Samuel</EmpName>
    <Empno>70</Empno>
    <DOJ>10052008</DOJ>
    <Grade>E2</Grade>
    <Sal>2530</Sal>
  </Emp>
  <Emp Empid="4">
    <EmpName>Dev</EmpName>
    <Empno>80</Empno>
    <DOJ>10032007</DOJ>
    <Grade>E2</Grade>
    <Sal>1200</Sal>
  </Emp>
</Dept>
'));I need to get the record for Empid="2"
So tried the following query with no expected o/p
SELECT a.empno,a.ename,a.empdetails.extract('//Dept/Emp/EmpName/text()').getStringVal() AS "EmpNAME",
     a.empdetails.extract('//Dept/Emp/Empno/text()').getStringVal() AS "EMPNumber",
      a.empdetails.extract('//Dept/Emp/DOJ/text()').getStringVal() AS "DOJ",
      a.empdetails.extract('//Dept/Emp/Grade/text()').getStringVal() AS "Grade",
      a.empdetails.extract('//Dept/Emp/Sal/text()').getStringVal() AS "Salary",
      a.empdetails.extract('//Dept/Emp[@Empid="2"]').getStringVal() AS "ID",
      a.empdetails.extract('//Dept/Emp[EmpName="Coster"]').getStringVal() AS "CHK"
     FROM emp_detail a
     where empno=7 
           AND a.empdetails.existsNode('//Dept/Emp[@Empid="2"]') =1thanks..

Answer 1

I am not very good at this... But Shouldn't your XML be more like this
SQL> Insert into EMP_DETAIL
  2     (EMPNO, ENAME, EMPDETAILS)
  3   Values
  4     (7, 'Martin', XMLTYPE('<Dept>
  5    <Emp>
  6      <Empid>1</Empid>
  7      <EmpName>Kevin</EmpName>
  8      <Empno>50</Empno>
  9      <DOJ>20092008</DOJ>
10      <Grade>E3</Grade>
11      <Sal>3000</Sal>
12    </Emp>
13    <Emp>
14      <Empid>2</Empid>
15      <EmpName>Coster</EmpName>
16      <Empno>60</Empno>
17      <DOJ>01092008</DOJ>
18      <Grade>E1</Grade>
19      <Sal>1000</Sal>
20    </Emp>
21    <Emp>
22      <Empid>3</Empid>
23      <EmpName>Samuel</EmpName>
24      <Empno>70</Empno>
25      <DOJ>10052008</DOJ>
26      <Grade>E2</Grade>
27      <Sal>2530</Sal>
28    </Emp>
29    <Emp>
30      <Empid>4</Empid>
31      <EmpName>Dev</EmpName>
32      <Empno>80</Empno>
33      <DOJ>10032007</DOJ>
34      <Grade>E2</Grade>
35      <Sal>1200</Sal>
36    </Emp>
37  </Dept>
38  '));
1 row created.so that you can
SQL> SET LINESIZE 250
SQL> COLUMN EMPNAME FORMAT A20
SQL> COLUMN EMPNUMBER FORMAT A2
SQL> COLUMN DOJ FORMAT A10
SQL> COLUMN GRADE FORMAT A10
SQL> COLUMN SALARY FORMAT A10
SQL> SELECT a.empno,a.ename,a.empdetails.extract('//Dept/Emp[Empid="2"]/EmpName/text()').getStringVal() AS "EmpNAME",
  2        a.empdetails.extract('//Dept/Emp[Empid="2"]/Empno/text()').getStringVal() AS "EMPNumber",
  3        a.empdetails.extract('//Dept/Emp[Empid="2"]/DOJ/text()').getStringVal() AS "DOJ",
  4        a.empdetails.extract('//Dept/Emp[Empid="2"]/Grade/text()').getStringVal() AS "Grade",
  5        a.empdetails.extract('//Dept/Emp[Empid="2"]/Sal/text()').getStringVal() AS "Salary"
  6   FROM emp_detail a
  7  /
     EMPNO ENAME                            EmpNAME              EM DOJ        Grade      Salary
         7 Martin                           Coster               60 01092008   E1         1000Edited by: Karthick_Arp on Apr 30, 2009 2:21 AM