How to extract every component in an array?

Question

Hello everyone!
Do you know how to extract every component from an array field?
For example:
The following is the defination of a table:
CREATE TABLE test (
id NUMBER PRIMARY KEY,
name VARCHAR2(32),
shape MDSYS.SDO_GEOMETRY
And then I insert a new record:
INSERT INTO test VALUES(
1,'first',
MDSYS.SDO_GEOMETRY(
2003,
NULL,
NULL,
MDSYS.SDO_ELEM_INFO_ARRAY(1,1003,3),
MDSYS.SDO_ORDINATE_ARRAY(1,1, 5,7)
The Question is I want to read the every component (for example 1,1,5,7) in the sdo_ordinate_array one by one. Who knows how to write the SQL?
I have tried "select a.shape.sdo_ordinates(1) from test a". But it can't work.
Thank you very much!

Answer 1

One solution is to read each ordinate from a cursor ina SQL block. Here is an example:
set serveroutput on
SET serveroutput on SIZE 1000000
set concat on
DEFINE layername = 'LAYER';
DEFINE geomcolname = 'GEOM';
DECLARE
id varchar2(10);
longitude number;
latitude number;
logmile number;
i number;
theLayer varchar2(32);
theGeomCol varchar2(32);
BEGIN
FOR rec IN (SELECT ROWID, id, &geomcolname FROM &layername ) LOOP
id := rec.id;
i := 1;
while i < rec.geom.sdo_ordinates.count loop
longitude:=rec.geom.sdo_ordinates(i);
latitude:=rec.geom.sdo_ordinates(i+1);
logmile:=rec.geom.sdo_ordinates(i+2);
dbms_output.put_line(id || ',' || longitude || ',' || latitude || ',' || logmile);
i := i + 3;
end loop;
END LOOP;
commit;
END;
Maybe that will help.
Dave
David R. Miller
Michael Baker Jr., Inc.
3601 Eisenhower Avenue
Alexandria, VA 22314
[email protected]
www.mbakercorp.com