How to extract information in cells of a mult-column list box?

I have multi column list box. At run time this listbox allow me to select entire row (this is fine), how to extract the data from each cell along the selected row? It seems to me that the Multi column Listbox (MCL) is merely a 1D array (I guess index of this 1D array corresponds to row index of the MCL and value of the element corresponds to column index of MCL.)

To extract cell values of the selected row, you can create a property node for the MCL. From this property node, choose "Item Names". This is a 2D array containing all cell values. Index this array with the MCL terminal. Note that you must choose the scalar data type for the MCL. To choose the scalar data type, right click on the MCL and go to "Selection Mode"->"Data Type"->"Scalar".
See attachment written with LabVIEW 6.
I hope it will help you.
Attachments:
MCL.vi ‏15 KB

Similar Messages

How do I change ALL cells in a Multi-Cloumn List box at one time ?

I would like to change ALL of the Cells in a Multi-Column Listbox at one time. Both, with the Editor and Programmatically. Any Ideas ?

Programmatically:
Use "Active cell" property node, create constant and type "-2" in both elements of the cluster constant.
Note: the first element is for the raw, the second for the column. -1 and -2 have special meanings.
-1: header of column (listbox has no header for the raws)
-2: all cells (of raw or column)
So for example:
-2;0: all cells of column 0 (with header)
-2; -2: all cells (with header)
-1;0: header of column 0
-1;-2: header of all columns

Is it possible to havedrop down lists in cells of a Multi Column List box(not Table)?

I was using a muticolumn listbox(not table,for table i have example code,and problem is that i was not getting active cell position for Multi column listbox) with 5 columns.In third column,i want to generate a ring control,generate in the sense,whenever user clicks on any cell of third column of multicolumn listbox(not table),the ring control should pop up.The thing is that i need to use only one ring control and whenever user clicks on any cell of a third column,this ring control should pop up.How can i achieve this,anyone please help me,
Regards,
Naresh.N

Hi, Naresh,
For starting point you can read this: Table with Drop Down Items
Andrey.

Add a Drop down menu / Combo Box into a specified cell of a multi column lsit box

Hello,
i have a question how to manipulate a cell of a multi column list box in that way that i can add a drop down menu or a combo box in this cell?
Is this possible in LabView?
Thank you!

Wow, I took a look at the alternate code posted here at that really takes you through gyration (also a similiar comment I see on Lava) to perform what I've done with a few functions....
See the Pics and attached VI for how its done. KISS, I added an event stucture and changed my first enum case to " " (i.e. a blank) to make it look like the other posted code....
Attachments:
DropDownMenuInABox.vi ‏18 KB
DropDownMenuInABox_FP.PNG ‏18 KB
DropDownMenuInABox_BD.PNG ‏36 KB

How to get the index of Mult column list box

Hello all,
I need small help. Please help me.
Is there is any property to change the "Multi column list box" row index position dynamically?
I want to change the index position at runtime like below.
Munna
Solved!
Go to Solution.

It's called Top Left Visible Cell. There aren't that many properties there.
Try to take over the world!

How to insert data to the specified row column of the multi column list box

Hi All
How do i insert data into the specified column of the multi cplumn list box?
I have a table that containsall station nos and name.Then another table contains the data the various stations having at for 24 hrs.That is 12 am to 11 pm.
And i want to display each stations details as follows using a multi column list box/table
My stationinfo table
stnno   stnname......................
s1           stn1
s2            stn2
s3             stn3
The other table
stnno      sysdatetime       data
s1             12am                   1
s2              12am                   4
s1               1 am                 2
So the station s1,s2.... will have data for 24 hrs.
And i want to display it as follows using a multicolumn listbox
stnname        12am   1 am ......................................11pm
s1                   ...................
s2                 ........................
What i have in my mind is to get all station nos
and in a for loop get the station's data from 12 am to 11 pm
or
select every statios data for each hor.But in this case i have to query the database 24 times.So i dont think its a good way.
Or any other better query available?
Can anybody suggest me a good idea?
One more thing...how to insert data into the specified field row or column of a multi column list box?
Thanks in advance

hi
i want to know,,can u say ur need clearly...and i attached two image u see that one
Indrajit
| [email protected] | [email protected] .
Attachments:
station.JPG ‏35 KB
station2.JPG ‏79 KB

How to prevent multi-column list box showing an extra column

I am using a multi-column list box to display data and to allow the user to enter new values. More columns are used than are actually displayed within the bounds of the listbox control. Using an event structure the user is able to scroll left and right along the columns of the list box to select the appropriate field. I am using the 'Edit Position' property to highlight the particular field that the user is selecting. This technique works well and the listbox scrolls left and right to display the selected fields correctly.
If the listbox has, say, 10 columns with only 5 being visible within the displayed width, then I clamp the Edit Position to a maximum column value of 9 to prevent the list box from continuing to scroll right into unused columns. This works fine, except that when the user scrolls to the 10th column, the listbox control always shows a blank 11th column. The 11th column cannot be selected. It would appear that this is default behaviour for the listbox control in that an additional column is always displayed relative to the Edit Position. In my particular application it is untidy to have this blank column appearing. I have tried a workaround by programmatically writing to the 'TopLeft' property of the listbox. This partially works by ensuring that the blank 11th column is never displayed, however, despite the Edit Position being correct to select the 10th column, the field in the 10th column is no longer highlighted and the user cannot enter a new value.
Does anyone know of a method for preventing the blank additional column from appearing?

Ok - I have attached an example which demonstrates the issue. This is produced with LV 2012. Open the project and then the 'Multi column listbox.vi'. Run the vi and use the right/left arrows to move between cells in the listbox. Observe that unused (unwanted) columns are always displayed to the right.
Thanks for any help..
Attachments:
Test Multi column listbox.zip ‏62 KB

How do I select a cell in a multicolumn list box and use scroll horizontal on th

From an event structure, how do I select a cell in a multicolumn list box and use scroll horizontal on the front panel at the same time. I can select a cell from the multicolumn in an event structure, but I cannot move the scroll bar on the front panel when the program is running.
Solved!
Go to Solution.

I'm assuming you're referring to the scrollbar in the multicolumn listbox. What is your code doing when you select a cell? Can you please post your code so we can see the behavior you're describing? It's possible that you're blocking the event structure, as in performing some long operation in the event that's handling the cell selection. In this case the event structure has to wait until the event completes before being able to respond to the next event. You can configure the event to not lock the front panel while waiting for the event to complete.

How Do I Filter a Report Using a Multi Select List Box and Specifying Date Between Begin Date and End Date

Hope someone can help. I have tried to find the best way to do this and can't seem to make sense of anything. I'm using an Access 2013 Database and I have a report that is based on a query. I've created a Report Criteria Form. I
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get it to work with a List Box so they can select multiple items. Any help is greatly appreciated while I still have hair left.

The query should return all records.
Let's say you have the following controls on your report criteria form:
txtStart: text box, formatted as a date.
txtEnd: text box, formatted as a date.
lbxMulti: multi-select list box.
cmdOpenReport: command button used to open the report.
The text boxes are used to filter the date/time field DateField, and the list box to filter the number field SomeField.
The report to be opened is rptReport.
The On Click event procedure for the command button could look like this:
Private Sub cmdOpenReport_Click()
Dim strWhere As String
Dim strIn As String
Dim varItm As Variant
On Error GoTo ErrHandler
If Not IsNull(Me.txtStart) Then
strWhere = strWhere & " AND [DateField]>=#" & Format(Me.txtStart, "yyyy-mm-dd") & "#"
End If
If Not IsNull(Me.txtEnd) Then
strWhere = strWhere & " AND [DateField]<=#" & Format(Me.txtEnd, "yyyy-mm-dd") & "#"
End If
For Each varItm In Me.lbxMulti.ItemsSelected
strIn = strIn & "," & Me.lbxMulti.ItemData(varItm)
Next varItm
If strIn <> "" Then
' Remove initial comma
strIn = Mid(strIn, 2)
strWhere = strWhere & " AND [SomeField] In (" & strWhere & ")"
End If
If strWhere <> "" Then
' Remove initial " AND "
strWhere = Mid(strWhere, 6)
End If
DoCmd.OpenReport ReportName:="rptMyReport", View:=acViewPreview, WhereCondition:=strWhere
Exit Sub
ErrHandler:
If Err = 2501 Then
' Report cancelled - ignore
Else
MsgBox Err.Description, vbExclamation
End If
End Sub
If SomeField is a text field instead of a number field, change the line
strIn = strIn & "," & Me.lbxMulti.ItemData(varItm)
to
strIn = strIn & "," & Chr(34) & Me.lbxMulti.ItemData(varItm) & Chr(34)
Regards, Hans Vogelaar (http://www.eileenslounge.com)

How to un-check everything in a Multi-selection list box in SP2013?

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Thank you

yes, that's what I've done but still not working. I even downloaded the sp,
InfoPath 2013 (KB2837648) 32-Bit Edition
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RoopeshV wrote:
Hi,
The below code shows how to read from txt file and display in the perticular fields.
Why have you used waveform?
Regards,
Roopesh
There are so many things wrong with this VI, I'm not even sure where to start.
Hard-coding paths that point to your user folder on the block diagram. What if somebody else tries to run it? They'll get an error. What if somebody tries to run this on Windows 7? They'll get an error. What if somebody tries to run this on a Mac or Linux? They'll get an error.
Not using Read From Spreadsheet File.
Use of local variables to populate an array.
Cannot insert values into an empty array.
What if there's a line missing from the text file? Now your data will not line up. Your case structure does handle this.
Also, how does this answer the poster's question?

How to make a custom cell to put in title list?

Hi,
I want to retrieve data from xml and make each item look like
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Is tile list the recommend control for the job?
Thanks,
Nuno

"sinosoidal" <[email protected]> wrote in
message
news:gcfhrp$8pp$[email protected]..
> Hi,
>
> I want to retrieve data from xml and make each item look
like a cell in
> the tile list. How can i do that in flex?
>
> Is tile list the recommend control for the job?
There are some good itemrenderer resources listed with Q2
http://www.magnoliamultimedia.com/flex_examples/Amys_Flex_FAQ.pdf

How to enable a button on click of an adjoining list box

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But it is not working.
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gary1234 wrote:
Dear Cotton,
I tried searching for a Java Script forum. Could not find it.Dear Gary,
I question either your competence or the veracity of this claim. A Google search for JavaScript forum returns 19,000,000+ results.
Please reply if you can help.
Thanks for enlightening me that Java script is different than Java.This is the third time now you have been so enlightened.
I am not sure how is it harming you if I post the Java script question here.Please don't be a wank. It is inappropiate for anyone, including you, to ask off topic questions on this, or any other forum. This forum is NOT for JavaScript questions and that is all there is to it.
So now go to Google. Type JavaScript Forum into the search box and find yourself a JavaScript forum and ask your JavaScript question there.
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How to extract person details (phone number) into a Sharepoint list

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Hemendra:Yesterday is just a memory,Tomorrow we may never see<br/> Please remember to mark the replies as answers if they help and unmark them if they provide no help

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Hello All
Here´s what we´re trying to do:
We have a folder with csv files named like this:
Sales_2013-02-05.csv
Sales_2013-02-04.csv
Sales_2013-02-03.csv
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I´ve tried entering = Source[Name] in a custom column, but it adds a "LIST" link, and on a click on expand, it adds ALL file names from the folder in each row, instead of just the needed one.
If we could get the proper file name in each row (from where they got extracted), we could split the column and get the date from there. But I don´t know how put the filename there properly.
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This isn't entirely straightforward, but it's definitely possible. What you need to do is to apply all of your transforms to each individual file instead of the combined files. I do that as follows:
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4) Expand the tables created in step 3.
As an example, I have some files with names that match the ones you suggested. After steps 1 + 2, my query looks like the following:
let
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    #"d:\testdata\files\_Sales_2013-02-01 csv" = Source{[#"Folder Path"="d:\testdata\files\",Name="Sales_2013-02-01.csv"]}[Content],
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in
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For step 3, I need to take steps 3-5 of my query and convert them into a function. As a check, I can apply that function to the same file that I chose in step 2. The result looks like this:
let
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        let
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            #"First Row as Header" = Table.PromoteHeaders(#"Imported CSV"),
            #"Changed Type" = Table.TransformColumnTypes(#"First Row as Header",{{"One", Int64.Type}, {"Two", type text}, {"Three", type text}})
        in
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in
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Now I apply the same function to all of the rows, transforming the existing "Content" column into a new value:
let
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        let
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            #"First Row as Header" = Table.PromoteHeaders(#"Imported CSV"),
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in
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let
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in
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From here, you should be able to get to what you want.

How to extract information in cells of a mult-column list box?

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