How to find a regular expression in a statement

I have to find regex in a statement and return boolean true if it matches .
regexpression : AR%SUPERUSER
How to write in code?
I have tried this
String EXAMPLE_TEST = "This is my AR SUPERUSER string which I'm going to use for pattern matching.";
System.out.println(EXAMPLE_TEST.matches("AR SUPERUSER"));
It returned false

That works fine, but if you want to find the part of the String you have some options:
String EXAMPLE_TEST = "This is my small example string which I'm going to use for pattern
System.out.println(EXAMPLE_TEST.matches(".+small example.+"));
System.out.println(EXAMPLE_TEST.indexOf("small example") >= 0);
System.out.println(EXAMPLE_TEST.contains("small example"));{code}

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I want regular expression for the [] Square brackets.
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private static final Pattern DESC_PATTERN = Pattern.compile("({1}[a-zA-Z])" +"([a-zA-Z0-9\\s.,_():}{/&#-]+)$");Thanks
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Since square brackets are meta characters in regex they need to be escaped when they need to be used as regular characters so prefix them with \\ (the escape character).

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Thanks much for your response. I found David's article to be a little thin with respect to examples using quantifiers in coordination with the wildcard metacharacters; however, I was able to cobble together a working expression through trial and error using the information he presented. For posterity, here’s the solution:
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I believe this literally translates to:
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I am using SAP UI5 .
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Can't you use this expression?
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This won't work with duplicate words, will it? well, maybe, since you are putting both strings in sets. But then, how would this handle capitalization? This is my ugly solution:
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First, Acrobat must "mount" the PDX.
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Fine fine. :P
I was a little bored, so here's some code that uses Strings and a StringBuffer (though you could use a String in place of the StringBuffer). Is this perhaps better? :)
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Or if you have to do it in java, check out the interfaces java.io.FileFilter and java.io.FileNameFilter
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user11181920 wrote:
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>
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>
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>
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How to use regular expression to delete a character?

Hello,
I have a query,
select partition_name from dba_tab_partitions where table_owner='xxx'and num_rows <>0 and table_name = 'xxx';
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How can I use regular expression in above SQL query to get result without letter 'P', like..
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thank you

I find answer...
select regexp_replace(partition_name,'P','')
thanks anyway

How to find a regular expression in a statement

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