How to find ?? in a view text (definition) in all schemas

Question

Hi
DB Version Oracle Database 11g Enterprise Edition Release 11.2.0.1.0 - 64bit Production
OS RHES 5U2
I would appreciate if someone can tell me how to get a list of all the views in the database that contains ?? in the text/definition of the view.
I tried with both DBA_VIEWS and ALL_VIEWS using following query but it returned error.
SELECT OWNER||'.'||VIEW_NAME
FROM ALL_VIEWS
WHERE TEXT LIKE '%??%'
AND owner not in ('SYS','SYSTEM','SYSMAN','DBSNMP','OLAPSYS','MDSYS','CTXSYS')
ORDER BY OWNER;
WHERE TEXT LIKE '%??%'
ERROR at line 3:
ORA-00932: inconsistent datatypes: expected NUMBER got LONG
SELECT OWNER||'.'||VIEW_NAME
FROM DBA_VIEWS
WHERE TEXT LIKE '%??%'
AND owner not in ('SYS','SYSTEM','SYSMAN','DBSNMP','OLAPSYS','MDSYS','CTXSYS')
ORDER BY OWNER;
WHERE TEXT LIKE '%??%'
ERROR at line 3:
ORA-00932: inconsistent datatypes: expected NUMBER got LONG
Thanks

Answer 1

WHERE TEXT LIKE '%??%'TEXT here is a LONG datatype, you cannot use it in an expression.
You could do that :
SQL> select count(*) from user_views where text like '%OPRD%';
select count(*) from user_views where text like '%OPRD%'
ERROR at line 1:
ORA-00932: inconsistent datatypes: expected NUMBER got LONG
SQL> create table myviews (view_name varchar2(30), text clob);
Table created.
SQL> begin
  2  for i in (select view_name,text from user_views) loop
  3  insert into myviews values (i.view_name,i.text);
  4  end loop;
  5  end;
  6  /
PL/SQL procedure successfully completed.
SQL> select count(*) from myviews where text like '%OPRD%';
  COUNT(*)
       136
SQL>Nicolas.