How to find the date when the cube was created

Hi gurus
I just want to find out the date when the cube was created,
Regards
Kumar

Kumar,
Go to table RSDCUBE, you can see date there.
Hope it helps,
Sam

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code
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[/code]
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2   c integer;
3   desc_t DBMS_SQL.DESC_TAB;
4   col_cnt integer;
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6   values1 gvarray := gvarray();
7   a integer;
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26      end loop;
27     else
28       exit;
29     end if;
30   end loop;
31   dbms_sql.close_cursor(c);
32 end;
33 /
Row number 1, column HIREDATE, value 17.12.80
Row number 2, column ENAME, value SMITH
Row number 1, column HIREDATE, value 20.02.81
Row number 2, column ENAME, value ALLEN
Row number 1, column HIREDATE, value 22.02.81
Row number 2, column ENAME, value WARD
Row number 1, column HIREDATE, value 02.04.81
Row number 2, column ENAME, value JONES
Row number 1, column HIREDATE, value 28.09.81
Row number 2, column ENAME, value MARTIN
Row number 1, column HIREDATE, value 01.05.81
Row number 2, column ENAME, value BLAKE
Row number 1, column HIREDATE, value 09.06.81
Row number 2, column ENAME, value CLARK
Row number 1, column HIREDATE, value 19.04.87
Row number 2, column ENAME, value SCOTT
Row number 1, column HIREDATE, value 17.11.81
Row number 2, column ENAME, value KING
Row number 1, column HIREDATE, value 08.09.81
Row number 2, column ENAME, value TURNER
Row number 1, column HIREDATE, value 23.05.87
Row number 2, column ENAME, value ADAMS
Row number 1, column HIREDATE, value 03.12.81
Row number 2, column ENAME, value JAMES
Row number 1, column HIREDATE, value 03.12.81
Row number 2, column ENAME, value FORD
Row number 1, column HIREDATE, value 23.01.82
Row number 2, column ENAME, value MILLER
PL/SQL procedure successfully completed.Rgds.

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SELECT TAccTrn.ASysCde
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Is there any more idea without using the subquery?

Hi ,
What about using an in-line view and the row_number () analytic function...????
Here is an example....
SQL> select * from emp;
EMPNO ENAME      JOB         MGR HIREDATE          SAL      COMM DEPTNO
7369 SMITH      CLERK      7902 18/12/1980     800,00               20
7499 ALLEN      SALESMAN   7698 20/02/1981    1600,00    300,00     30
7521 WARD       SALESMAN   7698 22/02/1981    1250,00    500,00     30
7566 JONES      MANAGER    7839 02/04/1981    2975,00               20
7654 MARTIN     SALESMAN   7698 28/09/1981    1250,00   1400,00     30
7698 BLAKE      MANAGER    7839 01/05/1981    2850,00               30
7782 CLARK      MANAGER    7839 09/06/1981    2450,00               10
7788 SCOTT      ANALYST    7566 18/04/1987    3000,00               20
7839 KING       PRESIDENT       17/11/1981    5000,00               10
7844 TURNER     SALESMAN   7698 08/09/1981    1500,00      0,00     30
7876 ADAMS      CLERK      7788 21/05/1987    1100,00               20
7900 JAMES      CLERK      7698 03/12/1981     950,00               30
7902 FORD       ANALYST    7566 03/12/1981    3000,00               20
7934 MILLER     CLERK      7782 23/01/1982    1300,00               10
14 rows selectedUsing a solution like the one you don't want ...(a subquery) i would write....
SQL> select ename from emp
2    where hiredate=(select min(hiredate) from emp)
3 /
ENAME
SMITHWhereas , using an in-line view....
SQL> select ename from
2   (
3    select ename,row_number() over(order by hiredate asc) row_num from emp
4    )
5 where row_num=1
6 /
ENAME
SMITHIs it acceptable...????
Regards,
Simon

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Can I obtain the date of the exe and display it on the fropnt panel?

Hello,
Is there a way that a Labview program can display the date of the exe and display it on the front panel? I am aware of the version info on the application builder, but I did not see a way to get the date when the exe was created.
Regards,
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Hi
You could use File/Directory Info function in your code like this
cheers
David
Message Edited by David Crawford on 02-24-2010 11:11 PM
Message Edited by David Crawford on 02-24-2010 11:12 PM
Attachments:
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How to find the date when the cube was created

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