How to find the partition column in a partitioned table
Hi,
I have a partition table and I need to find out what column was used to partition the table. Range partition.
Thanks,
Maria Sanchez
select *
from dba_part_key_columns
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4 cnt number;
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8 /
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7 /
REFERENCED_OWNER REFERENCED_NAME
SCOTT EMP
SQL> SY. -
Guys,
Please can you tell me how to find the partition name from the table for say today ("SYSDATE") assuming that the table is partitioned by Date ( monthly )
ie,
I need to find the partition belonging to the current month, on which i am working
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GBased on martina's suggestion (can be of course improved, maxvalue should be handled as well):
SQL> create table p(id number,time_stamp date)
2 partition by range(time_stamp)
3 (
4 partition p1 values less than(date '2007-10-01'),
5 partition p2 values less than(date '2007-11-01'),
6 partition p3 values less than(date '2007-12-01'),
7 partition p4 values less than(date '2008-01-01'),
8 partition p5 values less than(date '2008-02-01'),
9 partition p6 values less than(date '2008-03-01')
10 )
11 /
Table created.
SQL> create or replace function date_from_long(p_tabname varchar2,
2 p_partname varchar2)
3 return date is
4 l_long long;
5 l_date date;
6 begin
7 select high_value
8 into l_long
9 from user_tab_partitions
10 where table_name = p_tabname
11 and partition_name = p_partname;
12 if substr(l_long, 1, 7) = 'TO_DATE' then
13 execute immediate 'select ' || l_long || ' from dual'
14 into l_date;
15 return l_date;
16 else
17 return null;
18 end if;
19 end;
20 /
Function created.
SQL> select table_name,partition_name,
2 date_from_long(table_name,partition_name) high_value
3 from user_tab_partitions
4 where table_name='P'
5 order by 3
6 /
TABLE_NAME PARTITION_NAME HIGH_VALUE
P P1 01.10.2007 00:00:00
P P2 01.11.2007 00:00:00
P P3 01.12.2007 00:00:00
P P4 01.01.2008 00:00:00
P P5 01.02.2008 00:00:00
P P6 01.03.2008 00:00:00
6 rows selected.
SQL> select
2 max(partition_name)
3 keep
4 (dense_rank first order by date_from_long(table_name,partition_name)) part_name
5 from user_tab_partitions
6 where table_name='P' and date_from_long(table_name,partition_name)>=sysdate
7 /
PART_NAME
P2Best regards
Maxim
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