How to get Byte[] from an image object?

Question

This are the codes that i have tried, it did an resized.jpg but the file doesnt consist of the image. My program will stream the .jpg file using fileconnection then i resize the image and created the new image using image.createRGBImage(). Lastly, i need to save the resized image as a jpeg file but i failed to do so..
byte[] jpegData = ImageByteConverter.getByteArray(image);
OutputStream out = fconn.openOutputStream();
out.write(jpegData,0,jpegData.length);
* This method converts a int-array, containing all RGB values for the image, to
* a byte-array containing all RGB values.
public static byte[] getByteArray(Image image){
// Allocate new memory for the int-array and fill the array in the getRGB method.
int[]raw = new int[image.getWidth() * image.getHeight()];
image.getRGB(raw, 0, image.getWidth(), 0, 0, image.getWidth(), image.getHeight());
byte[]rawByte = new byte[image.getWidth() * image.getHeight() * 4];// ARGB
int a, r, g, b;
int n = 0;
// loop through the int-array and get the 4 bytes of each value to the byte-array.
// since java isn't supporting unsigned bytes we need to store the ARGB values from -128 to 127
// where -128 = 128, -127 = 129 and -1 = 255
for(int i=0; i<raw.length; i++){
// Right-shift the values to fit in a byte.
int ARGB = raw;
a = (ARGB & 0xFF000000) >> 24;
r = (ARGB & 0xFF0000) >> 16;
g = (ARGB & 0xFF00) >> 8;
b = (ARGB & 0xFF);
rawByte[n] = (byte)b;
rawByte[n+1] = (byte)g;
rawByte[n+2] = (byte)r;
rawByte[n+3] = (byte)a;
n+=4;
raw=null;
return rawByte;
Thanks in advance.

Answer 1

you can do follwoing but not sure whether thats what you want.
Also not sure whether its the best way.
ByteArrayOutputStream baos = new ByteArrayOutputStream();
ImageIO.write(image, "PNG",baos);
InputStream in = new ByteArrayInputStream(baos.toByteArray());