How to get *.class file path....

how could find the executable file path at execution time..
if there is one *.class file, then i will paste it to another location . next i will execute that .class file. how to find that path from execution program ....

Try the following
URL path = getClass().getProtectionDomain().getCodeSource().getLocation();

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How to get full file path while uploading a file in flex Applications

How to get full file path while uploading a file in flex applications.
FileReference Object is giving file name and other details but not the actual path.
Is there any workaround to to get the file path?.
Thanks

Why not ask in the Flex forum; it is more likely that someone over there knows.

How to get the file path in adf application

hii all,
i have a txt file that i am using in my adf application,
i am passing this txt file through a File Reader, for which i have to mention the file path.
The file is in web-content and when i am hard coding the complete file path i.e C:/JDeveloper/myApp/ViewController/public_html/log.txt
the application is working fine when run on integrated weblogic server.
My requirement is to access this file without giving the static file path, as in case i have to use this application on any other machine..
for that how to mention the file path-
i tried using FacesContext to get the context path :-
FacesContext.getCurrentInstance().getExternalContext().getRequestContextPath();
which gives me
\myApp-ViewController-context-root
after appending public_html\log.txt
I am using the following path to access the file :-
\myApp-ViewController-context-root\public_html\log.txt
again i am getting the java.io.FileNotFoundException
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Hi,
If you put your file under public_html folder, you can use this code to access the file:
For example file is : log.txt
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How to get the file path from HTML input form in Firefox3

In IE7 (and probably all famous browsers, including old Firefox 2), if we submit a file like 'C:\folder1\folder2\folder3\filename' it works properly and gives the full path to the file and the filename.
In Firefox 3, it returns only 'filename', because of their new 'security feature' to truncate the path, as explained in Firefox bug tracking system (https://bugzilla.mozilla.org/show_bug.cgi?id=143220)
I have no clue how to overcome this 'new feature'.
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Doubleposted and ignored any previous answer: [http://forums.sun.com/thread.jspa?threadID=5342405]. Don't do that. It's rude.
Regarding to your "problem": why do you need the file path?

How to get the file path from HTML input form in Firefox 3...

In IE7 (and probably all famous browsers, including old Firefox 2), if we submit a file like 'C:\folder1\folder2\folder3\filename' it works properly and gives the full path to the file and the filename.
In Firefox 3, it returns only 'filename', because of their new 'security feature' to truncate the path, as explained in Firefox bug tracking system (https://bugzilla.mozilla.org/show_bug.cgi?id=143220)
I have no clue how to overcome this 'new feature' because it causes all upload forms in my webapp to stop working on Firefox 3.
Can anyone help to find a single solution to get the file path both on Firefox 3 and IE7?
Thanks in advance....

As you're posting this in the JSF forum and looking at your [previous topic|http://forums.sun.com/thread.jspa?threadID=5342365], I assume that you're using Tomahawk's t:inputFileUpload. In this case, just use UploadedFile#getInputStream(). You may find this article useful: [http://balusc.blogspot.com/2008/02/uploading-files-with-jsf.html].
By the way, are you lazy or just dumb? You wasted one week to this! I've posted the aforementioned article one week ago. How did you stuck?

How to get physical file path from logical file path

Hi
there is a immediate requirement ,
I have logical file path but I need to get physical file path from it.
So is there any FM which providesthis functionality.
Points will be rewarded.
Thanks

Can you please share the piece of code ?
Which File APIs are you using ?
For java file, you can get complete path by simple method call : getAbsolutePath() on file object.
Regards,
Ashwani Kr Sharma

How to get .class files from a JAR at runtime

Hi. I wrote a program that load the classes it find in the "prog/components" directory. It enables me to add new components without messing with the code of the main program. Everything worked fine when wrote a batch file - but I want to create a JAR file. In the Batch file I gave the path to those files for the class loader in a loop, and it was "prog.components/" + filename[i] (I get the file names by using a FileFilter).
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Thanks man, that was really helpful! I wrote some piece of code that inserts the file names I want to an ArrayList. However, I wonder how you would make the program list all the files in the "prog.jar/prog/components/" directory? I think your code would be better tahn mine since you've coped with it before. Could you write the code snippet?

How to get Sequence file path In "SequentialModel.Seq"?

Hello
I need to get the sequence file path in "SequentialModel.seq" before the "GetReportoptions" Callback is called.
I found that step "Determine Report File Path" in "Sequenctialmodel.seq" returns the sequence file path but i.e after executing quite a series of steps.
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looking forward to hear from you
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Kulwant

Hello Kulwant,
try "RunState.InitialSelection.SelectedFile.Path" or "RunState.ProcessModelClient.Path" at the beginning of SequentialModel.seq please.
Regards
MY

How to get absolute File Path using JFileChooser?

Hi,
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How to get .class files (and others) out of JAR in code?

Hi all,
I am packaging up several classes in a jar file. In my code I want to be able to "read" any number of jar files, and in each case pull out all the .class files to create instances of them. I don't want to unzip/unjar the files to the disk system. I basically want to create instances of the classes in the jar files in memory as if they had been loaded off the disk by themselves. Here is the sticky issue. I have a class in each jar that is "instantiated" by my plugin engine. There are other classes in the JAR file that "support" this class that is created. For instance, the class that is instantiated then has references and calls to new SomeClase() in it, and those classes are in the JAR file. So, is there some way to either "pull out" the class(es) of a JAR file without actually unjarring them to the local system and be able to create instances of them? Or, perhaps there is a way to make the classpath of the running app "see into" all the JAR files (and any sub-dirs/packages in that jar file) as if it was part of its class path? Again, these are always loaded via the Class.forName() call and newInstance(), and can not be programitcally added to the initial running application.
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Not sure if this is what you are asking, but...
You have jars that reference each other (sounds pretty tightly coupled to me, maybe they shouldn't be in separate jars, but I digress) and each has a manifest file in META-INF, right?
To reference another jar's contents, simply add it to the Class-Path variable in your manifest. Then you can reference the classes as if they were all unjarred and slapped in the same directories.
More Info:
http://java.sun.com/docs/books/tutorial/jar/basics/manifest.html#special-purpose
Tarabyte :)

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Hi All,
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String filename1;
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rp0428 wrote:
>
BufferedWriter outFile = new BufferedWriter( fileName ) );
>
There is NOTHING named 'fileName' in any of the code you posted so that code can't possibly compile let alone actually run.
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import java.awt.*;
import java.awt.event.*;
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frame.pack();
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simply use file.getPath()
That should do it!Thank you !
It takes care of the problem !!

Sharepoint Workflow : how to get document full path + file name into variable?

Hi,
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Example http://sp1:80/InvoiceQueue/Shared Documents/123.pdf
I am using List Workflow which links to a document library.

Hi SAMSUNG,
According to your description, my understanding is that you want to get the full path of a document in a list workflow.
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Wendy Li
TechNet Community Support

How to get the absolute path of a file from the local disk given the file n

how to get the absolute path of a file from the local disk given the file name

// will look for the file at the current working directory
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File file = new File("README.txt");
if (file != null && file.exists())
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How to get rejected file absolute path location in file rejection handler

HI,
Right now I am working in the below scenario in SOA11G.
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Hi Omar,
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Please refer the below links
Upload File from SAP Application Server using ABAP
Application Server Program - ABAP Development - SCN Wiki
Hope this helps you.
Regards,
Rama

How to get *.class file path....

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