How to get the files' information?
I' d want to get the files' information in the action, such
as the .avi or .flv information about their duration and the
default image,
please help, thanks.
Hi,
You could use Oracle workflow builder to do thar....
Regards,
Luiz
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how to get the files in presentation server while uploading?
give me the function module nameHi,
PARAMETERS: P_FILE LIKE RLGRAP-FILENAME DEFAULT C_PRES. "Prsnt Srvr
AT SELECTION-SCREEN ON VALUE-REQUEST FOR P_FILE.
CALL FUNCTION 'WS_FILENAME_GET'
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Re: That garbage is unreadable.
If you really want help, stop messing with the fonts and post so that others can read and offer suggestions.
Or better yet... try a search, I'm certain you'll find a solution to whatever issue you're experiencing.
I have found that many times it is the things that make you most angry that push you to action. This was the case here. Thank you for causing me to get so angry that I found the answer myself. -
[CS3][JS] How to get the file type of current document
Hi,
How to get the file type of current opening document (e.g., tif, jpeg, png) using JavaScript with Photoshop CS3.
I am using file object the open the files one by one in the folder (the files sometimes don't have the extensions).
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Regards,
KarthikDo you really need to know the file type? What about just checking the bit depth?
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How to get the file size (in bytes) for all files in a directory?
How to get the file size (in bytes) for all files in a directory?
The following code does not work. isFile() does NOT recognize files as files but only as directories. Why?
Furthermore the size is not retrieved correctly.
How do I have to code it otherwise? Is there a way of not converting f-to-string-to-File again but iterate over all file objects instead?
Thank you
Peter
java.io.File f = new java.io.File("D:/todo/");
files = f.list();
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System.out.println("file[" + i + "]=" + files[i] + " size=" + (new File(files[i])).length() ); }pstein wrote:
...The following code does not work. Work?! It does not even compile! Please consider posting code in the form of an SSCCE in future.
Here is an SSCCE.
import java.io.File;
class ListFiles {
public static void main(String[] args) {
java.io.File f = new java.io.File("/media/disk");
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i +
"]=" +
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}Edit 1:
Also, in future, when posting code, code snippets, HTML/XML or input/output, please use the code tags to retain the indentation and formatting. To do that, select the code and click the CODE button seen on the Plain Text tab of the message posting form. It took me longer to clean up that code and turn it into an SSCCE, than it took to +solve the problem.+
Edited by: AndrewThompson64 on Jul 21, 2009 8:47 AM -
How to get the log information when using a class?
Hi All,
I have a simple question, which I don't know how to solve. I am using org.apache.commons.logging.Log and LogFactory to do some logging. A typical situation is exemplified in the following code snippet.
import org.apache.commons.logging.Log;
import org.apache.commons.logging.LogFactory;
class LogClass {
private static final Log LOG = LogFactory.getLog(AClass.class);
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Many thanks.jschell wrote:
jverd wrote:
...configuration in log4j.xml or log4j.properties.And far as I recall you need one of those two also. If there is no config then there is no output.I thought it used some default config if no file is present, but I could be mistaken. Either way, it adds to the possible problems that the OP could be having, any of which are consistent with his rather vague question.
1) He's passing the wrong class to the LogFactory, and hence getting a logger with the wrong name, so he's seeing a different name than he expects in the output that's being produced.
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3) His config file indicates a threshold that's less verbose than the level at which his code is logging, so no output is present when he wants it.
4) His config file is missing (or not where it's expected to be), so no output is being produced at all.
5) His config file is missing (or not where it's expected to be), so a default level or format is being produced, effectively the equivalent of one of the misconfigurations described in #2 and #3.
Since the OP seems to have vanished, we may never know. -
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hii all,
i have a txt file that i am using in my adf application,
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If you put your file under public_html folder, you can use this code to access the file:
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Hi.I use this code to parse a file that is on a server.
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//Open the file for reading:
URL u = new URL(entry);
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doc = builder.parse(inputXML);Try this instead:
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Thanks in advance....Doubleposted and ignored any previous answer: [http://forums.sun.com/thread.jspa?threadID=5342405]. Don't do that. It's rude.
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In IE7 (and probably all famous browsers, including old Firefox 2), if we submit a file like 'C:\folder1\folder2\folder3\filename' it works properly and gives the full path to the file and the filename.
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By the way, are you lazy or just dumb? You wasted one week to this! I've posted the aforementioned article one week ago. How did you stuck? -
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Hi Experts,
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>>i need to get the file name of file in one of the node in xml content of that file.
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How to get the FILE COUNT from File directory
Hello,
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Check this blog on the same -
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