How to I insert a line of best fit on a scatter plot????

I have data already organized in tables, and I created a scatter plot. NOw I need to insert a line of best fit and get the equation. How do I do this??? I already calculated a and b (for y=a+bx) but I have no idea how to insert it on the plot. Every search tells me to "insert a trendline"..... but numbers doesnt have that function. Help please???

Open inspector
Go to chart tab
Series
Click on the "Advanced" to reveal the menu
Trendline
Choose the desired trendline (linear etc)
Hope this helps.
Dimitris

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How do I do a line of best fit graph!!?

Hi guys, I need to do a line of best fit graph comparing two sets of numbers. I have the info on a scatter graph but can not find how to insert a line of best fit. The other graph options dont represent the data correctly. any help would be appreciated, thanks, Nick.

Here's a link to how we did it in the "old days":
http://www.regentsprep.org/Regents/math/data/linefit.htm
http://mathdemos.gcsu.edu/mathdemos/lsq-demonew/indexnew.html
Regards,

Extrapolation and Line of Best Fit

Hello,
I'm working on a project and I need to make a line of best fit for a scatter plot graph as well as make an extrapolation on the graph...any possibility someone could help me with these two questions?
Thank you,
Mike

Mike,
Numbers 08 have functions that you can use to calculate your lines of best fit, then chart the line calculations along with your data.
See INTERCEPT and SLOPE for 1st order lines.
Numbers 09 added quite a few new functions and also automatic Trendline generation.
Jerry

Line of best fit and reverse axis

Hi, How do i do a line of best fit in Numbers? Instead of having a line like do to dot i need it to be smooth, Excel does it but does Numbers?
I also need the bottom axis to start at 10 and go down to 0 and i need the left axis to be on the right! How do i do this?
thanks a lot

Hello
*go to "Provide Numbers Feedback" in the "Numbers" menu*, describe what you wish.
Then, cross your fingers, and wait at least for iWork'09
Yvan KOENIG (from FRANCE lundi 4 février 2008 13:36:58)

Line of best fit

Is there a way I can get a linear line of best fit for an XY plot.
Thanks,
Matt.
Solved!
Go to Solution.

Have you looked at the fitting palette under "Mathematics"? You need the Full Development System for these tools.
You can take the Best Linear Fit array from the linear fit.vi and wire this into your graph as a secondary plot.
Message Edited by vt92 on 07-20-2009 10:11 AM
"There is a God shaped vacuum in the heart of every man which cannot be filled by any created thing, but only by God, the Creator, made known through Jesus." - Blaise Pascal

How to Make a Line of Best Fit/Best Fit Line/Trendline in iWork Numbers '09

I'm not sure if this is well-known or has been answered elsewhere already, but multiple Google searches have not shown this solution on how to create a line of best fit in Numbers '09 (there is another method that involves drawing a line yourself, but this is much easier and more accurate).
I stumbled across this trying the above self-draw technique and got so excited I wanted to post the technique. So here is what you do:
1) Type out your X and Y data
2) Select the data and select Charts, then select the Scatter Plot
3) Open up Inspector and select the Chart tab
4) Select the "Series" tab below the picture of the Scatter Plot and the "Chart Colors..." button
5) At the bottom of the Inspector window, open the "Advanced" arrow
6) Select the "Trendline" tab and select the "Linear" trendline from the drop-down bar
That's it! You can even select the options to show the line equation or the R-squared value!
Here is a picture of the selected options and what your graph should look like (check that nice R-squared value!).
http://i.imgur.com/AvfPv.png
I hope this helps and hope it moves up to the top of the Google search page for this feature.

Hi Asclepius37,
Why not just search "trend" or "trendline" in the Numbers '09 User Guide?
That would take you to page 149 of the guide and the article "Showing Trendlines in Charts," which lists a set of instructions very similar to those in your post.
The Numbers '09 User Guide and the iWork Formulas and Functions User Guide are searchable pdf files, and may both be downloaded through kinks in the Help menu in Numbers. Both are excellent resources to have on hand.
Regards,
Barry
PS: Searching "best fit" will return zero results, but "best" or "best-fit" will get you to the same article.
B

Calendar app. How do i insert a line break in the title of an appointment?

How do i insert a line break in the title of an appointment?

Jonny Marshall wrote:
Hi, I've had this problem for a while now but just can't find the answer anywhere. I keep seeing that 'shift+return' or 'ctrl+return' will create a new line in a cell in numbers but it just doesn't! I can't seem to find a way of doing it. Please help!
Difficult to guess what is wrong in your system or what you made wrongly.
Here it work.
Maybe a problem of corrupted preferences.
Try to run Numbers from an other User Account.
If it behaves flawlessly it will be time to try to disable the Preferences files:
<startupVolume>:Users:<yourAccount>:Library:Preferences:com.apple.iWork.Numbers. plist
<startupVolume>:Users:<yourAccount>:Library:Preferences:com.apple.iWork.Numbers. LSSharedFileList.plist
(Also, not numbers related, but if you happen to know how I find out what version of OSX I'm using please let me know.)
menu :  (Apple)
menu item : About this mac
Yvan KOENIG (VALLAURIS, France) jeudi 3 juin 2010 14:41:07

How to draw line of best fit?

Hey all,
I am trying to draw a line of best fit with the scattered points being displayed as well. I have attached my VI below and tried all sorts of methods,
but to no avail. I am aware that there is a 'liner fit.vi' which I tried, but it did not give me what I wanted. In fact the line wasn't best fit at all.
I hope someone could help me as I'm new to LabVIEW.
Thanks in advance!
Cheers,
Ruben
Attachments:
Weibull LabVIEW Plot_Valve Spring.vi ‏15 KB

Hi Ruben
The Linear Fit.vi should provide the results you require. Check the attachment for an edited version of your code. Does this solve your problem? You can check the help file for advice on using different fitting techniques, setting tolerances and weightings.
Regards,
Peter D
Attachments:
EDIT_Weibull LabVIEW Plot_Valve Spring.vi ‏23 KB

Help with Line of Best Fit equation!

Alright, I'm making a graphing program where the user can input up to 10 coordinates (all ints) and when they click draw, the points will be graphed on a cartesian plain and the program will calculate and draw the line of best fit... including displaying the equation.
I've got the yIntercept to work perfectly, but sometimes the slope comes out to be 0.0, and such.
The equation to do it can be found on this site (in the big white space)
http://people.hofstra.edu/faculty/Stefan_Waner/RealWorld/calctopic1/regression.html
There are several things you must do first:
- Find the sum of all the X values
- Find the sum of all the Y values
- Find the sum of all the X*Y values
- Find the sum of all the X^2 values
You then stick it into the equation (you can see on that site) and you will get the slope. You then take the slope value and insert it into another equation to get the y-intercept
I was just wondering if you could just look over my calculation and see where I may be going wrong. (Sometimes, I get an error in the console saying I cannot divide by 0)
public void lineOfBestFit(int numOfPoints, int largeNumX, float increment, float incrementY)
     Graphics g = canvas.getGraphics();
     float sumX = 0;
     float sumY = 0;
     float sumXY = 0;
     float sumXSqr = 0;
     int smallNumX=9999999;
     int firstPoint, lastPoint;
     //Creates the variables for the line of best fit equation
     for(int j=0;j<numOfPoints;j++)
          sumX+=xValue[j];
          sumY+=yValue[j];
          sumXY+=(xValue[j]*yValue[j]);
          sumXSqr+=(Math.pow(xValue[j],2));
     //Line of best fit equation
     float slope = ((numOfPoints*sumXY)-(sumX*sumY))/((numOfPoints*sumXSqr)-(sumX*sumX));
     float yInt = (sumY - (slope*sumX))/numOfPoints;
     for(int j=0;j<numOfPoints;j++)
          if(xValue[j]<smallNumX)
               smallNumX=xValue[j];
     firstPoint=((int)((slope*smallNumX)+yInt)*50/(int)incrementY+210);
     lastPoint=((int)(slope*largeNumX+yInt)*50/(int)incrementY+210);
     int firstX=((int)(smallNumX*50/(int)increment+210));
     int lastX=((int)(largeNumX*50/(int)increment+210));
     g.drawLine(firstX,firstPoint,lastX,lastPoint);
     //Rounds and displays the line of best fit equation
     slope = (Math.round(slope*100))/100;
     yInt = (Math.round(yInt*100))/100;
     if(numOfPoints>1)
                 if(yInt < 0)
          g.drawString("y = " +slope+ "x " +yInt,250,350);
          else
               g.drawString("y = " +slope+ "x +" +yInt,250,350);

I think I may have solved it.... seems to be working now.
I casted all the numOfPoints as (float) .... and commented out the rounding. Since some of the slopes were coming out to be 0.00003, that would display 0.0 if I rounded.

Line of best fit in scatter plots

when making a line of best fit ( in this case a curve of best fit) how do I extend the curve beyond my data so that I can extrapolate information? Can I do this or will I have to do it manually? (print it out and draw it myself)

If you graph your data you can allow Numbers to plot a best fit AND show the equation it used (which will depend on the type of fit you selected).
Here I plotted some data where I introduced random noise (so it won't be "perfect") then had Numbers provide the best fit.:
The bluse graph is the original data. The Green is a prediction based on the coefficients from Numbers.
Once you graph the original data click on the graph, and then click a second time on one of the points in the graph to highlight the series:
Once you have the series highlighted you can use the Chart Inspector to turn on the Trendline.
I selected Polynomial because (1) It fit best and (2) the equation I used to make my made-up data was actually a polynomial. Check the "Show Equation" box to see the coefficients. Now take these coefficients and place then in cells of your table that has the original data (or some other table).
Now add a new column to your data (I called mine Ypredicated or Yextrapolated):
Now add a fomula to use the coefficients which will produce a 2nd graph you may extend beyond the data set:
C2=$E$6*A2*A2+$E$7*A2+$E$8
select C2 and fill down as needed (make sure the references to the coefficients are absolute... hence the "$" before the cell row and column names in the formula)
Finally add the extrapolated curve to your graph to see if it fits:
click on the graph
1) click the little cog at the top of the X column and select "Share X values"
<can't include screen shot right now... not sure why>
2) then expand the graph data set by clicking and holding the little circle at the bottom right of the highlighted area, and drag to the right so the new predicted column is included.
<can't include screen shot right now... not sure why>

Line of Best Fit/Trendline

As part of my Physics class we need to graph data that can only be displayed using a line of best fit (AKA a Trendline) - I can make any graph fine on Numbers but I am at a loss on how to make a trendline.
Could you please aid me in my search to create a Trendline?
Thanks,
Jean-Paul J
Message was edited by: Jean-Paul J

Question asked and responded several times.
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Yvan KOENIG (from FRANCE dimanche 28 septembre 2008 15:45:22)

Line of best fit in NUMBERS

How is a line of best fit created from a scatter graph in NUMBERS. There is a function called SLOPE which seems to do this but no information on how to use it!

no information on how to use it!
you can tap the blue arrow next to the function name for a small guide on how to use the function
You can tap on the name of the function two times (pause in between) and the same dialog appears above it
There is an entire manual dedicated to the functions used in Numbers.
As almost all of these functions are identical between spreadsheets many examples can be found on the internet but for the other programs (XL for example). Just remember that Array formulas (ones that require Ctrl-Shift-Enter in XL) dont exist in Numbers. You would use the Index function to wrap those functions that require CSE XL functions, as described in the help file for LINEST.
You might also look at LINEST as well if your working with lines of best fit.
Jason

Line of Best Fit / Linear Regression

I am trying ot get a line of best fit for a set of data in oracle
Lets say i have the following dataset.
Since there are a lot of 0 in the Terms I would like to ignore those Terms
Only use the Terms which have values to get a line of best fit.
Any help will be appreciated.
Thank you.
       TERMS            Count
TERM_0801     78
TERM_0802     58
TERM_0803     0
TERM_0804     82
TERM_0805     0
TERM_0806     0
TERM_0807     32
TERM_0808     0
TERM_0901     92
TERM_0902     0
TERM_0903     0
TERM_0904     56
TERM_0905     0
TERM_0906     0
TERM_0907     0
TERM_0908     0
TERM_1001     85
TERM_1002     0
TERM_1003     0
TERM_1004     67
Oracle Database 10g Enterprise Edition Release 10.2.0.5.0 - 64bi
Edited by: Chloe_19 on Jul 24, 2012 11:14 PM

Argh, i wonder about the values i got, different from what excel says ;-), till you came up with your solution.
They changed the order of the paramters from that what i consider as common:
"expr1 is interpreted as a value of the dependent variable (a y value), and expr2 is interpreted as a value of the independent variable (an x value)."
Do they also have left-hand traffic in the new world?
However, didnt OP wanted to have the zeros eliminated before the calculus?
with data as
select 'TERM_0801' t, 78 y from dual union all
select 'TERM_0802', 58 from dual union all
select 'TERM_0803', 0 from dual union all
select 'TERM_0804', 82 from dual union all
select 'TERM_0805', 0 from dual union all
select 'TERM_0806', 0 from dual union all
select 'TERM_0807', 32 from dual union all
select 'TERM_0808', 0 from dual union all
select 'TERM_0901', 92 from dual union all
select 'TERM_0902', 0 from dual union all
select 'TERM_0903', 0 from dual union all
select 'TERM_0904', 56 from dual union all
select 'TERM_0905', 0 from dual union all
select 'TERM_0906', 0 from dual union all
select 'TERM_0907', 0 from dual union all
select 'TERM_0908', 0 from dual union all
select 'TERM_1001', 85 from dual union all
select 'TERM_1002', 0 from dual union all
select 'TERM_1003', 0 from dual union all
select 'TERM_1004', 67 from dual
select
round(regr_slope(y,x), 4) slope
,round(regr_intercept (y, x) , 4) intercept
,round(regr_r2(y,x), 4) best_fit
from (
select
row_number() over ( order by t ) x, y
from data
where
y!=0
SLOPE INTERCEPT BEST_FIT
.4762 66.6071 .0035 regards
Edited by: chris227 on 25.07.2012 04:58
Edited by: chris227 on 25.07.2012 05:10
best fit added

How can I insert a line that extends from a word without it affecting the formatting of the WHOLE document?

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Just wanted to ask how can I insert new line item which were created from a file
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The requirement was to create new line item from a file and use those details in updating the contracts.
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Hi Rajvansh Ravi,
This is for Service Contracts. Sorry for missing this detail.
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How to I insert a line of best fit on a scatter plot????

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