How to insert Blank rows while Zero Suppression is Activated?

I am using BI 2004s and have applied zero suppression to a query I have built, how ever this removes the blank rows I am using to format the report. Any ideas on how I could get the blank rows to remain whilst removing zero value rows?
Thanks
Stu

in zero suppression, select active(All values = 0)
*reward if helpful*

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Insert Blank row After every Row in alv report

How to insert blank row After every row in Alv report

what do you mean by a 'blank row'? ALV displays tabular data with 'any' number of columns. Now if you actually want a blank row (no columns at all, just a row), then that is just not possible. If I'm not mistaken, this question was posted before, so try to do a search on SCN. See what is says.

How to add blank rows between groups of duplicate rows?

here is my setup
create table #tmpA(rowID int identity(1,1), fName varchar(10), lName varchar(10))
insert into #tmpA
select 'a', 'b' union all
select 'a', 'b' union all
select 'c', 'd' union all
select 'c', 'd' union all
select 'e', 'f' union all
select 'e', 'f' union all
select 'g', 'h' union all
select 'g', 'h'
select distinct fName, lName
into #tmpB
From #tmpA
select t1.* from #tmpA t1 Join #tmpB t2 on t1.fName = t2.fName and t1.lName = t2.lName
--output
rowID fName lName
1             a        b
2             a        b
3            c         d
4             c         d
5             e        f
6            e        f
7             g        h
8             g        h
I want to add blank rows between rows 2 & 3 and between rows 4 & 5 and between rows 6 & 7 in the join query above. Is there Tsql that can accomplish something like this to make the join query result look like the following output?
rowID fName lName
1           a         b
2           a          b
3            c          d
4            c         d
5           e         f
6            e         f
7           g          h
8            g         h
or if this is not possible I could go with an output like this:
rowID fName lName
1             a         b
2             a         b
3
4             c         d
5             c         d
6
7             e         f
8             e        f
9
10           g         h
11           g         h
Rich P

I came up with the following on my own. I was just hoping there might be a fancier way to do this - like without looping -- and yes, I could/should do this in a presentation layer, but I just wanted to do this in Query Analyzer (or whatever they call
it now -- SSMS ...) -- BTW, thanks CELKO for the suggestion about how to insert multiple rows using Values -- works great.
If (object_id('tempdb..#tmpA') is not null) drop table #tmpA
If (object_id('tempdb..#tmpC') is not null) drop table #tmpC
create table #tmpA(rowID int identity(1,1), fName varchar(10), lName varchar(10))
insert into #tmpA
values
('a','b'),
('a','b'),
('c','d'),
('c','d'),
('e','f'),
('e','f'),
('g','h'),
('g','h')
create table #tmpC(rrowID int Identity(1,1), rowID int, fName varchar(10), lName varchar(10))
declare @i int, @s varchar(10), @t varchar(10), @u varchar(10), @v varchar(10)
select @i = min(rowID) from #tmpA
set @u = 'xx'
While (@u != 'yy')
Begin
   select @s = fName, @t = lName from #tmpA Where rowID = @i
   if exists(select 1 from #tmpA Where rowID = @i + 1)
      select @u = fname, @v = lName From #tmpA Where rowID = @i + 1
   else
      set @u = 'yy'
    if @s = @u And @t = @v
       begin
         Insert Into #tmpC(rowID, fName, lName) Select * from #tmpA Where rowID = @i
         Insert Into #tmpC(rowID, fName, lName) Select * from #tmpA Where rowID = @i + 1
       end
    else
       begin
          Insert Into #tmpC(rowID, fName, lName) Select null, '', ''
       end
    set @i = @i + 1
End
select * from #tmpC
--output from #tmpC
rrowID rowID fName lName
1           1         a       b
2            2         a     b
3        NULL
4            3         c        d
5            4        c        d
6          NULL
7             5        e      f
8            6         e        f
9           NULL
10          7          g       h
11          8          g        h
12         NULL
Rich P

How to insert a row in oracle

how to insert a row in oracle if we have three colums all are number datatype i want one of the column blank;

Hi,
James has replied to your question ..
you seem to be new to sql
just adding to it for you information.. that in this case col2 will have NULL value.
I suggest you may please read the startup docs... They shall help you to unserdstand the sql better.
http://www.w3schools.com/sql/default.asp
Regards

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hello,
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suja

hello,
thanks for your rely,
again having the problem of while clicking the insert button, the insert button is not not accessing, insert button is not responding.
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suja

How to insert blank lines in the ALV output.

Hi Friends,
Could any body help me out How to insert blank lines in the ALV output.?? Any Code pls...
Thank you,
Vikram.C

hi vikram
do like this
In the fieldcatalog table all the fields should be in editable mode
ie lw_fcat-edit = 'X'.
CALL FUNCTION 'REUSE_ALV_GRID_DISPLAY'
EXPORTING
i_callback_program = sy-repid
i_callback_pf_status_set = 'SET_PF_STATUS'
i_callback_user_command = 'USER_COMMAND'
is_layout = lv_layout
it_fieldcat = lt_fcat[]
i_save = 'A'
is_variant = lv_variant
TABLES
t_outtab = lt_license[]
EXCEPTIONS
program_error = 1
OTHERS = 2.
IF sy-subrc 0.
MESSAGE ID sy-msgid TYPE sy-msgty NUMBER sy-msgno
WITH sy-msgv1 sy-msgv2 sy-msgv3 sy-msgv4.
ENDIF.
ENDFORM. " display_data
*& Form user_command
FORM user_command USING r_ucomm TYPE sy-ucomm
rs_selfield TYPE slis_selfield.
CASE r_ucomm.
WHEN 'ADD'. "
data: lv_ind type i.
data: lv_line type i.
describe table lt_license lines lv_line.
loop at lt_license into lw_license.
lv_ind = sy-tabix.
if lv_ind = lv_line.
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endif.
endloop.
ENDCASE.
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reward points if useful
Rohan

I want to bring in text from Word (and the web) that is already hyperlinked into InDesign. How do I do it while keeping the links active?

I want to bring in text from Word (and the web) that is already hyperlinked into InDesign. How do I do it while keeping the links active?
Whenever I copy/paste from web or Word it removes the hyperlinks. And when I try to do it by "Place"ing a Word document into my InDesign project it keeps the formatting with it, the rectangles around the text.
I have the latest version of InDesign.
Any help is appreciated.

Copy-and-paste may not include formatting. A regular import using Place is the best way.
The rectangles around the hyperlinks are just to indicate they are links -- they do not print, but they do show up in your PDF.
You can remove them by double-clicking the hyperlink in the Hyperlinks panel and select "Invisible Rectangle" as type.
Typically, Word hyperlinks are formatted -- blue text, underline -- with a Character Style. If you want to remove or change the formatting, all you have to do is change the character style. My experience, though, is you must check all hyperlinks because for no apparent reason sometimes they appear in the document without the character style.

EvDRE Question -- Inserting Blank Rows

Hi all,
Here's a good question that we've run into a couple of different times with EvDRE: Say you are specifying a Memberset to expand on that will consist of a comma-delimited list like:
bas(Accounts_Receivable), Accounts_Receivable,
bas(Accounts_Payable), Accounts_Payable,
bas(Notes_Receivable), Notes,Receivable,
bas(Fixed_Assets), Fixed_Assets ...etc.
This would expand each of the four account groups, and follow each of them with their respective parent.
Question: What's the best way to insert a blank row after each parent/subtotal?
It turns out that if you use the SUPPRESS=Y for that Expansion, that the Blanks get suppressed (since the suppression is . Also, I'm not sure if there is a good Before/After Range option... But, how about maybe using INSERT ?
Thanks,
Garrett

Garrett,
You can insert blank lines by adding extra commas with nothing in between.
So in your example this would mean:
bas(Accounts_Receivable), Accounts_Receivable,,bas(Accounts_Payable), Accounts_Payable,,bas(Notes_Receivable), Notes,Receivable,bas(Fixed_Assets), Fixed_Assets
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The option 'insert' will give you the possibilitie to manually insert new lines which you have to select with your right mouse button as an enduser, so I think this is useless this situation.
Hope this helps,
Alwin

How to insert a row in the detail table of a treeTable (master/detail)?

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Thanks.

Erp, why do you keep giving the links to that example or the zip including the project of that example? I explicitly asked to not send any links to that example, which does not work with jdev 11.1.2.1.
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:bndVarFirstName =null
:bndVarFirstName =null
:bndVarFirstName =null
:bndVarFirstName =null
:bndVarFirstName =null
:bndVarFirstName =null
:bndVarFirstName =null
:bndVarFirstName =null
:bndVarFirstName =null
:bndVarFirstName =null
:bndVarFirstName =null
:bndVarFirstName =null
:bndVarFirstName =null
:bndVarFirstName =null
:bndVarFirstName =null
:bndVarFirstName =null
:bndVarFirstName =null
:bndVarFirstName =null
:bndVarFirstName =null
:bndVarFirstName =null
:bndVarFirstName =null
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<FormRenderer> <_warnUnpoppedContextChanges> ADF_FACES-60095:Durante l'elaborazione del renderer del form, la modifica di contesto trovata non corrisponde al componente previsto.
<UIXCollection> <processSaveState> è possibile che la chiave di riga non venga reimpostata correttamente alla fine della richiesta. ID componente: :pc1:tt1, ViewId: /treeSample.jspx
<UIXComponentBase> <processSaveState> Salvataggio dello stato per gli elementi figlio del componente RichPanelCollection[UIXFacesBeanImpl, id=pc1] non riuscito.
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<UIXComponentBase> <processSaveState> Salvataggio dello stato per gli elementi figlio del componente RichForm[UIXFacesBeanImpl, id=f1] non riuscito.
<UIXComponentBase> <processSaveState> Salvataggio dello stato per gli elementi figlio del componente RichDocument[UIXFacesBeanImpl, id=d1] non riuscito.
<LifecycleImpl> <_handleException> ADF_FACES-60098:Il ciclo di vita Faces ha ricevuto eccezioni non gestite nella fase RENDER_RESPONSE 6
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     at org.apache.myfaces.trinidad.component.UIXComponentBase.processSaveState(UIXComponentBase.java:1043)
     at javax.faces.component.UIComponentBase.processSaveState(UIComponentBase.java:1156)
     at org.apache.myfaces.trinidadinternal.application.StateManagerImpl.saveView(StateManagerImpl.java:193)
     at org.apache.myfaces.trinidadinternal.application.StateManagerImpl.getViewState(StateManagerImpl.java:134)
     at oracle.adfinternal.view.faces.renderkit.rich.PprResponseWriter._writeViewState(PprResponseWriter.java:514)
     at oracle.adfinternal.view.faces.renderkit.rich.PprResponseWriter.endDocument(PprResponseWriter.java:83)
     at oracle.adfinternal.view.faces.renderkit.rich.DocumentRenderer.encodeAll(DocumentRenderer.java:1490)
     at oracle.adf.view.rich.render.RichRenderer.encodeAll(RichRenderer.java:1452)
     at org.apache.myfaces.trinidad.render.CoreRenderer.encodeEnd(CoreRenderer.java:511)
     at org.apache.myfaces.trinidad.component.UIXComponentBase.encodeEnd(UIXComponentBase.java:923)
     at javax.faces.component.UIComponent.encodeAll(UIComponent.java:1659)
     at oracle.adfinternal.view.faces.context.PartialViewContextImpl._processRender(PartialViewContextImpl.java:321)
     at oracle.adfinternal.view.faces.context.PartialViewContextImpl.processPartial(PartialViewContextImpl.java:152)
     at javax.faces.component.UIViewRoot.encodeChildren(UIViewRoot.java:974)
     at javax.faces.component.UIComponent.encodeAll(UIComponent.java:1652)
     at oracle.adfinternal.view.faces.component.AdfViewRoot.encodeAll(AdfViewRoot.java:91)
     at com.sun.faces.application.view.JspViewHandlingStrategy.doRenderView(JspViewHandlingStrategy.java:431)
     at com.sun.faces.application.view.JspViewHandlingStrategy.renderView(JspViewHandlingStrategy.java:233)
     at org.apache.myfaces.trinidadinternal.application.ViewDeclarationLanguageFactoryImpl$ChangeApplyingVDLWrapper.renderView(ViewDeclarationLanguageFactoryImpl.java:350)
     at com.sun.faces.application.view.MultiViewHandler.renderView(MultiViewHandler.java:131)
     at javax.faces.application.ViewHandlerWrapper.renderView(ViewHandlerWrapper.java:273)
     at org.apache.myfaces.trinidadinternal.application.ViewHandlerImpl.renderView(ViewHandlerImpl.java:165)
     at oracle.adfinternal.view.faces.lifecycle.LifecycleImpl._renderResponse(LifecycleImpl.java:1027)
     at oracle.adfinternal.view.faces.lifecycle.LifecycleImpl._executePhase(LifecycleImpl.java:334)
     at oracle.adfinternal.view.faces.lifecycle.LifecycleImpl.render(LifecycleImpl.java:232)
     at javax.faces.webapp.FacesServlet.service(FacesServlet.java:313)
     at weblogic.servlet.internal.StubSecurityHelper$ServletServiceAction.run(StubSecurityHelper.java:227)
     at weblogic.servlet.internal.StubSecurityHelper.invokeServlet(StubSecurityHelper.java:125)
     at weblogic.servlet.internal.ServletStubImpl.execute(ServletStubImpl.java:300)
     at weblogic.servlet.internal.TailFilter.doFilter(TailFilter.java:26)
     at weblogic.servlet.internal.FilterChainImpl.doFilter(FilterChainImpl.java:56)
     at oracle.adf.model.servlet.ADFBindingFilter.doFilter(ADFBindingFilter.java:173)
     at weblogic.servlet.internal.FilterChainImpl.doFilter(FilterChainImpl.java:56)
     at oracle.adfinternal.view.faces.webapp.rich.RegistrationFilter.doFilter(RegistrationFilter.java:122)
     at org.apache.myfaces.trinidadinternal.webapp.TrinidadFilterImpl$FilterListChain.doFilter(TrinidadFilterImpl.java:468)
     at oracle.adfinternal.view.faces.activedata.AdsFilter.doFilter(AdsFilter.java:60)
     at org.apache.myfaces.trinidadinternal.webapp.TrinidadFilterImpl$FilterListChain.doFilter(TrinidadFilterImpl.java:468)
     at org.apache.myfaces.trinidadinternal.webapp.TrinidadFilterImpl._doFilterImpl(TrinidadFilterImpl.java:293)
     at org.apache.myfaces.trinidadinternal.webapp.TrinidadFilterImpl.doFilter(TrinidadFilterImpl.java:199)
     at org.apache.myfaces.trinidad.webapp.TrinidadFilter.doFilter(TrinidadFilter.java:92)
     at weblogic.servlet.internal.FilterChainImpl.doFilter(FilterChainImpl.java:56)
     at oracle.security.jps.ee.http.JpsAbsFilter$1.run(JpsAbsFilter.java:111)
     at java.security.AccessController.doPrivileged(Native Method)
     at oracle.security.jps.util.JpsSubject.doAsPrivileged(JpsSubject.java:313)
     at oracle.security.jps.ee.util.JpsPlatformUtil.runJaasMode(JpsPlatformUtil.java:413)
     at oracle.security.jps.ee.http.JpsAbsFilter.runJaasMode(JpsAbsFilter.java:94)
     at oracle.security.jps.ee.http.JpsAbsFilter.doFilter(JpsAbsFilter.java:161)
     at oracle.security.jps.ee.http.JpsFilter.doFilter(JpsFilter.java:71)
     at weblogic.servlet.internal.FilterChainImpl.doFilter(FilterChainImpl.java:56)
     at oracle.dms.servlet.DMSServletFilter.doFilter(DMSServletFilter.java:136)
     at weblogic.servlet.internal.FilterChainImpl.doFilter(FilterChainImpl.java:56)
     at weblogic.servlet.internal.RequestEventsFilter.doFilter(RequestEventsFilter.java:27)
     at weblogic.servlet.internal.FilterChainImpl.doFilter(FilterChainImpl.java:56)
     at weblogic.servlet.internal.WebAppServletContext$ServletInvocationAction.wrapRun(WebAppServletContext.java:3715)
     at weblogic.servlet.internal.WebAppServletContext$ServletInvocationAction.run(WebAppServletContext.java:3681)
     at weblogic.security.acl.internal.AuthenticatedSubject.doAs(AuthenticatedSubject.java:321)
     at weblogic.security.service.SecurityManager.runAs(SecurityManager.java:120)
     at weblogic.servlet.internal.WebAppServletContext.securedExecute(WebAppServletContext.java:2277)
     at weblogic.servlet.internal.WebAppServletContext.execute(WebAppServletContext.java:2183)
     at weblogic.servlet.internal.ServletRequestImpl.run(ServletRequestImpl.java:1454)
     at weblogic.work.ExecuteThread.execute(ExecuteThread.java:209)
     at weblogic.work.ExecuteThread.run(ExecuteThread.java:178)
while I get this from my own project based on the above one:
<UIXEditableValue> <_isBeanValidationAvailable> A Bean Validation provider is not present, therefore bean validation is disabled
<UIXRegion> <_logIllegalContextChangeMessage> ADF_FACES-10026:Durante l'elaborazione del componente area, non è stata trovata una modifica di contesto oppure la modifica trovata non corrisponde all'istanza impostata dal componente corrente. Prevista oracle.adf.view.rich.component.fragment.UIXRegion$RegionContextChange, trovata UIXCollection.CollectionComponentChange[Component class: oracle.adf.view.rich.component.rich.data.RichTreeTable, component ID: tt1].
<UIXRegion$RegionSiteImpl> <validate> Attempt to validate an already invalid RegionSite:
<UIXCollection> <processSaveState> è possibile che la chiave di riga non venga reimpostata correttamente alla fine della richiesta. ID componente: :pt1:r1:pt1:pc1:tt1, ViewId: /main.jspx
Edited by: user10047839 on 20-ott-2011 7.23

How to Insert the row in the View object

I want to insert the row in the view object by instantiating Impl.java file
Could someone please let me know how to insert the blank row
Thanks

Inserting onto a view object should be done the following way:
//vo is your view object
Row aRow = vo.createRow();
//Set your attributes
aRow.setAttribute("AttributeName", objectValue);
//insert
vo.insertRow(aRow);
That should work for you if you are programming the input. If you are using java components bound to columns in a view object then the input should be done automatically for you when you commit.

How to Print Blank row in between the lsit of records/rows

Hi,
My Rtf output is 10 rows with 12 columns in each row, which comes form the SQL query of the RDF. Ii want to display a blank row after 9th row and before 10th row. So it would be 11 rows where 10th row should be blank. So how can i get this done through RTF syntax.
FYI, the o/p should look like below.
column 1 column 2 column3 ...
abc ac abc
abc ac abc
abc ac abc
abc ac abc
abc ac abc
abc ac abc
abc ac abc
abc ac abc
abc ac abc
abc ac abc
Any help is highly appreciated. Thanks much for your time and help.

Hi,
As far as I know, if we follow your steps: Page Layout settings > Page Setup > Print title> Sheet>Rows to Repeat at Top, we can set the row labels to every page, please see the below image:
We can see the row labels with page layout mode, but it does not display in Print Preview. Please try to save it as PDF or print it to see the row labels with every page.
Regards,
George Zhao
TechNet Community Support
It's recommended to download and install
Configuration Analyzer Tool (OffCAT), which is developed by Microsoft Support teams. Once the tool is installed, you can run it at any time to scan for hundreds of known issues in Office
programs.

How to insert 10 rows at a time in the oracle

how ti insert r update 10 query at a time in the oracle

You can do a small test to find it out.
SQL> set serveroutput on
SQL> drop table t
2 /
Table dropped.
SQL> drop table s
2 /
Table dropped.
SQL> create table s(no integer, name varchar2(4000))
2 /
Table created.
SQL> create table t(no integer, name varchar2(4000))
2 /
Table created.
SQL> insert into s
2 select level, rpad('*',4000,'*')
3    from dual
4 connect by level <= 10000
5 /
10000 rows created.
SQL> commit
2 /
Commit complete.
SQL> declare
2     ltime integer;
3 begin
4     ltime := dbms_utility.get_time;
5
6     for i in (select * from s)
7     loop
8             insert into t(no, name) values(i.no,i.name);
9     end loop;
10
11     ltime := dbms_utility.get_time - ltime;
12
13     dbms_output.put_line('Exec Time:'||ltime/100||' Seconds...');
14     commit;
15 end;
16 /
Exec Time:17.22 Seconds...
PL/SQL procedure successfully completed.
SQL> truncate table t
2 /
Table truncated.
SQL> declare
2     type my_type is table of s%rowtype;
3     lType my_type;
4     ltime integer;
5 begin
6     ltime := dbms_utility.get_time;
7
8     select * bulk collect into lType from s;
9
10     forall i in 1..lType.count
11             insert into t values lType(i);
12
13     ltime := dbms_utility.get_time - ltime;
14
15     dbms_output.put_line('Exec Time:'||ltime/100||' Seconds...');
16
17     commit;
18 end;
19 /
Exec Time:6.27 Seconds...
PL/SQL procedure successfully completed.
SQL> truncate table t
2 /
Table truncated.
SQL> declare
2     ltime integer;
3 begin
4     ltime := dbms_utility.get_time;
5
6     insert into t select * from s;
7
8     ltime := dbms_utility.get_time - ltime;
9
10     dbms_output.put_line('Exec Time:'||ltime/100||' Seconds...');
11
12     commit;
13 end;
14 /
Exec Time:3.26 Seconds...
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Karthick.

How can print blank rows for XML output report..

Hi all,
I am working in XML output PO fix format report and in that report there is 3 sections. (1) Header section(2)Line section (3) Footer section. My requirement is like this, header and footer section print in all pages and line section break for next page after printing fix 15 lines in a page. And if any page has less then 15 lines then it generate remaining blank row to maintain footer position.
Please suggest me, how can i generate blank rows and break lines for page if there is more then 15 rows in Line section.
Thanks in Advance!

Hi,
<?for-each:ROW?>
<?end for-each?><xsl:variable name="cnt" select="count(//row|//ROW)" />
<?for-each:xdoxslt:foreach_number($_XDOCTX,1,15-count(ROW),1)?> <?end if?>
this will create 15 lines irrespective of you have that much rows of data in xml or not
if you want more help , drop me mail @ [email protected]

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HI,
I have used below code for getting details from databse. Now i have to insert a row in the database.
Kindly let me know how can i use below code for inserting a row in the database. or should i make any change in its viewObject's Query.
If there is any another way of inserting data in database through method binding please let me knoe that.
ApplicationModule myService = ADFUtils.getApplicationModuleForDataControl("AppModuleDataControl");
ViewObject userInfoVO = myService.findViewObject("EmployeeViewParam1");
userInfoVO.executeQuery();
DCBindingContainer bindings = (DCBindingContainer)BindingContext.getCurrent().getCurrentBindingsEntry();
DCIteratorBinding dcItteratorBindings =
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RowSetIterator rowIter1 = dcItteratorBindings.getRowSetIterator();
Row[] rows1 = rowIter1.getAllRowsInRange();
for(int i=0;i<rows1.length;i++)
this.empId = (String)rows1.getAttribute("EmployeeId"); // primary key
this.employeeName = (String)rows1[i].getAttribute("Employeename");
Thanks and Regards,

HI,
i have tried belod code. for this i have made AppModuleImpl Class and wrote below method in that and called this method from my bean class with help of AppModuleImpl's Object.
public void createEmployee (){
ViewObjectImpl employee=getEmployeeView1();
// ViewObject employee= findViewObject("EmployeeView");
Row row = employee.createRow();
row.setAttribute("Employeeid",189420);
row.setAttribute("Employeename","Test");
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Kindly help me to shortout this.

How to insert Existing rows by modifying some cloumns values??

Respected experts ,
I have 72 rows in a table .I want to insert another 72 rows with one column value change and another columns value same??
Please suggest me how I do this ????
Thanks in advance.

Do you want to insert 72 rows from the same table but just changing value of the one column? If so, take a look at Scott's solution
Best Regards,Uri Dimant SQL Server MVP,
http://sqlblog.com/blogs/uri_dimant/
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