How to insert time

hi,
I want to insert (10.46.47.000000) this time format in a date field.
I have NLS_DATE_FORMAT=YYYY-MM-DD HH24.MI.SS in autoexec.bat

I tried but didnt got
SQL> select to_char('10.46.47.000000','hh24.mi.ss.ff') from dual;
select to_char('10.46.47.000000','hh24.mi.ss.ff') from dual
ERROR at line 1:
ORA-01722: invalid number
And again I tried with
SQL> select to_date('10.46.47.000000','hh24.mi.ss.ff') from dual;
select to_date('10.46.47.000000','hh24.mi.ss.ff') from dual
ERROR at line 1:
ORA-01821: date format not recognized
I am using Oracle 8i.

Similar Messages

How to insert time line

In iMovie 10 how do I insert a time line reference. In the attached photo I downloaded a movie file in which the time line shows up. On the 2nd photo which is my clip the time line does not show up. Thanks.

Hey gator12345,
Thanks for the question. The markers you see in your first screenshot have time references for the start of each clip. Because your second screenshot is one long clip, that is why you do not see (or have the option to add) a reference point. You can split the clip to add time references to the thumbnails.
Timeline
The area in the iMovie window where you create your movie by adding and arranging clips and making all your edits.
Each clip in the timeline is represented by a thumbnail or series of thumbnails.
via iMovie Help: timeline
http://help.apple.com/imovie/mac/10.0/#mov4f95d4de6
If you are interested in more advanced timeline editing, you may want to look into Final Cut Pro X:
Apple - Final Cut Pro X - Overview
https://www.apple.com/final-cut-pro/
Thanks,
Matt M.

How to insert Time alone

i got time alone if i insert this in datetime field while selecting will return with default date as 1st date of current month ... is there any other option other than
varchar field....

Hi,
Starting in Oracle 9, there's a datatype INTERVAL DAY TO SECOND for storing times. It's described in the SQL Language manual.
DATEs in Oracle always have a year, month and day.
Rather than store time in a DATE column, you can it in a NUMBER column; units of 1 day would be convenient.

How to insert into more than one table at a time also..

hi,
i am a newbee.
how to insert into more than one table at a time
also
how to get a autoincremented value of an id say transactionid for a particular accountid.
pls assume table as
transactionid accountid
101 50
102 30
103 50
104 35
i want 102 for accountid 30 and 103 for accountid 50.
thank u

@blushadow,
You can only insert into one table at a time. Take a look here :
Re: insert into 2 tables
@Raja,
I want how to extract the last incremented value not to insert.Also, I don't understand your thread title... which was "how to insert into more than one table at a time also.. "
Insert, extract... ? Can you clarify your job ?
Nicolas.

How to Insert more than one record at a time- with fixed set of values in one field

Can someone guide as to how to insert multiple records at a time using ASP VBScript in Dreamweaver CS4 or ADDT.
If someone can guide then the exact problem is given below.
I have a MS access database with one table. The table has three fields. The first field is an autonumber field for ID number.
The second field contains string values- One out of 7 predefined values. One set of records consists of 7 records containing all the seven types of predefined values in fields no 1.
The third field is a numeric field and can contain integers.
I want that the user can enter data for the table using an ASP form in such a way that he enters one set of records at a time in one single screen. This way he will not have to remember that he has /has not entered all the seven set of values for the field no 1.
I am not creating fields with the 7 types of field1value as their names as it will increase the number of fields drastically.
Please help for dreamweaver ASP VBScript.

I have successfully inserted seven records in one form submit operation by looping through the command object execute method.
However, the data that is being inserted by the command object is repetition of the first record and the command object is not taking any data from the text boxes for the second record onwards. In this I had used the isert record behavious generated by DW CS4 and modified it to suit my requirement. However, the data inserted in the first row is getting repeated in all the seven rows.
Please help.
Also advise if there are any free dreamweaver server side validation extensions available.

How to Insert more than one record at a time

How to insert multiple records at a time?
If someone can advise on this, then the actual problem is described below:
I have a MS access database with one table. The table has three fields. The
first field is an autonumber field for ID number.
The second field contains string values- One out of 7 predefined values. One
set of records consists of 7 records containing all the seven types of
predefined values in fields no 1.
The third field is a numeric field and can contain integers.
I want that the user can enter data for the table using an ASP form in such
a way that he enters one set of records at a time in one single screen. This
way he will not have to remember that he has /has not entered all the seven
set of values for the field no 1.
I am not creating fields with the 7 types of field1value as their names as
it will increase the number of fields drastically.
Please help with inserting multiple records at a time.

I have successfully inserted seven records in one form submit operation by looping through the command object execute method.
However, the data that is being inserted by the command object is repetition of the first record and the command object is not taking any data from the text boxes for the second record onwards. In this I had used the isert record behavious generated by DW CS4 and modified it to suit my requirement. However, the data inserted in the first row is getting repeated in all the seven rows.
Please help.
Also advise if there are any free dreamweaver server side validation extensions available.

How to insert 10 rows at a time in the oracle

how ti insert r update 10 query at a time in the oracle

You can do a small test to find it out.
SQL> set serveroutput on
SQL> drop table t
2 /
Table dropped.
SQL> drop table s
2 /
Table dropped.
SQL> create table s(no integer, name varchar2(4000))
2 /
Table created.
SQL> create table t(no integer, name varchar2(4000))
2 /
Table created.
SQL> insert into s
2 select level, rpad('*',4000,'*')
3    from dual
4 connect by level <= 10000
5 /
10000 rows created.
SQL> commit
2 /
Commit complete.
SQL> declare
2     ltime integer;
3 begin
4     ltime := dbms_utility.get_time;
5
6     for i in (select * from s)
7     loop
8             insert into t(no, name) values(i.no,i.name);
9     end loop;
10
11     ltime := dbms_utility.get_time - ltime;
12
13     dbms_output.put_line('Exec Time:'||ltime/100||' Seconds...');
14     commit;
15 end;
16 /
Exec Time:17.22 Seconds...
PL/SQL procedure successfully completed.
SQL> truncate table t
2 /
Table truncated.
SQL> declare
2     type my_type is table of s%rowtype;
3     lType my_type;
4     ltime integer;
5 begin
6     ltime := dbms_utility.get_time;
7
8     select * bulk collect into lType from s;
9
10     forall i in 1..lType.count
11             insert into t values lType(i);
12
13     ltime := dbms_utility.get_time - ltime;
14
15     dbms_output.put_line('Exec Time:'||ltime/100||' Seconds...');
16
17     commit;
18 end;
19 /
Exec Time:6.27 Seconds...
PL/SQL procedure successfully completed.
SQL> truncate table t
2 /
Table truncated.
SQL> declare
2     ltime integer;
3 begin
4     ltime := dbms_utility.get_time;
5
6     insert into t select * from s;
7
8     ltime := dbms_utility.get_time - ltime;
9
10     dbms_output.put_line('Exec Time:'||ltime/100||' Seconds...');
11
12     commit;
13 end;
14 /
Exec Time:3.26 Seconds...
PL/SQL procedure successfully completed.Thanks,
Karthick.

How dicrease the time for a bult insert.

Hi, we have a the following process..
1) create a cursor
2) insert in a table t1 acording the rows
selected in the cursor
3) a before insert on t1 create others rows on t2, t3...
This proccess cteate about 300,000 rows a take near 3 hours... my question is how dismiss this time???

Lets imagine I want to INSERT 10 rows into the following table, set a sequential product i.d. for each record and a quantity of zero:
CREATE TABLE sales (product_id NUMBER(10),
quantity NUMBER(5)) ;
Traditionally, I might write something like this (O.K., I know I could use a single INSERT statement for this, but let's assume you want to do some additional calculation inside the loop) :
BEGIN
FOR i IN 1..10 LOOP
INSERT INTO sales (product_id,quantity)
VALUES(i,0) ;
END LOOP ;
COMMIT ;
END ;
All well and good - except each INSERT causes the PL/SQL engine to request that the SQL engine should insert 1 row. This is an overhead that can be reduced by using BULK BIND coding (I mixed my terms previously - a BULK COLLECT allows multiple rows to be retrieved into a PL/SQL collections - it uses the same performance-enhancing technique, but in reverse) :
DECLARE
TYPE t_sales IS TABLE OF sales.product_id%TYPE INDEX BY BINARY_INTEGER ;
a_sales t_sales ;
BEGIN
FOR i IN 1..10 LOOP
a_sales(i) := i ;
END LOOP ;
FORALL j IN a_sales.FIRST..a_sales.LAST
INSERT INTO sales (product_id,quantity)
VALUES (a_sales(j),0) ;
COMMIT ;
END ;
The INSERT above is now passed to the SQL engine as a single request, which gives a significant performance improvement for large numbers of rows. Just remember that all those rows need to go somewhere in memory prior to the INSERT - namely the PGA for your session.
There are a few limitations to this method, the most significant being that fact that the PL/SQL table must be "simple" - i.e. no tables or records.
(Oracle Moderators: Please don't ask "Why is Andy writing such an pointless piece of code?" - it's just to demonstrate the technique!)
null

How to insert, as an input variable within formula, the total time window on scope?

How to insert, as an input variable within formula, the total time window on scope (i.e. 20ms/div x 10 div = 200ms)?
BELOW IS AN EXAMPLE OF ISSUE:
FORMULA FOR ACTION INTEGRAL:
STATISTICS:
Input variable: DPO4034(CH1);
Check Box: number of samples.
FORMULA
Input variable 0: DPO4034(CH1); alias: x0
Input variable 1: "Total Time Window on Scope???"; alias: x1
Input variable 2: Number of Samples (CH1); alias: x2
Under Operation Setup: Formula
Y= (x0^2)*(x1/x2)
Output: Processed Data 1 (CH1)
THEN USING STATISTICS:
Input signal: Processed Data 1 (CH1)
Check Box: SUM
Output: CH1 Action Integral [A^2s]
Solved!
Go to Solution.

Hi again Catherine,
I have now added another TekScope (TDS3032B) along with the DPO4034 and run the same work-around on the TDS3032B using CH1 as the "real" signal channel and CH2 as the "burst width" channel. However, the value returned for CH2 is nominally 99E+36 (min 99E+36, max 99E+36) with very few retrievals of correct burst width (~200ms). Seems the SignalExpress program is unable to consistently retrieve from TDS3032B the actual burst width (scope's time scale/window) and defaults to 99E+36 value. Any ideas on what is occurring and how to make it work? Attached are some screen captures to help guide discussion.
Regards,
Michael
Attachments:
TDS3032B - incorrect burst width.png ‏301 KB
TDS3032B - correct burst width.png ‏287 KB
DPO4034 - always correct burst width.png ‏302 KB

First time using don't know how to insert the video to start editing

first time using don't know how to insert the video to start editing

First thing you should know is that After Effects is not a video editor. Premiere is for putting shots together to tell stories (which is editing), After Effects is for creating those shots (compositing and visual effects) and creating motion graphics.
To use AE, start here: Getting started with After Effects

How to insert data in a one-to-many relationship

How do you insert data into the client, my model entity beans have a one-to-many relationship.
PARENT ENTITY BEAN
PARENT-ID
PARENT-NAME
The ejbCreate(Integer parentID,String name)
CHILD ENTITY BEAN
CHILD-ID
CHILD-NAME
PARENT-ID(foreign key of PARENTID).
ejbCreate(Integer parentID,String name,String foreignparentID)
In a jsp page i collect the parent details and 3 corresponding chld details in a text box.
Can you please tell me how do i proceed from here...
ie. how to i insert data into the entity beans..
Do i pass the child as a collection, and within parents ejbCreate() method do i lookup for the childs home interface and insert one -by -one from the collection.
1. Considering the above example, can some one pls tell how the ejbCreate() mehod signatures, for the parent and child entity beans should be.
2. Pls also show some sample client code as to how to make an insertion.
3. In case you are passing a collection of child data, then in what format does one have to insert into a collection and also how does the container know how to insert the values in the child table , bcoz we are passing as a collection.
4.In case collections cannot be inserted do we need to iterate into the collection in parent's ejbCreate() method, and manually insert into the database of the childtable, thereby creating child entity beans.
Thanks for your time and support...
regards
kartik

Hi,
3. In this case of course child's ejbCreate(and postCreate) looks like
ejbCreate(Integer childID,String name,ParentLocal parent) {
setId(Id);
setName(name);
ejbPostCreate(Integer childID,String name,ParentLocal parent) {
setParent(parent);
Here you don't need IDs, but it happens only using Locals, not Remotes, if I'm not wrong. Container does it itself.
1. Of course, if you have parent.getChildren() and parent.setChildren() then you don't need any loops, but it should be done anyway in postCreate, because in ejbCreate there no parent exists yet.
Once more 3: example - I'm using JBoss 3.2.5 as EJB container. It has tomcat inside and EJB and JSP+Struts use the same jvm. It means for me that I don't need to use remote interfaces, just locals. And in this case I can implement ejb-relations. So, a have the abstract method parent.getChildren() which returns Collection of ChildLocal - s and method parent.setChildren(Collection childrenLocals) which creates/modifies children by itself.
I have not used remotes for a long time, but as I remember it was not possible to implement ejb-relations using remotes.
regards,
Gio

How to insert more than one values

Oracle 9i
Hi all
I have 80 values how to insert it in a single time, it is in production
This is my insert statement
Insert into FND_LOOKUP_VALUES
(LOOKUP_TYPE,LANGUAGE,LOOKUP_CODE,MEANING,DESCRIPTION,ENABLED_FLAG,
START_DATE_ACTIVE,END_DATE_ACTIVE,CREATED_BY,CREATION_DATE,LAST_UPDATED_BY,L
AST_UPDATE_LOGIN,
LAST_UPDATE_DATE,SOURCE_LANG,SECURITY_GROUP_ID,VIEW_APPLICATION_ID,TERRITORY
_CODE,
ATTRIBUTE_CATEGORY,ATTRIBUTE1,ATTRIBUTE2,ATTRIBUTE3,ATTRIBUTE4,ATTRIBUTE5,AT
TRIBUTE6,ATTRIBUTE7,ATTRIBUTE8,ATTRIBUTE9,ATTRIBUTE10,ATTRIBUTE11,ATTRIBUTE1
2,ATTRIBUTE13,ATTRIBUTE14,ATTRIBUTE15,TAG,LEAF_NODE)
values ('XXHDNL_SHIPPABLE_POSTCODES','US','CF47 9','CF47 9','CF47 9','Y',
to_date('23-JUL-09','DD-MON-RR'),null,1090,to_date('23-JUL-09','DD-MON-RR'),
1090,47626,to_date('23-JUL-09','DD-MON-RR'),'US',0,3,null,null,null,null,nul
l,null,null,null,null,null,null,null,null,null,null,null,null,null,null);
I need to change the values in the field LOOKUP_CODE,MEANING,DESCRIPTION
there are 80 values it takes time to insert one one value each time.
The values are like this
DE1,DE1,DE1
D3,D3,D3
DE5,DE5,DE5
DE11,DE11,DE11
DE12,DE12,DE12
DE13,DE13DE13
How to do this?
Any help is highly appricatble
Thanks & regards
Srikkanth.M
Edited by: Srikkanth.M on Jan 14, 2011 6:04 PM

If the code is autonumeric ... then try
insert into FND_LOOKUP_VALUES (LOOKUP_TYPE,
                                                  LANGUAGE,
                                                  LOOKUP_CODE,
                                                  MEANING,
                                                  DESCRIPTION,
                                                  ENABLED_FLAG,
                                                  START_DATE_ACTIVE,
                                                  CREATED_BY,
                                                  CREATION_DATE,
                                                  LAST_UPDATED_BY,
                                                  LAST_UPDATE_LOGIN,
                                                  LAST_UPDATE_DATE,
                                                  SOURCE_LANG,
                                                  SECURITY_GROUP_ID,
                                                  VIEW_APPLICATION_ID
SELECT 'XXHDNL_SHIPPABLE_POSTCODES',
           'US',
           'DE' || level,
           'DE' || level,
           'DE' || level,
           'Y',
            to_date('23-JUL-09','DD-MON-RR'),
           1090,
           to_date('23-JUL-09','DD-MON-RR'),
           1090,
           47626,
           to_date('23-JUL-09','DD-MON-RR'),
           'US',
           0,
           3
from dual connect by level < 81

How to insert the data from XML to a table

Hi,
I'm using Oracle 10g Express Edition
I need help in How to insert the data from XML file into the table.
Below is the example i'm working on..
I have create ridb user with below mentioned privileges:
Account Status Locked Unlocked
Default Tablespace: USERS
Temporary Tablespace: TEMP
User Privileges :
Roles:
CONNECT
RESOURCE
Direct Grant System Privileges:
CREATE DATABASE LINK
CREATE MATERIALIZED VIEW
CREATE PROCEDURE
CREATE PUBLIC SYNONYM
CREATE ROLE
CREATE SEQUENCE
CREATE SYNONYM
CREATE TABLE
CREATE TRIGGER
CREATE TYPE
CREATE VIEW
& table is created TRIALZIPCODES below mentioned is the DDL:
CREATE TABLE TRIALZIPCODES
STATE_ABBR VARCHAR2(20) NOT NULL
, ZIP_CODE NUMBER(10, 0) NOT NULL
, ZIP_CODE_EXT VARCHAR2(20)
Below is the XML FILE: which is stored in C:\OracleProject Folder
File name: trial.xml
<?xml version="1.0" ?>
<metadata>
- <Zipcodes>
- <mappings Record="4">
<STATE_ABBREVIATION>CA</STATE_ABBREVIATION>
<ZIPCODE>94301</ZIPCODE>
</mappings>
- <mappings Record="5">
<STATE_ABBREVIATION>CO</STATE_ABBREVIATION>
<ZIPCODE>80323</ZIPCODE>
<ZIP_CODE_EXTN>9277</ZIP_CODE_EXTN>
</mappings>
</Zipcodes>
</metadata>
PL/SQL Procedure:which i'm trying to execute from SQLDeveloper
create or replace
PROCEDURE TRIAL AS
BEGIN
DECLARE
-- declare attributes
charString varchar2(80);
finalStr varchar2(4000) := null;
rowsp integer;
v_FileHandle UTL_FILE.FILE_TYPE;
l_context_handle dbms_xmlgen.ctxHandle;
insCtx DBMS_XMLStore.ctxType;
begin
-- DBMS_XMLGEN.setRowTag ( ctx IN ctxHandle, rowTag IN VARCHAR2);
-- DBMS_XMLGEN.setRowSetTag ( ctx IN ctxHandle, rowSetTag IN VARCHAR2);
-- the name of the table as specified in our DTD
DBMS_XMLGEN.SETROWSETTAG(l_context_handle,'zipcodes');
-- the name of the data set as specified in our DTD
DBMS_xmlgen.setRowTag(l_context_handle,'mappings');
-- for getting the output on the screen
dbms_output.enable(1000000);
-- open the XML document in read only mode
v_FileHandle := utl_file.fopen('c:/OracleProject','trial.xml', 'r');
loop
BEGIN
utl_file.get_line(v_FileHandle, charString);
exception
when no_data_found then
utl_file.fclose(v_FileHandle);
exit;
END;
dbms_output.put_line(charString);
if finalStr is not null then
finalStr := finalStr || charString;
else
finalStr := charString;
end if;
end loop;
-- for inserting the XML data into the table
insCtx := DBMS_XMLSTORE.NEWCONTEXT('RIDB.TRIALZIPCODES');
insCtx := DBMS_XMLSTORE.INSERTXML(insCtx, finalStr);
dbms_output.put_line('INSERT DONE '||TO_CHAR(rowsp));
DBMS_XMLStore.closeContext(insCtx);
END;
END TRIAL;
For the first time when i complied i got the errors as :
Procedure RIDB.PROCEDURE1@RIDB
Error(16,14): PLS-00201: identifier 'UTL_FILE' must be declared
Error(16,14): PL/SQL: Item ignored
Error(29,1): PLS-00320: the declaration of the type of this expression is incomplete or malformed
Error(29,1): PL/SQL: Statement ignored
Error(33,1): PL/SQL: Statement ignored
Error(33,19): PLS-00320: the declaration of the type of this expression is incomplete or malformed
Error(36,1): PL/SQL: Statement ignored
Error(36,17): PLS-00320: the declaration of the type of this expression is incomplete or malformed
So i logged in as sys & grant the permission to execute on UTL_FILE to ridb (user):
SQL Statement:
grant execute on utl_file to ridb
So, it got compiled successfully but when i execute it gives me error as:
Source does not have a runnable target.
What does this mean?
So I browse through forum & i got to know that i need to initial the UTL_FILE_DIR ="C:/OracleProject" in init.ora
So can i edit the init.ora with notepad.When i tried to do that it says permission denied
In my system it shows the init.ora file in path C:\oraclexe\app\oracle\product\10.2.0\server\config\scripts
but there is also other file initXETemp in the same path do i need to do the changes in it.
I have tried even editing the SPFILE as mentioned below:
C:\oraclexe\app\oracle\product\10.2.0\server\dbs\SPFILEEXE - I had edit this file using notepad & set the value of UTL_FILE_DIR ="C:/OracleProject". So next time when i restarted i'm unable to log on to the database.
So i had reinstall the software again.
Could you please let me know how to proceed..

hi,
I have created the directory from sys database
CREATE or replace DIRECTORY XML_DIR2 AS 'C:\OracleProject';
& grant read,write access to the user
grant read,write on directory XML_DIR2 to RIDB;
& i had change the tag name in the xml file as shown below:
<?xml version = '1.0'?>
<metadata>
<Zipcodes>
<mappings Record="4">
<STABBRE>CA</STABBRE>
<ZIPCODE>94301</ZIPCODE>
</mappings>
<mappings Record="5">
<STABBRE>CO</STABBRE>
<ZIPCODE>80323</ZIPCODE>
<ZIPCODEEXT>9277</ZIPCODEEXT>
</mappings>
</Zipcodes>
</metadata>
TRIALZIPCODE table as shown below:
CREATE TABLE "RIDB"."TRIALZIPCODE"
(     "STABBRE" VARCHAR2(20 BYTE),
     "ZIPCODE" NUMBER(*,6) NOT NULL ENABLE,
     "ZIPCODEEXT" NUMBER
) PCTFREE 10 PCTUSED 40 INITRANS 1 MAXTRANS 255 NOCOMPRESS LOGGING
STORAGE(INITIAL 65536 NEXT 1048576 MINEXTENTS 1 MAXEXTENTS 2147483645
PCTINCREASE 0 FREELISTS 1 FREELIST GROUPS 1 BUFFER_POOL DEFAULT)
TABLESPACE "USERS" ;
I have tried two methods as shown below:
Procedure 1:
create or replace
PROCEDURE TRIAL_V2 AS
BEGIN
DECLARE
-- declare attributes
charString varchar2(80);
finalStr varchar2(4000) := null;
rowsp integer;
v_FileHandle UTL_FILE.FILE_TYPE;
l_context_handle dbms_xmlgen.ctxHandle;
insCtx DBMS_XMLStore.ctxType;
cnt NUMBER;
xmldoc xmltype := xmltype( bfilename('XML_DIR2','trialxml.xml'), nls_charset_id('AL32UTF8') );
--XML_DIR VARCHAR2(40) := 'C:\\OracleProject';
BEGIN
insCtx := DBMS_XMLStore.newContext('DEV.TRIALZIPCODES');
DBMS_XMLStore.setUpdateColumn(insCtx, 'STABBRE');
DBMS_XMLStore.setUpdateColumn(insCtx, 'ZIPCODE');
DBMS_XMLStore.setUpdatecolumn(insCtx, 'ZIPCODEEXT');
DBMS_XMLStore.setRowTag(insCtx, 'mappings');
cnt := DBMS_XMLStore.insertXML(insCtx, xmldoc);
DBMS_XMLStore.closeContext(insCtx);
END;
Procedure 1 was compiled with out errors but when i execute i got the error as :
Source does not have a runnable target.
Procedure 2_
CREATE OR REPLACE PROCEDURE TRIAL_V3 AS
BEGIN
DECLARE
-- declare attributes
charString varchar2(80);
finalStr varchar2(4000) := null;
rowsp integer;
v_FileHandle UTL_FILE.FILE_TYPE;
l_context_handle dbms_xmlgen.ctxHandle;
insCtx DBMS_XMLStore.ctxType;
cnt NUMBER;
xmldoc xmltype := xmltype( bfilename('XML_DIR2','trialxml.xml'), nls_charset_id('AL32UTF8') );
--XML_DIR VARCHAR2(40) := 'C:\\OracleProject';
BEGIN
INSERT INTO trialzipcode (STABBRE, ZIPCODE, ZIPCODEEXT)
SELECT extractvalue(x.column_value, 'mappings/STABBRE'),
extractvalue(x.column_value, 'mappings/ZIPCODE'),
extractvalue(x.column_value, 'mappings/ZIPCODEEXT')
FROM TABLE(
XMLSequence(
EXTRACT(
xmltype( bfilename('XML_DIR2','trialxml.xml'), nls_charset_id('AL32UTF8') ),
'metadata/Zipcodes/mappings'
) x
END;
END TRIAL_V3;
Procedure 2 was complied without errors but when i execute i got the error as:
Connecting to the database RIDB.
ORA-22288: file or LOB operation FILEOPEN failed
The system cannot find the file specified.
ORA-06512: at "SYS.DBMS_LOB", line 523
ORA-06512: at "SYS.XMLTYPE", line 287
ORA-06512: at "RIDB.TRIAL_V3", line 12
ORA-06512: at line 2
Process exited.
Disconnecting from the database RIDB.
Could you please let me know how to proceed...

How to insert a dynamic image in a report

Hi,
I want to insert the image of a student in a report toghether with all other student's data. The image's file name is in a field of the students' table and the file is stored in a directory of the web application. I am using Visual studio 2010 and the reports are prepared with Crystal Reports 2008 (full product). At design time, when I try to insert an image on the report, it immediately asks for an image file on the computer, so I cant figure out how to insert an image whose path and file name come from a data source.
Thank you

Hi Don,
As I said, when I insert any field in the report, say for instance the Student ID, and then link it to a database field containing the name of the image file to display (I have to concatenate the path to this file name as well), it first shows the report with the Student ID. If I click on it, because of the hyperlink defined at design time, it opens the file (an image in this case) in Internet Explorer, not on the report.
The same happens if I put an image as an object on the report at design time. In this case as soon as I put the image object on the report it forces me to select an initial image to show on the report. Anyway, I define an hyperlink for this image, pointing it to the image file of the Student, using the database field containing the image file name. When I show the report I see the initial image I was forced to use and when I click it, the hyperlink takes me to the right student image, but even in this case it shows me the right image opening an Internet Explorer session and not on the report. On the report the initial image is still there and never changes.
What I actually need is a way to put the student's image on the report as soon as it shows the other student's data, as the name, age, ***, and so on, without having to click somewhere to show the student's image.
Thanks

How to insert a flying image in a video

How to insert flying images in a video...someone it's speaking in the left side and in the right side some flying pictures are coming, staying for 2-3 seconds one by one....some ideas???
Like the weather forecast...you have someone in the left side speaking and she is showing some images in the right side.
Please let me know if you know how it can be done this in after effects or with another video editor...
Thanks!!!

It can be done in either. There are 3 steps.
Learn about greenscreen (keying) including lighting, filming, best formats for video (the way they do it in the weather segment) or masking and roto.
learn about image editing including sizing images, color correcting, applying effects
learn about controlling motion and editing duration of stills in a NLE or After Effects
When you have a few of these basics down and have designed your production you then load up the video and the stills, key out the background or mask around your talent to separate the talent from the background, add your photos to the time line and animate their duration and position.
This is extremely basic stuff that can be accomplished in a NLE or in AE. You can basically reproduce just about any effect you've ever seen in a movie in AE with the right planning and plug-ins. You can do just about anything you've ever seen in a news broadcast in any modern NLE.

How to insert time

Similar Messages

Maybe you are looking for