How to know what causes SocketException to be thrown ?

Question

Hello Javatizers,
I use the following code to check if the socket connection is closed abnormally from the client or not.
           try {
                    .this.dos.write(m); //DataOutputStream
                } catch (SocketException se) {
                    String msg = se.getMessage();
                    if (msg != null && msg.contains("Connection reset")) {
                                 //handle here
                    } else {
                        se.printStackTrace();
                } catch (Exception otherExceptions) {  /*handle other exceptions*/ } My question is, can I depend on the exception message "Connection Reset" to check such case? Although it is working fine, but I think this is not a good approach checking the message contents !!, or is there any other way to know that the connection is reset? The doc says this exception is thrown to indicate that there is an error in the underlying protocol, such as a TCP error, but i think this is not enough !!
I hope I clarified my idea
Thanks

Answer 1

MohdSleem wrote:
Thanks for your reply
I am using this code into a network game server and there is a lot of possibilities of client shutdown (normal exit, internet went down, process killed,...etc), I use Runtime.getRuntime().addShutdownHook(....) on the client side to send a notification to the server that the client is existing, but the notification delivery is not guaranteed, I have no logical issues with the code above, but I ask to know if there is a better way to do it, I am sure it is a bad design to depend on the exception message :)Correct. It's usually bad.
I still don't get why it matters how or why the user got disconnected.