How to popup a page from a button not in a region position

Question

Hello.
I am using Apex 2.2.1. I have a form (not a report) on which I've placed a button that is positioned "among the items" as opposed to being placed in a specific region position.
When the button is clicked I would like to have another page popup. The problem is that I can get this to work only if the button is placed in a region position. With the button in a region position, I define the target to be a URL and then place a call to the popUp2 function, as in:
javascript:popUp2('f?p=&APP_ID.:32:&SESSION.::NO:::', 900, 700);
This works fine.
However, I need to position my button on the immediate right hand side of a form item. But when I create a button in such a position, I have no field in which to place the call to the popUp2() function. Instead, I have to create a "Branch to Page or URL" and then place my javascript call in the Branch field. Unfortunately, when I click the button, Apex wants to branch to page zero instead of the desired page. I saw that when I move the mouse over the button, Apex shows:
javascript: doSubmit('MY_BUTTON_REQUEST');
And, as mentioned, Apex tries to branch to page zero.
How does one call the popUp2() function from a button that is not placed in a region position?
Thank you for your help.
Elie

Answer 1

Hi Elie,
I had the same problem ... I only got it solved with creating a hidden item and adding the input-tag into the "Post Element Text" field.
Just have a look in the source code of your page, how a button is build and copy the necesaary code to the mentioned field. So you get a button with ApEx layout and can add your javascript call.
chrissy