How to Provide File Path in MII 12 to access file located in Network Path

Hi,
How can I locate a file which is placed Network Path?
Iam trying to access PDF file which is stored in Network Drive, I just want to open folder which contains all PDF files located in some Network Path on click of button.
I tried all possibilities like below:
window.open("file
\G:");
window.open("
SERVER-NAME
Folder Name");
But Iam unable to Fix this.
Please Help me in this regard
Regards,
Padma

Hi Rao,
this is less a MII than a browser or mapping problem.
You can access a local file in a browser like this:
window.open('file:///c:/folder/file.txt');
However, in case of MII local means local to the MII server. So in the above example the file is located on the c driver of the MII server.
If you want to access files on a network drive, the folders to the files should be mapped on the MII server so you are able to address them like they were local files.
I haven't tried to address network folders directly, because we are running MII on Unix.
Michael

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How to read data from a zipped MS Access file?

RPJ,
You do not need to use the Close Zip File.vi when you unzip a folder. This VI is used when you are creating a zip folder.
As for examples, I found a couple of ActiveX based MS Access examples. These programs look to be pretty basic. For more in depth example I would search Microsoft Developers Network
http://zone.ni.com/devzone/cda/epd/p/id/2188
http://zone.ni.com/devzone/cda/epd/p/id/1694
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National Instruments
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Ccm log access denied or invalid network path.

Hi
One of my system not able to install SCCM 2007 client. Getting below error when i drop ccr .
======>Begin Processing request: "I7M92P-7100726", machine name: "I7M92P-7100726"
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---> Warning: no remote client installation account found
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5 = "Access Denied"
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How to provide the user with a list of files to pick from...for downloading

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Hi Anoo,
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MissJavaa

You can't append multiple ObjectOutputStreams to the same file unless you know where one ends and the other starts and you use a new ObjectInputStream at each join. And even that mightn't work because of buffering. Keep the file open or start a new file.
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How do I use an external Monitor to access files on my iMac with a broken screen?

I have an 20 inch desktop iMac with a broken screen. It is the files on the computer that I wish to recover, after that, I can be on my merry way. Unfortunately, VileVault was on (Not my choice), and for some reason, when I target the disc image of the broken mac with a new one, ONE of the accounts "appears" to be completely empty. All of the accouts were running FileVault, but only one (mine) failed to be transferred because it is "empty". I refuse to believe that my files are actually all gone, because theoretically there should be nothing wrong with the CPU itself, just the screen.
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Does anyone have any ideas on how to 1. Get the monitor to simply show what's going on on the mac? or 2. Pull out my files through some other means?
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If you have a second Mac computer, you may want to try to copy over as many files you can. One way is to use target disk mode.
http://support.apple.com/kb/HT1661
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Hi,
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Wilson

I need help how to create menu function for link to access file and allow user to save the file when click on it.
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I measure a sine wave in LabView 6i. How can I write the datas automatically to an Acces-file, at the same time?
In my program, I managed it with Execute SQL.vi, I change a number in a SQL statement(String) -> after this I push start and then it writes the statement in the Access-file.
The problem is, it writes only one data per measurement in the file. How can I write all datas in the Access-file and measure the wave at the same time?
Thanks for help!
Attachments:
getwave.vi ‏49 KB

On the waveform palette, you will find a "to components" vi that you can break out the array of the waveform. You can then, using a for loop write all of the values from the waveform.
Better yet, there are examples in the database toolkit manual on pages 3-13 to 3-15 that deal with reading arrays (and even has a waveform example).
Good luck!

Please Help java.policy signedBy can't access file local

i create keystore and signjar in web applet
run tomcat access file in local but not acess file denied
i goto edit file java.policy
grant {
     permission java.security.AllPermission;
can access file
but put SignedBy cannot access file
grant SignedBy fuangchai{
     permission java.security.AllPermission;
Please help me example file keystore,applet.jar,java.policy
to signedby access file local in webapplet
env JDE 1.5 ,javascript yui 2.8 ,prototype js,tomcat6
File html
<object classid="clsid:8AD9C840-044E-11D1-B3E9-00805F499D93"
codebase="http://java.sun.com/update/1.5.0/jinstall-1_5-windows-i586.cab#Version=5,0,0,5"
width="1" height="1" >
<param name=code value="com.arg.aes.test.FileDirectoryBS.class" >
<param name=archive value="app.jar">
<param name=codebase value="." >
<param name="type" value="application/x-java-applet;version=1.5">
<param name="scriptable" value="true">
<param name="mayscript" value="true">
<param name="debug" value="false">
<comment>
<embed name="myApplet" id="myApplet"
type="application/x-java-applet;version=1.5"
code="com.arg.aes.test.FileDirectoryBS.class"
archive="app.jar"
java_codebase="."
width="1"
height="1"
scriptable="true"
mayscript="true"
pluginspage="http://java.sun.com/products/plugin/index.html#download">
<noembed>
</noembed>
</embed>
</comment>
</object>
<applet
code="com.arg.aes.test.FileDirectoryBS"
width="1"
height="1"
archive="app.jar"
name="myApplet"
codebase="."
MAYSCRIPT="true"
>
</applet>
javascript
initlistfile : function() {
          try
               var list = $("myApplet").initlistfileInDir();
               var jsondata = list.evalJSON();
               /*alert(jsondata.dirname);
               alert(jsondata.dirpath);
               alert(jsondata.listfile.length);*/
               initTableLeft(jsondata.listfile);
          catch(e)
               alert("Exception : access denied.");
               return;
import java.applet.Applet;
import java.io.File;
import java.security.Permission;
import java.security.PermissionCollection;
import java.security.Policy;
import java.security.ProtectionDomain;
import java.text.DecimalFormat;
import java.text.NumberFormat;
import java.util.ArrayList;
import java.util.Enumeration;
import java.util.List;
* @author fuangchai
public class FileDirectoryBS extends Applet{
public static File[] ROOTS = File.listRoots();
public static String HOME = System.getProperty("user.home");
public String listDir()
return JsonObj.makeTopDir((ROOTS.length > 0)?ROOTS : new Object[]{HOME});
public String initlistfileInDir()
return listfileInDir(null);
public String listfileInDir(String dirName)
if(null == dirName || dirName.equals(""))
System.out.println("root = " + ROOTS.length);
try {
dirName = (ROOTS.length > 0)?ROOTS[0].getPath():HOME;
catch (Exception e) {
e.printStackTrace();
return "";
System.out.println("#########################");
DirectoryDescImp obj = makeObjDir(dirName);
return (null == obj)?null:JsonObj.makeDir(obj);
public String listlinkInDir(String dirName)
if(null == dirName || dirName.equals(""))
System.out.println("root = " + ROOTS.length);
try {
dirName = (ROOTS.length > 0)?ROOTS[0].getPath():HOME;
catch (Exception e) {
e.printStackTrace();
return "";
System.out.println("#listlinkInDir#");
try {
File obj = new File(dirName);
return (null == obj)?null:JsonObj.makelinkDir(obj.getName(),obj.getPath());
} catch (Exception e) {
System.out.println("I can't access a file here! Access Denied!");
e.printStackTrace();
return null;
public boolean isEnc(File f)
//TODO
return false;
public DirectoryDescImp makeObjDir(String dirName)
System.out.println("dirName = " + dirName);
try{
File dir = new File(dirName);
String[] entries = dir.list();
if(null == dir || null == entries || entries.length <= 0)
System.out.println("Data is null or not obj." );
return null;
System.out.println("Dir List = " + dir.list().length);
System.out.println("Dir Name = " + dir.getName());
System.out.println("Dir Path = " + dir.getPath());
DirectoryDescImp dirDesc = new DirectoryDescImp();
dirDesc.setDirName(dir.getName());
dirDesc.setDirPath(dir.getPath());
List<FileDescImp> list = new ArrayList<FileDescImp>();
for(int i=0; i < entries.length; i++) {
File f = new File(dir, entries);
FileDescImp fDesc = new FileDescImp();
fDesc.setFile(f);
fDesc.setFileEncrept(isEnc(f));
list.add(fDesc);
dirDesc.setListfile(list);
return dirDesc;
catch(Exception e){
System.out.println("I can't access a file here! Access Denied!");
e.printStackTrace();
return null;
Thank you
Fuangchai Jum
Mail [email protected]
Edited by: prositron on Jan 13, 2010 7:35 AM

OK,
Let's say I have to intialize Environment, and call method initEnvironment() in Applet's init(). Environment class:
class Environment
     private KeyStore keyStore;
     private Enumeration<String> aliases;
     public void initEnvironment() {
          Security.addProvider(new sun.security.mscapi.SunMSCAPI());
          keyStore = KeyStore.getInstance("Windows-MY");
          keyStore.load(null);
          aliases = keyStore.aliases();
}Applet is signed, I trust signer.
Since Applet is signed I'm able to overwrite existing .java.policy under user.home.
This doesn't work if I don't have .java.policy:
grant {
permission java.security.SecurityPermission "insertProvider.SunMSCAPI";
permission java.security.SecurityPermission "authProvider.SunMSCAPI";
permission java.util.PropertyPermission "jsr105Provider", "read";
permission java.util.PropertyPermission "com.sun.xml.internal.ws.api.pipe.Fiber.serialize", "read";
permission java.lang.RuntimePermission "setContextClassLoader";
permission java.util.PropertyPermission "com.sun.xml.internal.ws.api.streaming.XMLStreamWriterFactory.noPool", "read";
permission java.lang.RuntimePermission "accessDeclaredMembers";
permission java.lang.reflect.ReflectPermission "suppressAccessChecks";
permission java.lang.RuntimePermission "accessClassInPackage.com.sun.xml.internal.ws.fault";
permission java.util.PropertyPermission "com.sun.xml.internal.ws.api.streaming.XMLStreamWriterFactory.woodstox", "read";
};P.S.
Does it make sense to be able to make changes to file system and not be able to make actions from above policy?!?!

Reflection - How to provide qualified path to class?

Hello folks,
I am writing the application in which user will be able examine any java class at any mapped drive at his PC.
The snipplet is as follows:
import java.lang.reflect.*;
public class ClassInfo {
public static void main( String[] args ) throws Exception {
Class theClass = Class.forName(args[0]);
System.out.println("Class Name: " + theClass.getName());
//Other methods go here
(In GUI application I will provide a FileChooser, of course.)
It works perfectly well as long as the class I want to examine is in the same folder. Example below.
C:\MyFolder>java ClassInfo MyClass
Class Name: MyClass
But when I try to provide the full path to the class outside of that folder - it did not work at all. I am getting ClassNotFound exception. I tried every possible way, such as "C:\\myFolder2\\myClass2� and
"myFolder2.myClass2", etc.
Does someone know how to circumvent this obstacle?
Many thanks at advance.
Vlad

Thank you very much, guys, for your responses. I figured it out. Hopefully, my code will be useful for someone else.
The only limitation is: In the current version it does not handles packages, in other worlds, if the class is a part of a package, such as
package hello;
public class HelloFromHell{
//the rest of the class
I am getting error messge:
Exception in thread "main" java.lang.NoClassDefFoundError: HelloFromHell (wrong name: hello/HelloFromHell) It expects to find the class name in the directory named "hello", which is a package name.
Vlad
import java.io.*;
import java.lang.reflect.*;
import java.net.*;
import javax.swing.*;
public class ClassInfo {
static void displayClassInfo(File file) {
//Get Directory info
File directory = file.getParentFile();
//Get Class name without ".class" ext
String className = file.getName().substring(0,file.getName().length() -".class".length());
try {
//Create the URLClassLoader
URL[] theURL = {directory.toURL()};
URLClassLoader loader1 = new URLClassLoader(theURL);
//Pass class name loader to the forName method
Class theClass = Class.forName(className, true, loader1);
System.out.println("Directory: " + directory.toURL());
System.out.println("Class: " + theClass.getName());
Method[] theMethods = theClass.getDeclaredMethods();
System.out.println("Methods:");
System.out.println("-------");
for (int i = 0; i < theMethods.length; i++) {
System.out.println("Name: " + theMethods.getName());
System.out.println();
//Other reflection methods go here as needed
catch (ClassNotFoundException cnfe) {
System.err.println(cnfe);
System.err.flush();
catch (java.net.MalformedURLException mue) {
System.err.println(mue);
System.err.flush();
//Helper method to prevent user from selecting anything but java classes
static boolean isClass(String fileName) {
if (fileName.endsWith(".class")) {
return true;
return false;
//Method to call JFileChooser dialog thus preventing users from typing
public static void main(String[] args) {
// display a file dialog to the user for file selection
JFileChooser fileChooser = new JFileChooser(System.getProperty("user.dir"));
if (JFileChooser.APPROVE_OPTION == fileChooser.showOpenDialog(new JFrame())) {
if ( (fileChooser.getSelectedFile().getName() != null) &&
(isClass(fileChooser.getSelectedFile().getName()))) {
displayClassInfo(fileChooser.getSelectedFile());
else {
//Handle errors gracefully
System.out.println("No file was selected or file is not a java class.");
System.exit(0);

How to Provide search Help for files on Application Server

Hi Guys,
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Thanks & Regards.
Harish.

Hi Harish,
Use the following code,
tables sxpgcotabe.
data: lt_execprot LIKE btcxpm OCCURS 0 WITH HEADER LINE,
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SELECT SINGLE *
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           AND opsystem = sy-opsys.
IF sy-subrc <> 0.
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ENDIF.
sxpgcotabe-parameters = p_filepath. --> provide the directory path.
CALL FUNCTION 'SXPG_COMMAND_EXECUTE'
       EXPORTING
            commandname                   = sxpgcotabe-name
            additional_parameters         = sxpgcotabe-parameters
            operatingsystem               = sxpgcotabe-opsystem
       TABLES
            exec_protocol                 = lt_execprot
       EXCEPTIONS
            no_permission                 = 1
            command_not_found             = 2
            parameters_too_long           = 3
            security_risk                 = 4
            wrong_check_call_interface    = 5
            program_start_error           = 6
            program_termination_error     = 7
            x_error                       = 8
            parameter_expected            = 9
            too_many_parameters           = 10
            illegal_command               = 11
            wrong_asynchronous_parameters = 12
            cant_enq_tbtco_entry          = 13
            jobcount_generation_error     = 14
            OTHERS                        = 15.
IF sy-subrc <> 0.
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ENDIF.
Loop round the directory list, split each line up into a line table
and get the last data for each line, should be the filename
Then build the dirlist.
REFRESH t_dirlist.
LOOP AT lt_execprot.
    REFRESH t_dirline.
    SPLIT lt_execprot-message AT space INTO TABLE t_dirline.
    DESCRIBE TABLE t_dirline LINES w_nolines.
    READ TABLE t_dirline INDEX w_nolines.
    MOVE t_dirline-data TO t_dirlist-filename.
    APPEND t_dirlist.
ENDLOOP.
Here you will get all the files in the directory mentioned in Application server.
For displaying them as a Search help use the FM '/BMC/ZPOPUP_GET_VALUE'
Pass the Internal table to this FM.
Regards,
Paul.

How do I find out the exact path of each and every file that LabVIEW finds and loads into memory for a given top level vi?

How do I find out the exact path of each and every file that LabVIEW finds and loads into memory for a given top level vi? There is probably a trivial, easy way to get this info, but I have not yet found it! Thanks..

Or if you want to grab all the paths programatically, try the attached VI.
Open the top level that you want all the paths from and close all others, then open the
attached and run it. It will return an array of all the VIs that the VI
in question uses, including vi.lib VIs. You can filter these as well if
you like.
Ed
Message Edited by Ed Dickens on 08-01-2005 07:01 PM
Ed Dickens - Certified LabVIEW Architect - DISTek Integration, Inc. - NI Certified Alliance Partner
Using the Abort button to stop your VI is like using a tree to stop your car. It works, but there may be consequences.
Attachments:
Get all paths.vi ‏29 KB

How to run a jar file which needs another jar to be in the class path

Hi,
I need to execute a jar, which needs another jar to be in the classpath.
If I run like
java -classpath <jar1 name> -jar <main jar>
It is giving classnotfoundexception, where as the class is available in the <jar1 name>.
so, currently I am doing like this
In the manifest file i have given like
Main-Class: <class name>
Class-Path: <jar name> <jar name2>
then it is running fine. But, if I want to change the jar location again I need to changed the manifest file.
Is there any way to do this? Pls help me.

How about
java -cp jar1.jar;jar2.jar com.acme.MainClass
You won't need to worry about the manifest file after that and you can make a bat files (or .sh file in *nix) for it.

How to get the full path instead of just the file name, in �FileChooser� ?

In the FileChooserDemo example :
In the statement : log.append("Saving: " + file.getName() + "." + newline);
�file.getName()� returns the �file name�.
My question is : How to get the full path instead of just the file name,
e.g. C:/xdirectory/ydirectory/abc.gif instead of just abc.gif
import java.io.*;
import java.awt.*;
import java.awt.event.*;
import javax.swing.*;
import javax.swing.filechooser.*;
public class FileChooserDemo extends JFrame {
static private final String newline = "\n";
public FileChooserDemo() {
super("FileChooserDemo");
//Create the log first, because the action listeners
//need to refer to it.
final JTextArea log = new JTextArea(5,20);
log.setMargin(new Insets(5,5,5,5));
log.setEditable(false);
JScrollPane logScrollPane = new JScrollPane(log);
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final JFileChooser fc = new JFileChooser();
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JButton openButton = new JButton("Open a File...", openIcon);
openButton.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent e) {
int returnVal = fc.showOpenDialog(FileChooserDemo.this);
if (returnVal == JFileChooser.APPROVE_OPTION) {
File file = fc.getSelectedFile();
//this is where a real application would open the file.
log.append("Opening: " + file.getName() + "." + newline);
} else {
log.append("Open command cancelled by user." + newline);
//Create the save button
ImageIcon saveIcon = new ImageIcon("images/save.gif");
JButton saveButton = new JButton("Save a File...", saveIcon);
saveButton.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent e) {
int returnVal = fc.showSaveDialog(FileChooserDemo.this);
if (returnVal == JFileChooser.APPROVE_OPTION) {
File file = fc.getSelectedFile();
//this is where a real application would save the file.
log.append("Saving: " + file.getName() + "." + newline);
} else {
log.append("Save command cancelled by user." + newline);
//For layout purposes, put the buttons in a separate panel
JPanel buttonPanel = new JPanel();
buttonPanel.add(openButton);
buttonPanel.add(saveButton);
//Explicitly set the focus sequence.
openButton.setNextFocusableComponent(saveButton);
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Container contentPane = getContentPane();
contentPane.add(buttonPanel, BorderLayout.NORTH);
contentPane.add(logScrollPane, BorderLayout.CENTER);
public static void main(String[] args) {
JFrame frame = new FileChooserDemo();
frame.addWindowListener(new WindowAdapter() {
public void windowClosing(WindowEvent e) {
System.exit(0);
frame.pack();
frame.setVisible(true);

simply use file.getPath()
That should do it!Thank you !
It takes care of the problem !!

How to provide date and time stamp to the extracted file.

I 'm downloading data from DB to Flat file using GUI_DOWLOAD. whenever it is executed it is creating with a file name.
if i rerun the program the file is overwriting with the same name.
now based on the requirement how many times i executed, that many times file should be individually created and should be added with date and time stamp.
like
if when i executed at the very first time it should saved with filename, date and time.
say "Address.txt 04/05/2007 07:55:10"
When i executed it for second time it doesn't overwrite the file.
it should create a new file.
like "Address.txt 04/05/2007 07:59:20".
Please guide me the way if possible code.
Thanks in advance.

Hi Vamsi,
               Use FM 'F4_PROGRAM' to take file from the user .
In this case user will enter the file name. u can append date & time to that file path.
Refer this code.
CALL FUNCTION 'F4_FILENAME'
    EXPORTING
      PROGRAM_NAME = SY-REPID
      DYNPRO_NUMBER = SYST-DYNNR
    IMPORTING
      FILE_NAME     = P_P_FILE.
concatenate P_FILE '04/05/2007 07:59:20' into V_FILE.
CALL FUNCTION 'GUI_DOWNLOAD'
    EXPORTING
      filename                        = v_file
     filetype                        = 'ASC'
      write_field_separator           = 'X'
    TABLES
      data_tab                        = i_tab
IF sy-subrc <> 0.
MESSAGE ID SY-MSGID TYPE SY-MSGTY NUMBER SY-MSGNO
        WITH SY-MSGV1 SY-MSGV2 SY-MSGV3 SY-MSGV4.
ENDIF.
IF sy-subrc = 0.
    MESSAGE i002.
ENDIF.
Reward points if helpful.
Regards,
Hemant.

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