How to quickly find the difference of two version of RPD?

Hi all,
Does anyone have good idea about quickly finding the difference of two versions of RPD in the project?
Regards,
Anne

This might be of help to you
http://varanasisaichand.blogspot.com/2010/03/how-to-merge-two-repositories.html
http://www.rittmanmead.com/2010/07/obiee-11gr1-incremental-patches-to-the-rpd/
Cheers,
KK
Edited by: Kranthi.K on Dec 7, 2011 9:41 PM

Similar Messages

How to do find the difference between two time stamps

Hi all,
i have a table with 2 columns called GMT time and Local time . so i need to find difference between these two time stamps.
i tried like this
select to_date(GMT_TIME,'yyyy-mm-dd hh24:hi:ss')-to_date(LOCAL_TIME,'yyyy-mm-dd hh24:hi:ss') from date_table
the result is coming as follows ..
0.291666666667
i did not under stand the out put.
In my table GMT_TIME= 2011-06-26 00:00:00 and LOCAL_TIME=2011-06-25 17:00:00 ..
please help me how to get exact hours between two dates ..
Thanks
Sreedhar

Hi Sreedhar,
Your output (0.2916666) has the unit day.
You should multiply with 24 to get the unit hour.
select ( to_date(GMT_TIME,'yyyy-mm-dd hh24:hi:ss')-to_date(LOCAL_TIME,'yyyy-mm-dd hh24:hi:ss') ) * 24 from date_table;Rgds,
Tycho

Find the difference between two columns in an ssrs matrix ? MSCRM

Hi All,
I am working in reporting part of our project (On-line MSCRM 2013) & in reporting services.
I am trying to create report using fetch xml based. Below is the snap what we required the result.
Kindly help me, how to get the difference in both column. (Its a matrix table where year is grouped).
We need difference between both year Like (Plan Revenue of 2013 & Plan Revenue of 2014 difference in Plan Revenue Diff section) and same for Actual
Revenue.
https://social.microsoft.com/Forums/en-US/054d5ca4-0d38-4dc6-84a8-88866cc228fe/find-the-difference-between-two-columns-in-an-ssrs-matrix-mscrm?forum=crmdevelopment
Thanks,
Mohammad Sharique

Hi Bro,
I used parametrized option for year and done the report,Currently we are getting values in Difference column now i want to show
that value in percentage. How can we show the percentage based on that value. Means i want to show the Difference in Percentage.
Kindly help me i tried but getting some issue. Below i am mentioning the code and snap with result.
Below expression using to showing Plan Revenue in Percentage for year.
=
Sum(IIF(Fields!new_year.Value =Parameters!StartYear.Value,cdec(Fields!new_planrevenueValue.Value/1000), cdec(0)))
- Sum(IIF(Fields!new_year.Value =Parameters!EndYear.Value,cdec(Fields!new_planrevenueValue.Value/1000), cdec(0)))
/IIF(Sum(IIF(Fields!new_year.Value = Parameters!StartYear.Value,cdec(Fields!new_planrevenueValue.Value/1000), cdec(0)))>0,
(Sum(IIF(Fields!new_year.Value = Parameters!StartYear.Value,cdec(Fields!new_planrevenueValue.Value/1000), cdec(0))))
,1)
)*100))
Result issue is as below in snap with highlighted in red colour.
Kindly help me on this issue also :)

Need to find the Difference between two table

Hello ,
I have stucked in program as below scenario:-
I have two tables of huge data of same structure in a same schema.I need to find the difference exact values in tables.
By using MINUS we can find the difference between two table ,i need to find the what exact difference in the there values with colunm and value at that column.
Example TableA
Col1 col2 col3 col4 col5.... col50
10 ABC 2001 EE 444 TT
40 XYZ 3002 RR 445 TT3
80 DEF 6005 YY 446 YY8
TableB
Col1 col2 col3 col4 col5.... col50
10 ABC 2001 EE 444 TT
40 XYZ 3002 RR 445 TT3
81 DEF 6005 Yu 447 YY8
I need to the out put like this :-
The Diffence between two table is
TableA.COL1=80 TableB.Col1=81, Different
TableA.Col4=YY TableB.col4=Yu,Different
TableA.Col5=446TableB.col5=447,Different
Please suggest me to write the pl/sql program for the same
thanx in advance
KK

Thanx friends for all your efforts
I have a sample code for the same,this will compare the two tables for single row in each table .
what r the modification needed for the multiple rows of values in the two tables??
Please suggest!!
CREATE OR REPLACE PROCEDURE test_compare
IS
TYPE t_col
IS
TABLE OF VARCHAR2 (30)
INDEX BY PLS_INTEGER;
l_col t_col;
j NUMBER := 0;
l_sql VARCHAR2 (2000);
col1 VARCHAR2 (30);
col2 VARCHAR2 (30);
val1 NUMBER;
val2 NUMBER;
status VARCHAR2 (30);
CURSOR c1
IS
SELECT column_id, column_name
FROM all_tab_columns
WHERE table_name = 'TEST1';
BEGIN
FOR i IN c1
LOOP
j := j + 1;
l_col (j) := i.column_name;
END LOOP;
FOR k IN 1 .. j
LOOP
l_sql :=
'SELECT '
|| ''''
|| l_col (k)
|| ''''
|| ', '
|| 'TEST2.'
|| l_col (k)
|| ', '
|| ''''
|| l_col (k)
|| ''''
|| ', '
|| 'TEST1.'
|| l_col (k )
|| ', '
|| 'DECODE(TEST2.'
|| l_col (k)
|| ' -TEST1.'
|| l_col (k)
|| ', 0, ''NO CHANGE'', ''CHANGED'') FROM TEST2, TEST1';
EXECUTE IMMEDIATE l_sql INTO col1, val1,col2, val2, status;
IF status = 'CHANGED'
THEN
DBMS_OUTPUT.put_line( 'TEST2.'
|| col1
|| '='
|| val1
|| ', TEST1.'
|| col2
|| '='
|| val2
|| ', '
|| status);
END IF;
END LOOP;
EXCEPTION
WHEN OTHERS
THEN
DBMS_OUTPUT.put_line ('Error:- ' || SQLERRM);
END;
/

Find the difference between two internal table

how can i see the difference between two interal tables?
The requirement is as follows
1. We have a transparent table, which stores the employee data with EMP ID as key.
2. We load the transp table data into a interal table (B).
3. We get data from legecy system as file and it gets loaded into another internal table (A) (this also has the same EMP ID key and this will have latest addition/update to those emplyees).
Now we need to seperate out these data into three interal table Inserted (I), Deleted (D) and Updated (U).
We want to do followign things
I = A - B
D = B - A
Both A and B will have around 40k records. Hence we are trying to avoid the looping.
Please suggest the best option for us.
Thank you in advance.
Raghavendra

>
RAGHAV URAL wrote:
> how can i see the difference between two interal tables?
> The requirement is as follows
>
> 1. We have a transparent table, which stores the employee data with EMP ID as key.
> 2. We load the transp table data into a interal table (B).
> 3. We get data from legecy system as file and it gets loaded into another internal table (A) (this also has the same EMP ID key and this will have latest addition/update to those emplyees).
>
> Now we need to seperate out these data into three interal table Inserted (I), Deleted (D) and Updated (U).
>
> We want to do followign things
> I = A - B
> D = B - A
>
> Both A and B will have around 40k records. Hence we are trying to avoid the looping.
>
> Please suggest the best option for us.
>
> Thank you in advance.
> Raghavendra
Hi Raghavendra,
Currently as of my knowledge, these operations are only possible through LOOPs. But LOOPign can be really fast here if you properly utilize the SORTING, READ with BINARY SEARCH and FIELD-SYMBOLS usage. I would say:-
Steps for Insert:-
SORT: A, B.
LOOP AT A ASSIGNING <WA_A>.
READ TABLE B WITH TABLE KEY key = <WA_A>-key BINARY SEARCH.
IF SY-SUBRC NE 0.
APPEND <WA_A> TO I.
ENDIF.
ENDLOOP.
Steps for Delete:-
SORT: A, B.
LOOP AT B ASSIGNING <WA_B>.
READ TABLE A WITH TABLE KEY key = <WA_B>-key BINARY SEARCH.
IF SY-SUBRC NE 0.
APPEND <WA_B> TO D.
ENDIF.
ENDLOOP.
Regards,
Ravi.

Extract Time from date and Time and Need XLMOD Funtion to find the Difference between Two Time.

X6 = "1/5/15 5:16 AM" & NOW ....................difference by Only Time
not date
X6 date and Time will be changing, Its not Constant
Dim myDateTime As DateTime = X6
            Dim myDate As String = myDateTime.ToString("dd/MM/yy")
            Dim myTime As String = myDateTime.ToString("hh:mm tt")
            Dim myDateTime1 As DateTime = Now
            Dim myDate1 As String = myDateTime1.ToString("dd/MM/yy")
            Dim myTime1 As String = myDateTime1.ToString("hh:mm tt")
Need to use this function to find the Difference between Two Time. due to 12:00 AM isuue
Function XLMod(a, b)
    ' This replicates the Excel MOD function
    XLMod = a - b * Int(a / b)
End Function
Output Required
dim dd = XLMod(myTime - myTime1)
Problem is myTime & myTime1 is String Need to convert them into Time, Later use XLMOD Funtion.

Induhar,
As an addendum to this, I thought I'd add this in also: If you have two valid DateTime objects you might consider using a class which I put together a few years ago
shown on a page of my website here.
To use it, just instantiate with two DateTime objects (order doesn't matter, it'll figure it out) and you'll then have access to the public properties. For this example, I'm just showing the .ToString method:
Option Strict On
Option Explicit On
Option Infer Off
Public Class Form1
Private Sub Form1_Load(ByVal sender As System.Object, _
ByVal e As System.EventArgs) _
Handles MyBase.Load
Dim date1 As DateTime = Now
Dim date2 As DateTime = #1/1/1970 2:35:00 PM#
Dim howOld As New Age(date1, date2)
MessageBox.Show(howOld.ToString, "Age")
Stop
End Sub
End Class
I hope that helps, if not now then maybe at some point in the future. :)
Still lost in code, just at a little higher level.
Thanx frank, can use this in Future....

Function Module to find the Difference between two times.

Hi All,
Wud you plz let me know the Function Module to find the Difference between two times.
Input Time1( Hours:Minutes) Time2 ( Hours:Minutes)
Need Output in Hours:Minutes only . ( No seconds Needed )
Ex :
Input :
       06:00 to 18:00 Output : 12:00
and 20:00 to 06:00 Output: 10:00 with +ve sign only. No -ve sign.
Thanks,
N.L.Narayana

check this .
data : p_timel like sy-uzeit,
       p_timeh like sy-uzeit,
       diff like sy-uzeit,
       di(8) type c .
       p_timel = '200000'.
       p_timeh = '060000'.
       diff = p_timeh - p_timel.
       concatenate diff+0(2) ':' diff+2(2) into di.
       write:/ di.
also check for this.
       p_timel = '060000'.
       p_timeh = '180000'.
see if this can be implemented in ur code .
or else u can try with Fm L_TO_TIME_DIFF passing startdate enddate starttime endtime with UOM as MIN
hope this helps regards,
vijay

How do you find the difference in no. of days between 2 dates?

How do you find the difference in no. of days between 2 dates ?

There are 2 way to solve this: using java.util.GregorianCalendar or java.util.Date (like jesper1 suggested), depending what kind of solution You need:
        GregorianCalendar gc1 = new GregorianCalendar(2001, 01, 01, 23, 00, 00);
        GregorianCalendar gc2 = new GregorianCalendar(2001, 01, 03, 10, 00, 00);
        // 1st way using GregorianCalendar
        int diff1 = gc1.get(GregorianCalendar.DATE) - gc2.get(GregorianCalendar.DATE);
        System.out.println("Differnce: " + diff1);
        // 2nd way using Date
        int diff2 = (int)(gc1.getTime().getTime() - gc2.getTime().getTime()) / (24 * 60 * 60 * 1000);
        System.out.println("Differnce: " + diff2);Note: There are 2 days between the given dates, but exactly 1 day and 11 hours.
The first solution returns "-2", the second returns "-1".
(... and a 4th posting also won't help ...)

Find the difference in Two Tabels in two different schema?

Hello Gurus,
In DB which have millions of records -
I have a Tabel A under Schema A and i have another Tabel B under Schema B and i have to pick the refrence from Tabel C under Schedma B altough my DB is same. Both of the tables (Table A and Table B) have exatly the same structure in both the schema and when i tried finding the difference like -
Find the refrence from Table C and pick the values which are in Tabel A under Schema A but which are not present in the Tabel B under Schema B .
I have to compare each and ever field value which is present under all of the columns under Table A to ever field value which is present under all of the columns under Table B.
then wrote the following query-
SELECT * FROM
SchemaA.Table A t1,SchemaB.Table C t2
WHERE t1.SV_ID = t2.SV_ID order by t1.SV_ID
Minus
Select * from SchemaB.TableB order by SV_ID
Then this query is not working. And display the following error -
"query block has incorrect number of result columns"
Even both of the tables have the same column's and same structure.
Kindly help me .
Looking forward for some guidance -
Thanks in advance.

1-There are some 70 Columns in both of the tables so thats why i don't want to use the query based on columns as it will involve writing all of the columns.
2- By using the query something like -
select <column_name(s)> from table1
minus
select <column_name(s)> from table2, table1
where <condition>
It is throwing the error -ORA-01789: query block has incorrect number of result columns
3- Using the query
SELECT t1.*
FROM SchemaA.TableA t1,SchemaB.TableC t2
WHERE t1.SV_ID = t2.SV_ID
MINUS
SELECT t3.*
FROM SchemaB.TableB t3
order by SV_ID
It gives me the reuslt but when i corss check them individually in both of the tables then there is no difference.
4- SELECT t1.* FROM
SchemaA.Table A t1,SchemaB.Table C t2
WHERE t1.SV_ID = t2.SV_ID order by t1.SV_ID
Minus
Select * from SchemaB.TableB order by SV_ID
Query is not working.
Kindly help me to find the difference between two tables , column by column based on the condition both of the tables have the same SV_ID.

How to find the difference of two columns in deski

Hi Everyone,
I have a deski report which is build from a single query. The report contains two tables.
Table-1:MTK Loc
           MTKnet
Table-2:WTK Loc
            WTKnet
Now i need to find the difference of the columns WTKnet and MTKnet.
These two are report level variables.Their definitins are as below:
MTKnet:=Sum((<Fees Collected by Per Collected>) In Body) ForEach <vMTKLocation>
WTKnet:=Sum((<Fees Collected by Per Collected>) In Body) ForEach <vWTKLocation>
Where <Fees Collected by Per Collected> is universe variable.
Please help...
Thanks in Advance......

Hi Bol,
As I understand you are taking MTK_Loc and WTK_Loc together in the report which have common values under Fees Collected by Per Collected column.
Please follow the steps mentioned below:
1. Calculate the Variables MTK_Net as
       =Sum(<Fees>) IN <MTK_Loc>
2. Calculate the Variables WTK_Net as
       =Sum(<Fees>) IN <WTK_Loc>
3. You will get the values based on the Locations MTK_Loc and WTK_Loc .
You are using combination of values for MTK_Loc and WTK_Loc hence you will get the variable values in combination.
Insert new column right to the WTK_Net and write the formula name it Variance.
=<MTK_Net>- <WTK_Net>
The values look like :
MTK_Loc      WTK_Loc             MTK_Net                 WTK_Net             Variance
Chicago           Chicago                16,696,274.43      157,168.26            16,539,106.17
Chicago           Madison               16,696,274.43       274,396.12            16,421,878.31
Chicago           Milvaki                 16,696,274.43       16,622,870.97       73,403.46
Chicago           Pennsylvania        16,696,274.43        4,299.35               16,691,975.08
Chicago           Waukesha             16,696,274.43        22,067.08             16,674,207.35
Here you will see values for MTK_Net are repeated because these are based on the MTK_Loc which is same for all rows i.e. Chicago , same is the case with remaining values of MTK_Loc.
We can not calculate variabnce based on the values like Canada,Pennsylvania for all values as these values come in combination of each other and as these are all connected columns WEBI groups Measure data based on the Dimension and variable columns associated with it.
MTK_Loc   WTK_Loc          MTK_Net         WTK_Net          Variance.
Chicago        Chicago           16696274.43        157168.26           16539106.17
However you can compare the values based on the values as :
1. Drag and Drop MTK_Loc and MTK_Loc separately on the report.
2. Drag and Drop WTK_Loc and WTK_Loc separately and put it on the report, Connect it to the columns MTK_Loc and MTK_Loc columns already dragged. Then you can compare the values
MTK_Loc                MTK_Net                         WTK_LOC                    WTK_Net
Chicago                    16,696,274.43                 Chicago                       157,168.26
Madison                   315,705.91                       Madison                      274,396.12
Manitowoc              362,632.50                        Manitowoc                  359,978.50
Milvaki                    54,172.84                          Milvaki                       16,622,870.97
Pennsylvania             2,966.56                           Pennsylvania               4,299.35
Waukesha                 9,028.03                          Waukesha                      22,067.08
Here I unchecked the option avoid duplicate row aggregation (select table-> format table) thatu2019s why it is showing all values as a sum of all MTK_Net and WTK_Net values corresponding to Location values..
Here we are using MTK_Loc and WTK_Loc separately and not connected because though values seems same but they are used in combination ( Chicago, Pennsylvania) in 2 separate tables in DB hence we canu2019t synchronize them by liking these 2 location columns using 2 data providers.
I Hope this is what you want....
Thanks....
Pratik

How can I find the maximum of two enum values?

I have a set of enum values (let's call then ONE, TWO, THREE.....). I want to find the larger of two of them. But max(ONE,THREE) gives a compile error as MAX isn't defined for type-safe enums. Fair enough.
I also agree that one shouldn't be able to use arithmetic functions on enums.
But as Enum implements Comparable, one can write a function which implements max and min, rather inefficiently I assume.
Is there a better way of getting the max/min of an enum? And if not, can the Java team be persuaded to implement it?

I have a set of enum values (let's call then ONE, TWO, THREE.....). I want to find the larger of two of them. But max(ONE,THREE) gives a compile error as MAX isn't defined for type-safe enums. Fair enough.
I also agree that one shouldn't be able to use arithmetic functions on enums.
But as Enum implements Comparable, one can write a function which implements max and min, rather inefficiently I assume.
Is there a better way of getting the max/min of an enum? And if not, can the Java team be persuaded to implement it?
The first place you should look for ANY basic question about Java classes is the documentation.
http://docs.oracle.com/javase/7/docs/api/java/lang/Enum.html#compareTo(E)
Why do you need a MAX method? You said you are only comparing TWO objects and you also say you know that 'Enum implements Comparable.
So just compare the two enums. The Enum class supports the 'compareTo(E o)' method as the doc API shows.

Find the difference between two dates for the specific month and year

Hi,
I have two dates, start date is 30/12/2012 and end date is 04/01/2013. Using datediff I found the difference of days between two dates. But I find the no of days in January 2013. ie output is 4 instead of 6. I input month and year to find the no of days
for that date. In this case I input Jan 2013. How can I sql this ?

I don't understand how most of the answers provided here not analytically solving the problem with many cases possible.
First let me understand you:
You have 2 dates range and you want to calculate day range for specific month and year between the original date range.
declare @for_month int = 1 --January
declare @for_year int = 2013
declare @StartDate date = '2012-12-20'
declare @EndDate date = '2013-01-04'
SELECT
CASE
WHEN (DATEPART(MONTH, @StartDate) = @for_month and DATEPART(MONTH, @EndDate) = @for_month) and ((DATEPART(YEAR, @StartDate) = @for_year or DATEPART(YEAR, @EndDate) = @for_year)) THEN
DATEDIFF(DAY, @StartDate,@EndDate)
WHEN (@StartDate < cast(CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) and (@EndDate between (cast(CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) and (cast(DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) + 1, 0)) as date))) THEN
DATEDIFF(DAY, DATEADD(MONTH, DATEDIFF(MONTH, -1, @EndDate)-1, 0),@EndDate)
WHEN (@EndDate > cast(DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) + 1, 0)) as date)) and (@StartDate between (cast(CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) and (cast(DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) + 1, 0)) as date))) THEN
DATEDIFF(DAY, @StartDate,DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, @StartDate) + 1, 0))) + 1
WHEN ((DATEDIFF(DAY, @StartDate, cast(DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date)) + 1, 0)) as date)) >= 0) and (DATEDIFF(DAY, cast(CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as date), @EndDate) >= 0)) THEN
DATEDIFF(DAY, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as datetime), DATEADD(d, -1, DATEADD(m, DATEDIFF(m, 0, cast( CONVERT(varchar(4), @for_year) + '-' + CONVERT(varchar(2), @for_month) + '-01' as datetime)) + 1, 0))) + 1
ELSE
0
END as [DD]
I don't know how you calculate day range between 01/01/2013 and 04/01/2013
is 4, it is actually is 3 but if that is the case, you can add 1 from the condition.

Help I need to subtract times to find the difference between two times?

Hello there, I really need help.
I'm trying to make this attendance tracking system so that when a user enters his or her ID the system wll remember his/her check in time. However I also need to find out either how late the person is or how early to store their over time and late.
So I get the time by using a timestamp, so I'm left with a timestamp that I store into the db. But the problem comes when trying to compute for the late or over time. To do that I have to get the normal login/checkin time from the employee schedules table in the db and either subtract that time from the checkInTime to compute for how late or subtract the checkIn time from it to find early.
The thing is, the schedule is stored in datetime format in the db since the db is sql. Also I have no idea on how to subtract the two dates via java. The month, date and year stored in the sql db are just fillers, all I need computed is the time difference of the hours and minutes between the checkInTime and the schedule.
I've tried to use datediff: SELECT e.employeeNumber, datediff('hh', startTime, checkInTime) as lateTime from employeeschedules e, timandattendance, contractualemployees c where c.scheduleNumber=e.scheduleNumber and t.employeeNumber=c.employeeNumber and t.checkInNumber=1;
But it keeps on giving out various errors: You have an error in your sql syntax check your manual that corresponds to your sql server version. for the right syntax to use near , checkInTime) as lateTime from employeeschedules e, timandattendance, contractualemployees c where c.scheduleNumber=e.scheduleNumber and t.employeeNumber=c.employeeNumber and t.checkInNumber=1;
My sql server is My SQL 5.0.5
Now I'm thinking of useing Gregorian instead, but I don't know how to use Gregorian and dont know the various methods. Can someone tell me what to do, provide some sample codes and references that I can use to accomplish what I need to do?

NewtonsApple_2 wrote:
Now I'm thinking of useing Gregorian instead, but I don't know how to use Gregorian and dont know the various methods. Can someone tell me what to do, provide some sample codes and references that I can use to accomplish what I need to do?it may help...
GregorianCalendar

How do I calculate the difference between two times?

I am so embarrassed by the fact that I can't figure this out.
Cell B2- 8:00 am
Cell C2- 10:50 am
Cell D2- (How do I get this cell to calculate the difference and say 2:50?)
I know this is probably one of the most basic operations, but for the life of me I can't figure it out. Cells B2 & C2 are formatted for 24 hour clock. But if I tell the system to just subtract the two, I get "0.118". Everything I find on the forum search goes beyond what I need. Can anyone help me?
Thank you.

KOENIG Yvan wrote:
Numbers states clearly in the Help and the PDF Users Guide that it doesn't know a "duration" object but a time one which is restricted to the range 00:00:0 to 23:59:59.
When I search the U.S. language Numbers User Guide for the word "duration," it is not found.
What may be more clear: _duration is not available but time is_?
Once again your response resemble to a rant againt the Help and the User Guide.
In the Help:
+date-time Any Numbers date/time value. _While you can choose to display only date or time in a cell, all Numbers date or time values contain both the date and time._+
Which wording would be more clear and precise?
TIMEVALUE
+The TIMEVALUE function converts a date, a time, or a text string to _a decimal fraction of a 24-hour day._+
Which wording would be more clear and precise?
TIME
+The TIME function converts hours, minutes, and seconds into a time format.+
+TIME(hours, minutes, seconds)+
+hours: The number of hours _(using a 24-hour clock)._+
+minutes: The number of minutes.+
+seconds: The number of seconds.+
Notes
+You can specify hour, minute, and second values greater than 23, 59, and 59, respectively. _If the hours, minutes, and seconds add up to more than 24 hours, Numbers subtracts 24 hours repeatedly until the sum is less than 24 hours._+
Which wording would be more clear and precise?
In the User Guide:
page 190
+date-time Any Numbers date/time value. _While you can choose to display_+
+_only date or time in a cell, all Numbers date or time values contain_+
+_both the date and time._+
+TIME (page 277) Converts a time to a decimal fraction of a 24-hour day.+
+TIMEVALUE (page 278) Converts a time in a string to a decimal fraction of a 24-hour day.+
TIME
+The TIME function converts the specified time to a decimal fraction of a 24-hour day.+
+TIME(hours, minutes, seconds)+
+• hours: The number of hours _(using a 24-hour clock)_.+
+• minutes: The number of minutes.+
+• seconds: The number of seconds.+
Notes
+You can specify hour, minute, and second values greater than 23, 59, and 59,+
+respectively. _If the hours, minutes, and seconds add up to more than 24 hours,_+
+_Numbers subtracts 24 hours repeatedly until the sum is less than 24 hours._+
+You can also specify fractional values for hours, minutes, or seconds.+
TIMEVALUE
+The TIMEVALUE function converts a time in a string to a decimal fraction of a 24-hour+
day.
TIMEVALUE(date-time)
+• date-time: A date, a time, or a string in any of the Numbers date and time formats.+
As you may check, the infos are exactly the same in the Help and in the Guide.
And I really don't understand how you may find them unclear.
Yvan KOENIG (from FRANCE lundi 4 août 2008 14:57:36)

How do I find the difference between every OCI releases version in SRM ?

Hi guys,
Ithere any document about the detailed difference between every OCI (open catalog interface) release versions in SRM ?
So far, I only found some documents about OCI release 2.0,3.0,4.0, but no detailed telling what's the difference between them.

Hi,
[SAP Supplier Relationship Management - SAP SRM Open Catalog Interface (B2B-OCI) [original link is broken]|SAP Supplier Relationship Management - SAP SRM Open Catalog Interface (B2B-OCI) [original link is broken]]
I always give the latest OCI 4.0 specification to suppliers who implements the OCI enabled catalog. If supplier implements the OCI 4.0, old version of OCI works.
Regards,
Masa

How to quickly find the difference of two version of RPD?

Similar Messages

Maybe you are looking for