How to read a string character by character and pass it into an array

Hi,
I have a requirement to write a function.The thing is,i need to read string,replace space with a NULL,return in the form of an arrayy.
for this what i thought is,if the character is not a space,i need to put that into array,if its space,put a NULL for that.
the string is of type varchar2.
ex:XX XX XX
i need some suggestions for this.
thanks

Well, you can just use a loop that runs for the length of the string.
Then for each iteration of the loop, take the next character of the string (substr or similar) and add it to the array. If it's a space, then add a NULL to the array (if that's what you want).
Easy :)

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Hi!
This is a possible solution to your problem.
import java.io.*;
class AddressExtractor {
 public static void main(String args[]) throws IOException{
 //retrieve the commandline parameters
 String fileName = "default.html";
 if (args.length != 0) fileName =args[0];
 else {
 System.out.println("Usage : java AddressExtractor <htmlfile>");
 System.exit(0);
 BufferedReader in = new BufferedReader(new FileReader(new File(fileName)));
 StreamTokenizer st = new StreamTokenizer(in);
 st.lowerCaseMode(true);
 st.wordChars('/','/'); //include '/' chars as part of token
 st.wordChars(':',':'); //include ':' chars as part of token
 st.quoteChar('\"'); //set the " quote char
 int i;
 while (st.ttype != StreamTokenizer.TT_EOF) {
 i = st.nextToken();
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 i = st.nextToken(); //the next token (assumed) is the '=' sign
 i = st.nextToken(); //then after it is the href value.
 getURL(st.sval); //retrieve address
 in.close();
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 //Check string if it has http:// and truncate if it does
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