How to receive a part of cursor together with total count of records

Hello for all!
I have table with 5 millions of records. This table has varchar2 field.
I need look into this table by this field with using LIKE '%something%'. I.e. I need search by free substring in varchar2 field.
Because my table has serious record count then this query runs during 5-20 seconds and can return serious amount of records (for example 300.000 records).
I don't want to receive 300.000 records in the user program which runs on user desktop computer. I want receive records by page. I.e. by chunks with 100-200 records.
I can use following query:
select * from
(select rownum rn, t1.* from table1 t1 where field1 like '%something%' order by field2)
where rn between 100 and 200
This query can return only needed records from total cursor.
But in this case I don't know total records quanity. But I should show to user total quantity of pages!
I can run query twice. I.e. first time I can run "select count(*) ", next time I can "select * ". But it means that Oracle should process two queries instead of one. This is not good desigion.
Please suggest me something useful for solving this problem.
Thank you,
Best regards,
Eugeny

I can use following query:
select * from
(select rownum rn, t1.* from table1 t1 where field1 like '%something%' order by field2)
where rn between 100 and 200That is not correct.
http://asktom.oracle.com/pls/ask/f?p=4950:8:5368894803981003723::NO::F4950_P8_DISPLAYID,F4950_P8_CRITERIA:127412348064
But in this case I don't know total records quanity. But I should show to user total quantity of pages!That is not a good idea.
http://asktom.oracle.com/pls/ask/f?p=4950:8:::::F4950_P8_DISPLAYID:127412348064#14136093079164

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