How to redirect the clients software updates to the same server but different IP?

Hello Everyone,
Well our Mac expert left the company and I got promoted to take his place. I only have about 7 months experience in the Mac world and I have about 90 Macs in the company. Anyways, our company moved into a new building and the Mac server was moved which I am sure the IP address changed. The server is up and running now, but the clients cannot see it and are not allowed update their software. I didn't change any paths or settings to the server, so I am guessing it has to do with something of some IP changes. The Network team set the static IP address up for it so I could connect to it with Remote Desktop just fine. Any suggestions to a Mac rookie?
Thanks

If your clients can't find the software update server (SUS), then either the server changed DNS names and thus your CatalogURL setting is wrong, or the server was moved to a new address and your DNS services were not updated (or the DNS updates haven't propagated through all the caches quite yet).
To see the current DNS setting for the server your.software.update.server.example.com (and replace that intentionally-bogus DNS name with the DNS name for your software updare server), launch Terminal.app (Applications > Utilities) and issue the command:
dig +short your.software.update.server.example.com
and see if you get the IP address that you expect, or the old IP address, or some other address.
Software Update CatalogURL
The usual way an OS X client configures the local (target) software update server is via a plist setting:
$ sudo defaults write /Library/Preferences/com.apple.SoftwareUpdate CatalogURL http://your.software.update.server.example.com:8088/index.sucatalog
To view the current CatalogURL setting from the plist:
$ sudo defaults read /Library/Preferences/com.apple.SoftwareUpdate CatalogURL
Details of the catalog URL setting needed varies by the version of the OS X Server; the above is for fairly recent servers. Google or Bing or DDG for the string:
/Library/Preferences/com.apple.SoftwareUpdate CatalogURL
for details on this, or check the Apple doc (see below) for details.
Background / Resources / More
Take the time to download and skim through the 10.6 Apple OS X Server 10.6 manuals (search for Mac OS X Server 10.6 to narrow what's posted); there's a lot of good information in those Apple documents, particularly given that the documentation for the more recent releases of OS X Server have gotten rather thinner. You'll find additional details of setting up software update services in those 10.6 documents; in the system imaging and software updates manual.
Also see the archives of the Mac Enterprise mailing list for related information and discussions, as well as details on tools such as Reposado.

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Hi all
I don't understand why the same query but Oracle use different plan
explain plan for select far.id,fab.id
from agent_body fab
INNER JOIN agent_ref far ON (far.bodyid = fab.id)
WHERE fab.id=72449;
| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time | Pstart| Pstop |
| 0 | SELECT STATEMENT | | 1 | 18 | 2 (0)| 00:00:01 | | |
| 1 | NESTED LOOPS | | 1 | 18 | 2 (0)| 00:00:01 | | |
| 2 | PARTITION HASH SINGLE | | 1 | 6 | 1 (0)| 00:00:01 | 4 | 4 |
|* 3 | INDEX UNIQUE SCAN | PK_AGENT_BODY | 1 | 6 | 1 (0)| 00:00:01 | 4 | 4 |
| 4 | PARTITION HASH ALL | | 1 | 12 | 1 (0)| 00:00:01 | 1 | 4 |
| 5 | TABLE ACCESS BY LOCAL INDEX ROWID| AGENT_REF | 1 | 12 | 1 (0)| 00:00:01 | 1 | 4 |
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Predicate Information (identified by operation id):
3 - access("FAB"."ID"=72449)
6 - access("FAR"."BODYID"=72449)
AND
explain plan for select far.id,fab.id
from agent_ref far,agent_body fab
where fab.id=far.bodyid and far.id=2219306;
| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time | Pstart| Pstop |
| 0 | SELECT STATEMENT | | 1 | 18 | 2 (0)| 00:00:01 | | |
| 1 | NESTED LOOPS | | 1 | 18 | 2 (0)| 00:00:01 | | |
| 2 | PARTITION HASH SINGLE | | 1 | 12 | 1 (0)| 00:00:01 | 3 | 3 |
| 3 | TABLE ACCESS BY LOCAL INDEX ROWID| AGENT_REF | 1 | 12 | 1 (0)| 00:00:01 | 3 | 3 |
|* 4 | INDEX UNIQUE SCAN | PK_AGENT_REF | 1 | | 1 (0)| 00:00:01 | 3 | 3 |
| 5 | PARTITION HASH ITERATOR | | 3348K| 19M| 1 (0)| 00:00:01 | KEY | KEY |
|* 6 | INDEX UNIQUE SCAN | PK_AGENT_BODY | 3348K| 19M| 1 (0)| 00:00:01 | KEY | KEY |
Predicate Information (identified by operation id):
4 - access("FAR"."ID"=2219306)
6 - access("FAB"."ID"="FAR"."BODYID")
Can anyone explain to me?
Thanks

user554265 wrote:
Hi all
I don't understand why the same query but Oracle use different plan
explain plan for select far.id,fab.id
from agent_body fab
INNER JOIN agent_ref far ON (far.bodyid = fab.id)
WHERE fab.id=72449;
AND
explain plan for select far.id,fab.id
from agent_ref far,agent_body fab
where fab.id=far.bodyid and far.id=2219306;
Can anyone explain to me?Perhaps this makes a difference...
WHERE fab.id=72449; and
and far.id=2219306; Essentially the two queries ARE different.

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