How to Redirect to a URL on Button Click

Hi all,
I am new to Apex and have a following Requirement
On the page I have a Field P3_CASE_ID and a Button P3_SUBMIT.
When I click the Submit Button, It should Open a new window
https://customer.peoplesoft.com/psp/C1PRD_2/EMPLOYEE/CRM/c/CALLCENTER.RC_CASE_SW.GBL?Page=RC_CASE_SW&Action=U&CASE_ID=
Above String should be Concatneted with value from P3_CASE_ID.
Say if I enter P3_CASE_ID as 123456 then a new window should be opened with following URL
https://customer.peoplesoft.com/psp/C1PRD_2/EMPLOYEE/CRM/c/CALLCENTER.RC_CASE_SW.GBL?Page=RC_CASE_SW&Action=U&CASE_ID=123456
How to do it...?
I tried following in Optional URL Redirect for the button.
javascript:popupURL('
https://customer.peoplesoft.com/psp/C1PRD_2/EMPLOYEE/CRM/c/CALLCENTER.RC_CASE_SW.GBL?Page=RC_CASE_SW&Action=U&CASE_ID=&P3_CASE_ID.');
But the P3_CASE_ID is not appended to the URL.
Thanks and Regards
Kesav
Message was edited by:
user619016

Here is some code I think you will find helpful.
http://www.oracle.com/technology/products/database/application_express/howtos/how_to_create_custom_popups.html

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