How to save uploaded file in the context

Question

Hi,
I am trying to save an uploaded file in a folder in reference to the
context. I can not get the path to the destination folder with reference to
the context.
The file gets uploaded fine as I can pull the info about the file, however,
I am not able to save it in a folder under context. Any ideas?
the code is pasted below;
thanks
Rauf
public class MyBean {
    private UploadedFile uploadedFile;
    int BUFFER_SIZE = 20000;
    protected final Log logger = LogFactory.getLog(getClass());
    public UploadedFile getUploadedFile() {
        return uploadedFile;
    public void setUploadedFile(UploadedFile uf) {
        this.uploadedFile = uf;
    public String processMyFile() {
         String uploadedFileName = getUploadedFile().getName();
         logger.debug("The uploaded file name is: " + uploadedFileName);
        int index = uploadedFileName.lastIndexOf('/');
        String justFileName;
        if ( index >= 0) {
            justFileName = uploadedFileName.substring( index + 1 );
        } else {
            // Try backslash
            index = uploadedFileName.lastIndexOf('\\');
            if (index >= 0) {
                justFileName = uploadedFileName.substring( index + 1 );
            } else {
                // No forward or back slashes
                justFileName = uploadedFileName;
        logger.debug("just file name: " + justFileName);
       String uploadedFileType = uploadedFile.getContentType();
       FacesContext facesContext = FacesContext.getCurrentInstance();
            try {
                 logger.debug("In the first try loop");
                // get the path to the /img directory from the servlet context
                ServletContext servletContext = (ServletContext)facesContext.getExternalContext();
                String realPath = servletContext.getRealPath("/img");
                logger.debug("The real path: " + realPath);
                logger.debug("saved file name: " + realPath + justFileName);
                  InputStream in = new BufferedInputStream(getUploadedFile().getInputStream());
                BufferedOutputStream outputStream = new BufferedOutputStream(new FileOutputStream(realPath + justFileName));
                     try {
                            byte[] data = new byte[BUFFER_SIZE];
                       int readSize;
                       while ((readSize = in.read(data, 0, BUFFER_SIZE)) != -1)
                            logger.debug("writing buffer: " );
                            outputStream.write(data, 0, readSize);
                       in.close();
                       outputStream.close();
                     catch (FileNotFoundException e) {
                          e.printStackTrace();
                   catch (IOException e) {
                        e.printStackTrace();
                   logger.debug("return OK");
                   return "OK";
            catch(Exception e){
                 e.printStackTrace();
                 return "Not OK";
}

Answer 1

What I am struggling with is how to get the path relative to the context. The file upload works fine, however, the code fails at the fillowing line:
ServletContext servletContext = (ServletContext)facesContext.getExternalContext();producing the following error:
The uploaded file name is: c:\myjava\downloads\b2b-project-0.1-07282004.zip
2006-08-22 00:16:34,344 DEBUG [com.hunza.kcw.jsfupload.MyBean] - just file name: b2b-project-0.1-07282004.zip
2006-08-22 00:16:34,344 DEBUG [com.hunza.kcw.jsfupload.MyBean] - In the first try loop
2006-08-22 00:16:34,344 DEBUG [com.sun.faces.lifecycle.InvokeApplicationPhase] - Exiting InvokeApplicationsPhase
If I specify the absolute path like c:\temp, the file save is successfull. I am looking for a way to save the file in a folder in the context, without having to specify the full path of the folder.
Rauf