How to set a fixed size window, so that moving 2D pictures wouldnt go off?

Question

Hi
I dont if this question has been asked or no & also not sure if its right to be posted here as my problem is a java 2D graphics problem in swing environment.
I want to know is how can i set the window to a fixed size with boundaries such that my graphics 2D picture in the swing window will not go off the edges of window when i do some transformations with the 2D picture.
For e.g:
so far ive got a frame window of size 350 by 350 with my 2D picture inside it made up of shapes etc...
when i apply some transformation to it (moving it) for a distance it goes disappeared off window beyond 350 and will come back if i move it back.
So how do i restrict the window so that when picture reaches the edge, it will not be able to move any further?
Do i set some specific bounds to the JFrame?
i hope i've explained it properly
Thanks

Answer 1

In a 2D coordinate system the horizontal values are represented by some letter, usually x. In the same coordinate system the vertical values are classically represented by y.
Note: In your code, if you wish, you can replace x and y with anything you desire--p and q or perhaps jeff and alice or any variable name you wish, but for simplicity, and usually ease of understanding because almost everyone has had 100's of math problems drilled into their head with (x, y), x and y are used as convention.
In Java the screen coordinates run from 0 to the width-1 for x and 0 to height-1 for y of the component you are using to display.
So logically when you have a value of x or y that goes beyond the addressable bounds of your display, then you have to make some type of adjustment--when your value dips below 0, you reset it to 0, when your value goes above what ever width-1 or height-1 then you have to set that value to width-1 or height-1.
This all assumes that when you hit the wall, floor, or ceiling you stick there until you change directions--if you wish to wrap then you set your value to the opposite bound--so if you go below 0, you would then pop out back in on the right side--your appropriate x would be set to width-1 instead of 0 and in the case of y going below 0 your y would be set to height-1. This is also to say that when you descend below your minimum, then you would pop back out on the opposite side you went out on--so x greater then width-1 would get set to 0 and y greater than height-1 would get set to 0.
That is not even a start on if you want to include elastic collisions, angle of impact, any type of deceleration force, or anything else.
In any case... I would recommend that you add more math to your studies, I've never met an engineer or computer science grad that said: "Wow, I really regret taking all that math in college (or HS), I never use it."