How to show a symbol if two others equal true
I'm sure this is cake but, heh :-/
I have two symbols that are set to equal show when dragged ontop of a target
sym.$('TARGET-PA1').droppable(
accept:sym.$('PURPLE-A-1'),
drop: function(){
sym.$('PROX-PURPLE-A-1').show(); //showing symbol one
sym.$('TARGET-PA2').droppable(
accept:sym.$('PURPLE-A-2'),
drop: function(){
sym.$('PROX-PURPLE-A-2').show(); //showing symbol two
I have another symbol that i want to .show() when both are true how do i do this?
i think i'm close but it's still not working
i have this if statement
if(sym.getSymbol("PROX-GREEN-A-1") == true){ // it was set to hide() but it's on the stage now
sym.$('PROX-SM-AG-1').show(); // i want this symbol to show()
else{
sym.$('PROX-GREEN-A-2').show();
is the == true part wrong?
I used to do this with .visible in flash but can't find the Edge equivalent :-/
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