How to specify timezone in quartz scheduler

Question

Hi,
I want to initiate a job at a particular time - 6 AM EST every Monday. The cron expression can help me do "6 AM every Monday" part, but not the EST part. How do I specify a timezone. I could not find any examples pertaining to doing this in quartz used in a web application. I found some links that talked about doing this in spring framework - http://forum.springsource.org/archive/index.php/t-16381.html
My web.xml currently looks like this:
<?xml version = '1.0' encoding = 'windows-1252'?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd"
version="2.4" xmlns="http://java.sun.com/xml/ns/j2ee">
<description>Empty web.xml file for Web Application</description>
<!--servlet>
<servlet-name>QuartzInitializer</servlet-name>
<servlet-class>org.quartz.ee.servlet.QuartzInitializerServlet</servlet-class>
<load-on-startup>1</load-on-startup>
<init-param>
<param-name>config-file</param-name>
<param-value>bpel_quartz.properties</param-value>
</init-param>
</servlet-->
<servlet>
<servlet-name>BPELSchedulerServlet</servlet-name>
<servlet-class>com.otn.samples.BPELSchedulerServlet</servlet-class>
<init-param>
<param-name>cronExpr</param-name>
<param-value>0 0 6 ? * MON</param-value>
</init-param>
<load-on-startup>2</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>BPELSchedulerServlet</servlet-name>
<url-pattern>/bpelschedulerservlet</url-pattern>
</servlet-mapping>
<session-config>
<session-timeout>35</session-timeout>
</session-config>
<mime-mapping>
<extension>html</extension>
<mime-type>text/html</mime-type>
</mime-mapping>
<mime-mapping>
<extension>txt</extension>
<mime-type>text/plain</mime-type>
</mime-mapping>
</web-app>
TIA
Amit

Answer 1

Thanks, I followed your suggestion and was able to make this work. Here is what I have done.
In Web.xml, added a new init parameter, timezone.
<servlet>
<servlet-name>BPELSchedulerServlet</servlet-name>
<servlet-class>com.otn.samples.BPELSchedulerServlet</servlet-class>
<init-param>
<param-name>cronExpr</param-name>
<param-value>0 30 6 ? * MON</param-value> <!--Mondays 6:30amEST -->
</init-param>
<init-param>
<param-name>timezone</param-name>
<param-value>EST</param-value>
</init-param>
<load-on-startup>2</load-on-startup>
</servlet>
then in the scheduler servlet,
String cronExprFromWebXml = null;
// Get the cron Expression as an Init parameter
cronExprFromWebXml = getInitParameter("cronExpr");
String timezone = getInitParameter("timezone");
String cronExpr = convertCronExpr(cronExprFromWebXml,timezone);
and I wrote a function in the same file,
public String convertCronExpr(String inputCronExpr, String desiredTimezone)
String outputCronExpr="";
String[] inputCronArray = inputCronExpr.split(" ");
String dateInDesiredFormat = inputCronArray[0]+":"+inputCronArray[1]+":"+inputCronArray[2]+":"+desiredTimezone;
String dateInServerFormat;
DateFormat genFormat = new SimpleDateFormat("s:m:k:z");
Date specifiedTime;
try
specifiedTime = genFormat.parse(dateInDesiredFormat);
genFormat.setTimeZone(TimeZone.getDefault());//This gets the server timezone
dateInServerFormat = genFormat.format(specifiedTime);
String[] outputCronArray = dateInServerFormat.split(":");
outputCronExpr = outputCronArray[0]+" "+outputCronArray[1]+" "+outputCronArray[2]+" "+inputCronArray[3]+" "+inputCronArray[4]+" "+inputCronArray[5];
System.out.print("inputCronExpr "+inputCronExpr);
System.out.println(" --- In "+desiredTimezone);
System.out.print("outputCronExpr "+outputCronExpr);
System.out.println(" --- In soa suite timezone,"+TimeZone.getDefault().getDisplayName());
return outputCronExpr;
catch (ParseException e)
return inputCronExpr;
ofcourse I havent done any error handling here, and the code really works only for the given situation (it would fail if we use other forms of the cron expression..)
-Amit