How to use Arrays in Oracle

Question

Can any one help me to use an Array in oracle.Also i want to search whether an element is already existing in the array

Answer 1

One possible approach
SQL> create or replace type array as table of number;
  2  /
Type created.
SQL> select case when count(*) = 1 then 'found' else 'not found' end
  2  from dual
  3  where exists (
  4    select null from table(array(1,2,3,4,5))
  5    where column_value = 3);
CASEWHENC
found
SQL> edi
Wrote file afiedt.sql
  1  select case when count(*) = 1 then 'found' else 'not found' end
  2  from dual
  3  where exists (
  4    select null from table(array(1,2,3,4,5))
  5*   where column_value = 1)
SQL> /
CASEWHENC
found
SQL> edi
Wrote file afiedt.sql
  1  select case when count(*) = 1 then 'found' else 'not found' end
  2  from dual
  3  where exists (
  4    select null from table(array(1,2,3,4,5))
  5*   where column_value = 6)
SQL> /
CASEWHENC
not found