How to write this sql code ?

Question

for example below shows:
create table temp
order_type varchar2(30),
order_num number);
insert into temp values('apple',000001);
insert into temp values('banana',000002);
insert into temp values('chair',000003);
select *
from temp
where instr(order_type,decode(x,1,'a',2,'b',2,'c',order_type)) >0
if i let x equals 2 and i want to get b and c from above querying .
why above query could not get 'c' and only get 'b' if i give 2 to x ?
how to write above select clause ?
who can help me ?
thanks!

Answer 1

Decode will return the first match;
SQL> select decode(2,1,'a',2,'b',2,'c')
from dual
D
b
1 row selected.This may help;
old: select *
from temp
where regexp_like(order_type, case to_number(&x)
                                 when 1 then 'a'
                                 when 2 then 'b|c'
                              end)
new: select *
from temp
where regexp_like(order_type, case to_number(2)
                                 when 1 then 'a'
                                 when 2 then 'b|c'
                              end)
ORDER_TYPE                      ORDER_NUM
banana                                  2
chair                                   3
2 rows selected.