How to Zip server files(in a directory) and throwing back to client

Question

Can someone tell me how to zip all the files in a particular directory of my web application and throwing back to client to give option for save that zipped file.
i have used the below used function to zip in servlet. But I cann't zip a particular directory of my application in server.
Please help
private void zipDir(String dir2zip, ZipOutputStream zos)
try
//create a new File object based on the directory we
// have to zip File
File fileDir2Zip = new File(dir2zip);
System.out.println("is directory ..."+fileDir2Zip.isDirectory());
//get a listing of the directory content
String[] dirList = fileDir2Zip.list();
for(int i = 0 ; i < dirList.length ; i++)
System.out.println("Dir list ..."+dirList);
byte[] readBuffer = new byte[2156];
int bytesIn = 0;
//loop through dirList, and zip the files
for(int i=0; i<dirList.length; i++)
File f = new File(fileDir2Zip, dirList[i]);
if(f.isDirectory())
//if the File object is a directory, call this
//function again to add its content recursively
String filePath = f.getPath();
zipDir(filePath, zos);
//loop again
continue;
//if we reached here, the File object f was not
//a directory
//create a FileInputStream on top of f
FileInputStream fis = new FileInputStream(f);
//create a new zip entry
ZipEntry anEntry = new ZipEntry(f.getPath());
//place the zip entry in the ZipOutputStream object
zos.putNextEntry(anEntry);
//now write the content of the file to the ZipOutputStream
while((bytesIn = fis.read(readBuffer)) != -1)
zos.write(readBuffer, 0, bytesIn);
System.out.println("Last");
//close the Stream
fis.close();
catch(Exception e)
e.printStackTrace();

Answer 1

Hi
Whatever file exist in directory should execute with out any condition because they delete all files after exection of my process chain. They are using another process chain once a day for deletion of all files in that directory.
So directory always contains fresh files.
Here by using routine in infopackge i am unable to run all files one by one at a time.
As of my knowledge  by using infopackage we can run only one file at a time.
Here my question is , can we run more than one file in single run of infopackage?
or can we have any function module to run the infopackage from externally? so that i can use function module in abap program? any ideas..
Regards
Raju