I cant't read the last line in the grid
hello,
I use a grid to display a SQL query with a field-entry
When I loop through the grid, I manage to read all lines except the line or the cursor, it keeps the old value
Do you have an idea
Thank you
It's my code
Shared Sub ItemEvent_Maj_emplacement_lot(ByRef FormUID, ByRef pVal, ByRef BubbleEvent)
Dim EventEnum As SAPbouiCOM.BoEventTypes
EventEnum = pVal.EventType
If pVal.ItemUID = "1" Then
Dim jj As Integer
EventEnum = pVal.EventType
If EventEnum = BoEventTypes.et_CLICK Then
oform = SBO_application.Forms.Item(FormUID)
oitem = oform.Items.Item("MyGrid")
oGrid = oitem.Specific
Dim ColNum = oGrid.Columns.Count
Dim OgridCodeItem As Long
Dim OgridCodeMag As String
Dim OgridCodeLot As String
Dim OgridEmplacement As String
If oGrid.Columns.Count = 0 Then
Exit Sub
End If
For jj = 0 To oGrid.Columns.Count
Try
OgridCodeItem = oGrid.DataTable.GetValue(1, jj)
OgridCodeMag = oGrid.DataTable.GetValue(2, jj)
OgridCodeLot = oGrid.DataTable.GetValue(3, jj)
OgridEmplacement = oGrid.DataTable.GetValue(5, jj)
' This field OgridEmplacement is This field keeps the old value only on the last line before
' On the other lines, it works well
Catch oEx As Exception
' MessageBox.Show(oEx.Message & " jj = " & CStr(jj))
' Exit Sub
End Try
Next jj
End If
End If
End Sub
Similar Messages
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Cannot retrieve all vector objects - reading only last line .. Please help
<pre>
When I test the vector in the method that adds the elements, each line is returned. Testing the vector in the method getData(), all items are returned within the while loop, but the test returns only the last line of in the vector. Can anyone help me out and let me know what I'm doing wrong.
Here's a summary of what I'm doing and the code follows.....
My bean class:
- creates a vector and adds several lines to the vector
- using StringTokenizer and Enumeration, parses the data and checks to see if the line has the required amount of tokens (which is 4). If so, then the string is passed to my main class
In the main class, the string is parsed into its appropriate attribute and then the required ones are displayed in the browser.
//Vector class bean
public SpecBean()
public Vector addData()
vecdata.addElement ("3|4||");
vecdata.addElement ("2|3||1200");
vecdata.addElement ("1|2|Q|");
vecdata.addElement ("4|2|U|4356");
return vecdata;
public String getData()
StringTokenizer st;
String record = new String();
Enumeration enumdata = vecdata.elements();
while (enumdata.hasMoreElements())
record = enumdata.nextElement().toString();
System.out.println (record);
st = new StringTokenizer( record, "|");
int numberOfTokens = st.countTokens();
if (numberOfTokens < 4)
record = "Incomplete Data";
return record;
// end class...
//begin main class -- this is a servlet which is why the
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try {
SpecBean specs = new SpecBean();
specs.getItemListing();
token = new StringTokenizer ((String)specs.getData(), "|");
out.println ("<table width=\"100%\" border=1>");
out.println("<tr>");
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while (token.hasMoreTokens())
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String orderNum = token.nextToken();
String name = token.nextToken();
String confNum = token.nextToken();
out.println (title + "</td>");
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Thank you.<pre>
My apologies. What I was looking to do was return EVERY line from the vector that had an equivalent of 4 tokens and no less. I just realized that the sample data I had entered into the vector only had one line w/ 4 tokens. When this is modified and there are 2+ lines that contain 4 tokens, the only line that is retrieved is the very last line. So if the data in the vector was:
public Vector addData()
vecdata.addElement ("3|4|rtd|222");
vecdata.addElement ("2|3||1200");
vecdata.addElement ("1|2|QsT|");
vecdata.addElement ("4|2|U|4356");
return vecdata;
public String getData()
StringTokenizer st;
String record = new String();
Enumeration enumdata = vecdata.elements();
while (enumdata.hasMoreElements())
record = enumdata.nextElement().toString();
System.out.println (record);
st = new StringTokenizer( record, "|");
int numberOfTokens = st.countTokens();
if (numberOfTokens < 4)
record = "Incomplete Data";
return record;
The output to the browser is
4 2 U 4356
and not
3 4 rtd 222
4 2 U 4356
I did some print statements throughout addData() and getData() to see if all of the objects in the vector were still there and everything checked out until I hit the end of the getData(). Before 'return record' the print statement returned '4 2 U 4356' only. I'm not sure what I have missed to have the getData() method return only one matching line and not all of them.
Your help is appreciated. Thank you. -
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return read();
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public static List<String> tail(File file, String encoding, int numberOfLinesToRead) throws IOException
assert (file != null) && file.exists() && file.isFile() && file.canRead();
assert numberOfLinesToRead > 0;
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char temp = chars[j];
chars[j] = chars[k];
chars[k]= temp;
lines.addFirst(new String(chars));
reader.close();
return lines;
public static void main(String[] args)
try
File file = new File("/usr/share/dict/words");
int n = 10;
System.out.println("Head of " + file);
int index = 0;
for (String line : head(file, n))
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System.out.println("Tail of " + file);
int index = 0;
for (String line : tail(file, "us-ascii", n))
System.out.println(++index + "\t[" + line + "]");
catch (Exception e)
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Hello, I am new to Java. Do anybody know how to read the last line (this is the last record) in the text file.The method I am now using is reading from the first line until I reach the last line in the text file. Thank you!!
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Hi
I am sending in a clarification , hoping that I get an efficient solution from the group, should somebody have come across this scenario and implemented.
How to read or get the last line from a text file , which usually have a no of records, without actually reading or looping through all the lines
I know there is some solution with the RandomAccessFile, but given there can be some encoding issues or so.
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Read in the last line of a file
Can I use the "Read from File " vi to read ionly the last line of the file? If so, how? Thanks in advance for the help
[email protected]Reading the "last line" of a file implies that you are dealing with an humanly readable ASCII text file and there are special characters (/n or /r or a combination of the two) that signify line breaks.
You can only start reading from a certain byte offset using file I/O. Unless all your lines are equal lenght, It is impossible to find the start of the last line without reading every character leading up to it in one way or another.
So in the most general case, you would need to read the entire file and find the last linefeed.
HOWEVER: Typically, lines are not infinitely long, so if you have an upper estimate of line lenght, you can read a slightly longer tail from the end of the file and find the last linefeed there. You can probably modify the VI I posted here for your purpose, just use an appropriate length. Message Edited by altenbach on 06-08-2005 10:42 AM
LabVIEW Champion . Do more with less code and in less time . -
Hi,
I fixed error in last post and rewrote the code using ProcessBuilder instead.
Output from my unix tool is:
Command is a shell application' /home/myid/test/myshell/bin/run' that starts a ascii gui that looks like ( see below). It waits for input from user.
* My shell Application *
HELP: h
COMMAND: c
QUIT:q
135.19.45.18>
And still the last line is not showing when I read the text.
I have tried with readLine() and I get the same error.
Note: When I debug, after characters in line:
OUIT:q
have been read I can see that debugger hangs on
br.read()
And now the code looks like:
import java.io.BufferedReader;
import java.io.BufferedWriter;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.OutputStream;
import java.util.ArrayList;
import java.util.List;
public class RunShellCmd {
private BufferedReader processInputStream;
private BufferedWriter processWriter;
public static void main(String args[]) throws Exception {
RunShellCmd cmd = new RunShellCmd();
cmd.runCmd();
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Process process = null;
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cmd.add("/bin/bash");
cmd.add("/home/myid/test/myshell/bin/run");
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process = processBuilder.start();
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BufferedReader br = new BufferedReader(isr);
StringBuilder sb = new StringBuilder();
int intch;
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char ch = (char) intch;
sb.append(ch);
System.out.println(sb.toString());
} catch (IOException e) {
System.out
.println("An error occourd: "
+ e.toString());
} finally {
processInputStream.close();
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Please don't create duplicate threads. You already have a thread for this same issue.
I fixed error in last post and rewrote the code using ProcessBuilder instead.
Good - then post your progress in the original thread and keep using it until the problem is resolved. That way the people that tried to help you before can see the entire context of what you are trying.
https://forums.oracle.com/thread/2611844 -
How to read the second line in a .txt file with bufferedReader?
hi,
i am not the best in speaking english and programming java :)
so, just try to make sense of my question:
Im using a BufferedReader to read a .txt file.
the .txt file has 5+ different lines, and each line has 6 tokens (separated with ; )
My java file has 6 textFields and each textfield is filled with one of the 6 different tokens.
and my problem is:
I want my buffered reader to read the next line (with 6 new different tokens) by pressing a button.
if somethings not understandable, just ask :)maybe its easier to help me, when i publish my code, so here it is:
(its my version, without Thof's code. Sorry, but the comments are the most in german)
/* userdata.java */
import java.awt.*;
import java.awt.event.*;
import java.applet.*;
import javax.swing.*;
import java.util.*;
import java.io.*;
public class userdata extends Frame {
//-----------------------------------KlassenVariablen------------------------------------------------
private JPanel panel = new JPanel ();
String tokId = "";
String tokName= "";
String tokAge= "";
String tokTel= "";
String tokMail= "";
String tokText= "";
BufferedReader br;
String zeile;
StringTokenizer st;
String delim = ";";
//---------Buttons f?r Panel 1-------------------------
Button first = new Button("|< First");
Button back = new Button("< Back");
Button next = new Button("Next >");
Button last = new Button("Last >|");
//---------Buttons f?r Panel 3-------------------------
Button neu = new Button("New");
Button safe = new Button("Safe");
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//--------Labels f?r Panel 2-----------------------------
Label lid = new Label("ID",Label.LEFT);
Label lname = new Label("Name",Label.LEFT);
Label lage = new Label("Age",Label.LEFT);
Label ltel = new Label("Tel.",Label.LEFT);
Label lmail = new Label("E-Mail",Label.LEFT);
Label ltext = new Label("Spruch",Label.LEFT);
Label lub = new Label("Last Button",Label.LEFT);
TextField id = new TextField();
TextField name = new TextField();
TextField age = new TextField();
TextField tel = new TextField();
TextField mail = new TextField();
TextField text = new TextField();
TextField usedbutton = new TextField();
//--------ActionEvent bla sachen eben--------------------
public static void main (String[] args) throws IOException {
userdata wnd = new userdata();
wnd.setVisible(true);
public userdata() throws IOException {
//--------------------------------Layout mit panel bestimmung--------------------------------------
setLayout(new BorderLayout());
JPanel p1 = new JPanel();
JPanel p2 = new JPanel();
JPanel p3 = new JPanel();
add(BorderLayout.NORTH ,p1);
add(BorderLayout.CENTER , p2);
add(BorderLayout.SOUTH , p3);
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p1.add(back);
p1.add(next);
p1.add(last);
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p2.add(id);
p2.add(lname);
p2.add(name);
p2.add(lage);
p2.add(age);
p2.add(ltel);
p2.add(tel);
p2.add(lmail);
p2.add(mail);
p2.add(ltext);
p2.add(text);
p2.add(lub);
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p3.add(neu);
p3.add(safe);
p3.add(refresh);
//--------------------------------BufferedReader -------------------------------------------------
readData();
//--------------------------------Panel 2 TextField-----------------------------------------------
fillForm();
//================================ActionPerformed==================================================
first.addActionListener(new java.awt.event.ActionListener() {
public void actionPerformed( ActionEvent e ) {
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usedbutton.setText("First");
back.addActionListener(new java.awt.event.ActionListener() {
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usedbutton.setText("Back");
next.addActionListener(new java.awt.event.ActionListener() {
public void actionPerformed( ActionEvent e ) {
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usedbutton.setText("Next");
last.addActionListener(new java.awt.event.ActionListener() {
public void actionPerformed( ActionEvent e ) {
System.out.println ("Last");
usedbutton.setText("Last");
neu.addActionListener(new java.awt.event.ActionListener() {
public void actionPerformed( ActionEvent e ) {
System.out.println ("New entry");
usedbutton.setText("New");
safe.addActionListener(new java.awt.event.ActionListener() {
public void actionPerformed( ActionEvent e ) {
System.out.println ("Now Saving, do not turn off!");
usedbutton.setText("Save");
//-----------------refresh
refresh.addActionListener(new java.awt.event.ActionListener() {
public void actionPerformed( ActionEvent e ) {
try{
readData();
}catch( IOException ioe){
System.out.println("Fehler beim lesen aus Datei");
fillForm();
usedbutton.setText("Refresh");
//=============================================================================Button Funktionen!!!
pack();
//--------------------------------WindowsListener hinzuf?gene--------------------------------------
addWindowListener(
new WindowAdapter() {
public void windowClosing(WindowEvent event)
setVisible(false);
dispose();
System.exit(0);
//-----------------------------------readData() - > Buffered Reader in aktion! --------------------
private void readData() throws IOException{
BufferedReader br = new BufferedReader(new FileReader("My .txt File with path"));
String zeile;
StringTokenizer st;
String delim = ";";
zeile = br.readLine();
st = new StringTokenizer(zeile, delim);
st.hasMoreTokens();
//System.out.println (st.nextToken());
tokId = new String(st.nextToken());
tokName = new String (st.nextToken());
tokAge = new String (st.nextToken());
tokTel = new String (st.nextToken());
tokMail = new String (st.nextToken());
tokText = new String (st.nextToken());
//--------------------------fillForm() - > f?llt die TextFelder aus!--------------------------------
private void fillForm(){
id.setText(tokId);
name.setText(tokName);
age.setText(tokAge);
tel.setText(tokTel);
mail.setText(tokMail);
text.setText(tokText);
} -
hi im having huge problems trying to install flash for my mac 10.5 imac, iv gone through the internet and tried all of the solutions, everytime i try to install flash it says cant read the download file, or it just wont install, anybody plz help!
iv unistalled flash, iv checked plug ins it just wont work,It would have been a great help to know precisely what Mac you have, so some of the following may not apply:
You can check here: http://www.adobe.com/products/flash/about/ to see which version you should install for your Mac and OS. Note that version 10,1,102,64 is the last version available to PPC Mac users*. The latest version,10.3.183.23 or later, is for Intel Macs only running Tiger or Leopard, as Adobe no longer support the PPC platform. Version 11.4.402.265 or later is for Snow Leopard onwards.
(If you are running Mavericks: After years of fighting malware and exploits facilitated through Adobe's Flash Player, the company is taking advantage of Apple's new App Sandbox feature to restrict malicious code from running outside of Safari in OS X Mavericks.)
* Unhelpfully, if you want the last version for PPC (G4 or G5) Macs, you need to go here: http://kb2.adobe.com/cps/142/tn_14266.html and scroll down to 'Archived Versions/Older Archives'. Flash Player 10.1.102.64 is the one you download. More information here: http://kb2.adobe.com/cps/838/cpsid_83808.html
You should first uninstall any previous version of Flash Player, using the uninstaller from here (make sure you use the correct one!):
http://kb2.adobe.com/cps/909/cpsid_90906.html
and also that you follow the instructions closely, such as closing ALL applications (including Safari) first before installing. You must also carry out a permission repair after installing anything from Adobe.
After installing, reboot your Mac and relaunch Safari, then in Safari Preferences/Security enable ‘Allow Plugins’. If you are running 10.6.8 or later:
When you have installed the latest version of Flash, relaunch Safari and test.
If you're getting a "blocked plug-in" error, then in System Preferences… ▹ Flash Player ▹ Advanced
click Check Now. Quit and relaunch your browser.
You can also try these illustrated instructions from C F McBlob to perform a full "clean install", which will resolve the "Blocked Plug-in" message when trying to update via the GUI updater from Adobe.
Use the FULL installer for 12.0.0.44: Flash Player 12 (Mac OS X)
And the instructons are here: Snow Leopard Clean Install.pdf
(If you are running a PPC Mac with Flash Player 10.1.102.64 and are having problems with watching videos on FaceBook or other sites, try the following solution which fools the site into thinking that you are running the version 11.5.502.55:)
Download this http://scriptogr.am/nordkril/post/adobe-flash-11.5-for-powerpc to your desktop, unzip it, and replace the current Flash Player plug-in which is in your main/Library/Internet Plug-Ins folder, (not the user Library). Save the old one just in case this one doesn't work. -
How to find out the Last line of a page in Smart forms
Hi Experts,
I need to find out the <b>last line of a page in smartforms</b>.
I have <b>Heading in a text element</b> and its <b>text in another text element</b>.
If the heading falls in the last line, its contents will be displayed in the next page. I want to print the heading in the next page.
Please advise on this issue.
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VivenYou can put both the heading and contents in a Folder node and check the page protection checkbox of the Folder node. This way both will be displayed on the same page always.
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Hi Experts,
As part of one interface uploading the csv file (4coulmns) manually using the TCODE: CSCA_FILE_COPY.
After uploading when i see in the AL11 as it is csv file it is filling the , in each space.
But my issue while running the interface (because of logic in it) checking for the hash total in the last line where (record count, hash total) only 2 items should come but because of manual upload adding the (record count, hash total, , ,) another two spaces.
Where program not moving further becasue the it is alway comparing the amounts (1000.00 not matching with 1000.00, , ) it is not processing. In production files directly load in to unix server so no issues and i can't ask to change the program code...because iam not following the process. As part of testing i've to do manually only.
Please suggest the workaround for this.
Is it possible to change the contents directly in AL11 directly....then HOW ?
or
How to create a csv file w/o , , in the last line (may be it is not possible) ?
Thanks for your replies in advance.
Regards
VVRI don't think you can edit from AL11, nor creating a CSV without those commas at the end because are created to state fields with empty value.
You have 6 columns filled with values but for the last line you only fill the first four. It is expected to appear , , for the last 2 columns on the last line.
I can only suggest keep doing it manually before uploading the CSV file... or... you are saying you can't change the program.
How about upload all CSV files... then writing another program to get those files from AL11 and delete the spare commas at the end line?
Cheers,
Andres.
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Do i need to close an i tunes account?
about 6 months my ipod nano (4th gen) and my roommates lap top (a pc) got stolen. (different incidences around the same time) we sort of said "Cest' la' vi" to the whole thing.. but luckily i just got a handy new Macbook pro and a new ipod nano (4th
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Publish Password Protect Calendar for Web-Browsers?
I read the various help resources in OS 10.4.11 and online and can't seem to figure out if a calendar can be shared with password protection so that anyone using a web browser who knows the password only can access it. From what I've read, Apple says
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Very n00b error....just started programming and need help?!?!
Hi i just started programming in java. im running j2se 1.5.0 on windows xp im on the subject of classes and objects. here is my simple little code im trying to get to compile public class Newprog public static void main(String[] args)
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Creative cloud License problem / Camera raw problem / Linked ?
I have bought a CC 1 year licence. Quite every time I start Photoshop CS 6 it says that the CC trial period has expired (I installed CS6 premium from trial a few days before CC was activated) It ask to connect oline to activate - then it activate pr