Ignoring the period in a sentence

Question

Hello,
I am trying to create a code segment that goes through a sentence (input) word by word and displays all words which have an even number of letters and ignores the words with an odd number of letters. I have created a code that is able to do that. But, the only problem is that the last word in the sentence includes the punctuation (period, question mark) in it's count. Can anyone tell me how to go about fixingthat problem. Here's what I've come up with so far . . .
public static void main (String[] args)
   Scanner scan = new Scanner (System.in);
   System.out.print("Enter a statement >");
   String sentenceIn = scan.nextLine();
   String oneWord;
   StringTokenizer st = new StringTokenizer(sentenceIn);
    while (st.hasMoreTokens())
       oneWord = st.nextToken();
       if (oneWord.length() % 2 == 0)
       System.out.println(oneWord);
}Any help will be greatly appreciated!! Ana : )

Answer 1

Hi,
You could use a regular expression to remove the non word characters. Here's an example
          String test = "this is a test line, where ? there are some words!";
          test = test.replaceAll("\\W", " ");
          System.out.println("test = " + test);
          String[] parts = test.split("\\s");
          System.out.println("parts.lenth = " + parts.length);
          for (int i = 0; i < parts.length; i++) {
               int length = parts.trim().length();
               if (length > 0 && length % 2 == 0) {
                    System.out.println(parts[i]);