IllegalArgumentException when opening an URL

Question

Hi,
I am trying to open a URL which has some kind of special character inside.
This special character causes a IllegalArgumentException when I try to open it with Java while it works fine opening it in my Firefox Browser.
The code is:
String url = "http://www.flunk.de/webkatalog/forum/rtl-und-coca-cola-heimspiel-wg-ich-brauch-h%EDlfe-t335.html";
URL urlObj = new URL(url);
try {
  InputSource source = new InputSource(url.openStream());
} catch (IOException e) {
  e.printStackTrace();
}This causes an exception with the following StackTrace:
java.lang.IllegalArgumentException
at sun.net.www.ParseUtil.decode(Unknown Source)
at sun.net.www.ParseUtil.toURI(Unknown Source)
at sun.net.www.protocol.http.HttpURLConnection.plainConnect(Unknown Source)
at sun.net.www.protocol.http.HttpURLConnection.connect(Unknown Source)
at sun.net.www.protocol.http.HttpURLConnection.getInputStream(Unknown Source)
at java.net.URL.openStream(Unknown Source)The Problem seems to be the "%ED" part of the URL. If I delete that part, no exception occures which doesn't help me, since the url is no more correct and I don't reach the correct website with it.
Does anybody know, how I can avoid that?
Thanks,
Henrik

Answer 1

Oh sorry - of course I tried this one:
String url = "http://www.flunk.de/webkatalog/forum/rtl-und-coca-cola-heimspiel-wg-ich-brauch-h%EDlfe-t335.html";
URL urlObj = new URL(url);
try {
  InputSource source = new InputSource(urlObj.openStream());
} catch (IOException e) {
  e.printStackTrace();
}Message was edited by:
HenrikH