Im puling my hair out! compiler error message

Question

can any one please give me an insight into why my program is giving me the following message
myTry3.java [24:1] variable output might not have been initialized
JOptionPane.showMessageDialog(null,output,"Information",JOptionPane.INFORMATION_MESSAGE);
i cant understand this as i have set up the variable as a string at the start of the program. some guidance would be well appreciated here if possible please. thanks.

Answer 1

Then maybe you need to assign something sensible to output, won't you?
After all, you were the one who was insisting that it was initialized properly just a while ago. That turned out to be incorrect, didn't it?
Peeking at my javadocs, I don't see a four-argument ctor for JOptionPane that takes an int as the fourth argument.
My next idea is to suggest that you remove that first 'null' from the argument list and assign a sensible output message to 'output':
output = "Something informative";
JOptionPane.showMessageDialog(output,"Information",JOptionPane.INFORMATION_MESSAGE);Why don't you declare the output String closer to the JOptionPane? Narrow scope is a good thing.
Other advice? Stop tearing at your hair every time you get a Java error. You'll be bald soon. Read the javadocs more often. Stop assuming that everything you do is correct and that the machine is persecuting you. Doubt yourself more. - MOD