In list problem

Question

Dear All,
I have several id values with a comma separator in a column named matched_id like this 33577,33588,36987,62731 in a table named tab2. Then I am writing a query as follows:
select emp_id,name
from tab1
where to_char(emp_id) in(select matched_id from tab2 where id=1)
But it does not return me any value.matched_id column have the id of tab1 with comma separator.
TAB1 (EMP_ID number, NAME varchar2(100))
TAB2 (ID NUMBER,MATCHED_ID VARCHAR2(200))
Can anyone please help me to solve this problem.
Best Regards,

Answer 1

Try this
SQL> set lines 10000
SQL> select * from scott.emp;
     EMPNO ENAME      JOB              MGR HIREDATE         SAL       COMM     DEPTNO
      7369 SMITH      CLERK           7902 17-DEC-80        800                    20
      7499 ALLEN      SALESMAN        7698 20-FEB-81       1600        300         30
      7521 WARD       SALESMAN        7698 22-FEB-81       1250        500         30
      7566 JONES      MANAGER         7839 02-APR-81       2975                    20
      7654 MARTIN     SALESMAN        7698 28-SEP-81       1250       1400         30
      7698 BLAKE      MANAGER         7839 01-MAY-81       2850                    30
      7782 CLARK      MANAGER         7839 09-JUN-81       2450                    10
      7788 SCOTT      ANALYST         7566 19-APR-87       3000                    20
      7839 KING       PRESIDENT            17-NOV-81       5000                    10
      7844 TURNER     SALESMAN        7698 08-SEP-81       1500          0         30
      7876 ADAMS      CLERK           7788 23-MAY-87       1100                    20
     EMPNO ENAME      JOB              MGR HIREDATE         SAL       COMM     DEPTNO
      7900 JAMES      CLERK           7698 03-DEC-81        950                    30
      7902 FORD       ANALYST         7566 03-DEC-81       3000                    20
      7934 MILLER     CLERK           7782 23-JAN-82       1300                    10
14 rows selected.
SQL> select * from t;
COL
7900,7902,7934
SQL> select
  2     empno,
  3     ename
  4  from
  5     scott.emp
  6  where
  7     (select ','||col||',' from t) like '%,'||to_char(empno)||',%' ;
     EMPNO ENAME
      7900 JAMES
      7902 FORD
      7934 MILLER
SQL> But your database is not normalized.