In OAF, How to get the DFF Attributes bean in the PR of the controller

Question

Hi All,
I am not able to get the holder of the Descriptive Flex Field bean attributes in the processrequest method of the controller. Any idea, how to get it?
my Code Snippet:
OADescriptiveFlexBean oadescriptiveflexbean = (OADescriptiveFlexBean)webBean.findIndexedChildRecursive("AdditionalAttributes");
if(oadescriptiveflexbean != null)
System.out.println("oadescriptiveflexbean is not null);
OAWebBean bean1 = (OAWebBean) oadescriptiveflexbean.findIndexedChildRecursive("AdditionalAttributes1");
System.out.println("bean1 "+bean1);
It is going inside the IF condition. But, it displaying the bean1 value as null.
Regards,
Soorya

Answer 1

Hi,
You cannot reorder the dffbeans. In DFF setup definition itself, you have to maintain the sequence of the fields.
DFF beans are listed under flow layout by default. Following note from OA Framework developer guide
++++
Altering the Flexfield UI LayoutNote:
This is not recommended by the OA Framework team and may cause problems with PPR.
If you want to do something unusual with the descriptive flexfield UI layout (like insert a button after every segment or move the segments around), you need to follow these steps:
Find the OADescriptiveFlexBean by attribute name and call the processFlex method on OADescriptiveFlexBean. After this, you will be creating the flexfield segment web beans based on metadata and the view object attribute.
Call the getIndexedChild(int)method on the flexfield web bean to go through all the child of the flexfield and alter the layout as desired.
++++
Regards,
Soorya