Increase in price, yearly.. and calculate the difference between the years.

Question

Hi everyone
I need to make the following code show how many years it took for it to reach its required goal.
show difference between the years and how much money increased ever year. ..
I am totally confused at the moment... any help would be greatly appreciated...
declare
a number(9):=1000;
b number(9);
c number(9);
d number(9);
begin
for d in 2012..2099
loop
dbms_output.put_line(a||' '||d);
if a >2000 then
exit;
end if;
a :=a + a*10/100;
end loop;
end;
Result for above query:
Price Years
1000 2012
1100 2013
1200 2014 etc...
I need to show the amount of years it took to reach its goal, which was $2000
and also the change in price, how much it increased every year...
Thanks
Umair

Answer 1

Hi Umair ,
I am not sure why you have created so many different variables. ( b , c , d )
Try this
declare
    a                number(9)  :=1000;
    cnt              number      := 0;
begin
    for d in 2012..2099 loop
        if a > 2000 then    
            exit;
        end if;
        dbms_output.put_line(a||'   '||d);
        a :=a + a*10/100;
        cnt := cnt + 1;
    end loop;
    dbms_output.put_line( 'Number of years required to reach the goal are:- ' || to_number(cnt) );
end;
/If you want to show number of years in yyyy way ( example :- 2020) then set cnt to 2012 as for loop is starting with 2012.
Thanks.