Incrementing an array variable!!!

Question

Hello,
I wanna know if we can increment an array variable by more than 1.
When I use for(i=0;i<10;i+4) it is giving me an error.Just wanted to know if we can increment an array variable by any value other than 1.
Thanks

Answer 1

Your are right, I see that thank you
Ok sorry guys for pasting the assignment. I have done some thing but me not sure weather I am doing right way or not. here is my code. And by the way how to return the integer to the main function "public static void main(String args[]){" from static integer function "static int isCentered(int[] a){"
Code for Q. 1)
Out put:
{1,2,3,4,5} => 0(the middle element 3 is not strictly less than all other elements)
{3,2,1,4,5} => 1(the middle element 1 is strictly less than all other elements)=>
{3,2,1,4,1} => 0(the middle element 1 is strictly less than all other elements)
{3,2,1,14,6} => 0(no middle element since array has even number of elements)
{} => 0(no middle element)
{1} => 1(satisfies the condition vacuously)
import java.io.*;
public class isCenteredArray{
public static void main(String args[]){
isCentered(new int[]{1, 2, 3, 4, 5});
isCentered(new int[]{3, 2, 1, 4, 5});
isCentered(new int[]{3, 2, 1, 4, 1});
isCentered(new int[]{3, 2, 1, 1, 4, 6});
isCentered(new int[]{});
isCentered(new int[]{1});
static int isCentered(int[] a){
int ar=0;
if(a.length%2 ==0){
  return ar;     
int j=1;     
for (int i=0; i<a.length; i++){
if(j != a.length/2){
if(a[i] > a[a.length/2]){
ar = 1;
}else{
ar = 0;
return ar;     
j=j+1;     }     
return ar;           
Code for Q. 2)
Out put:
{1,2,3,0} => 1(because 1+2 = =3+0= =3)
{1,2,2,1,3,0} => 1(because 1+2 = =2+1= =3+0= =3)
{1,1,2,2} => 0(because 1+1 = =2 != 2+2)
{1,2,1} => 0(because array does not have any even number of elements)
{} => 1
import java.io.*;
public class isDualArray{
public static void main(String args[]){
isDual(new int[]{1, 2, 3, 0});
isDual(new int[]{1, 2, 2, 1, 3, 0});
isDual(new int[]{1, 1, 2, 2});
isDual(new int[]{1, 2, 1});
isDual(new int[]{});
static int isDual(int[] a){
int ar=0;
for(int i=0; i<=a.length; i++){
if(i%2 !=0){
if((a[i-1] + a) == a[i+1]){
ar = 1;     
}else{
ar = 0;     
return ar;
return ar;     
Code for Q. 3)
Out put:
{1} => 1(true vacuously)
{2} => 0(contains no odd elements)
{1,1,1,1,1,1} => 1
{2,4,6,8,11} => 1
{-2,-4,-6,-8,-11} => 0
import java.io.*;
public class idOddHeavyArray{
public static void main(String args[]){
isOddHeavy(new int[]{1});
isOddHeavy(new int[]{2});
isOddHeavy(new int[]{1, 1, 1, 1, 1, 1});
isOddHeavy(new int[]{2, 4, 6, 8, 11});
isOddHeavy(new int[]{-2, -4, -6, -8, -11});
static int isOddHeavy(int[] a){
int ar=0;
int oddheavynumber=0;
for (int i=0; i<a.length; i++){
if(a>oddheavynumber){
oddheavynumber = a[i];     
     }else{
oddheavynumber=oddheavynumber;          
if(oddheavynumber%2==0){
ar=0;     
     }else{
ar=1;          
System.out.println(ar);
return ar;          
Please check the way out how I did and let me know if I am going the wrong way...
Thanks,
Indoman