InfoCube F table & E table for Bex

Hello All,
Could someone help me with the following,
1. Bex access the records from F-table or E- Table of InfoCube?
2. If Accessing from E- table is true, do we have to move the records from F table to E table in-order to make the records available for reporting?
3. when we do roll-up in InfoCube maintenance, records are moved to aggregates? or  moved from F table to E table?
your responses are appreciated with points.
Thanks

hi,
1. Bex access the records from F-table or E- Table of InfoCube?
Ans - If the cube is not compressed it takes from F table, if fully compressed it takes from E table, partial compression - both F and E.
2. If Accessing from E- table is true, do we have to move the records from F table to E table in-order to make the records available for reporting?
Ans - E table will have data once you do compression, and compression is not mandatory for all the cases. try using aggregates for reports.
3. when we do roll-up in InfoCube maintenance, records are moved to aggregates? or moved from F table to E table?
Ans- Moved from cube to aggregates.
Ramesh

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    PARTITION Text_Part_L VALUES LESS THAN ('M') PCTFREE 0 TABLESPACE Firewire Storage (Initial 10M Next 1M PCTIncrease 0),
    PARTITION Text_Part_M VALUES LESS THAN ('N') PCTFREE 0 TABLESPACE Firewire Storage (Initial 10M Next 1M PCTIncrease 0),
    PARTITION Text_Part_N VALUES LESS THAN ('O') PCTFREE 0 TABLESPACE Firewire Storage (Initial 10M Next 1M PCTIncrease 0),
    PARTITION Text_Part_O VALUES LESS THAN ('P') PCTFREE 0 TABLESPACE Firewire Storage (Initial 10M Next 1M PCTIncrease 0),
    PARTITION Text_Part_P VALUES LESS THAN ('Q') PCTFREE 0 TABLESPACE Firewire Storage (Initial 10M Next 1M PCTIncrease 0),
    PARTITION Text_Part_Q VALUES LESS THAN ('R') PCTFREE 0 TABLESPACE Firewire Storage (Initial 10M Next 1M PCTIncrease 0),
    PARTITION Text_Part_R VALUES LESS THAN ('S') PCTFREE 0 TABLESPACE Firewire Storage (Initial 10M Next 1M PCTIncrease 0),
    PARTITION Text_Part_S VALUES LESS THAN ('T') PCTFREE 0 TABLESPACE Firewire Storage (Initial 10M Next 1M PCTIncrease 0),
    PARTITION Text_Part_T VALUES LESS THAN ('U') PCTFREE 0 TABLESPACE Firewire Storage (Initial 10M Next 1M PCTIncrease 0),
    PARTITION Text_Part_U VALUES LESS THAN ('V') PCTFREE 0 TABLESPACE Firewire Storage (Initial 10M Next 1M PCTIncrease 0),
    PARTITION Text_Part_V VALUES LESS THAN ('W') PCTFREE 0 TABLESPACE Firewire Storage (Initial 10M Next 1M PCTIncrease 0),
    PARTITION Text_Part_W VALUES LESS THAN ('X') PCTFREE 0 TABLESPACE Firewire Storage (Initial 10M Next 1M PCTIncrease 0),
    PARTITION Text_Part_X VALUES LESS THAN ('Y') PCTFREE 0 TABLESPACE Firewire Storage (Initial 10M Next 1M PCTIncrease 0),
    PARTITION Text_Part_Y VALUES LESS THAN ('Z') PCTFREE 0 TABLESPACE Firewire Storage (Initial 10M Next 1M PCTIncrease 0),
    PARTITION Text_Part_Z VALUES LESS THAN (MAXVALUE) PCTFREE 0 TABLESPACE Firewire Storage (Initial 10M Next 1M PCTIncrease 0))
    NOLOGGING PARALLEL -- FLASHBACK ARCHIVE IOT_Flashback_Data
    This errors out with the following...
    SQL Error: ORA-25182: feature not currently available for index-organized tables
    25182. 00000 - "feature not currently available for index-organized tables"
    *Cause:    An attempt was made to use one or more of the following feature(s) not
    currently supported for index-organized tables:
    CREATE TABLE with LOB/BFILE/VARRAY columns,
    partitioning/PARALLEL/CREATE TABLE AS SELECT options,
    ALTER TABLE with ADD/MODIFY column options, CREATE INDEX
    *Action:   Do not use the disallowed feature(s) in this release.
    6) Re-running the create table statement in step 5 without the MAPPING TABLE clause works fine. Not surprisingly an attempt to create a secondary local bitmap index on this table fails as there's no mapping table, like so...
    CREATE BITMAP INDEX IOTObj_Table_BMI1 ON IOTObj_Table (numberData)
    LOCAL STORAGE (INITIAL 1M PCTINCREASE 0 NEXT 512K) NOLOGGING PARALLEL;
    CREATE TABLE with LOB/BFILE/VARRAY columns,
    partitioning/PARALLEL/CREATE TABLE AS SELECT options,
    ALTER TABLE with ADD/MODIFY column options, CREATE INDEX
    *Action:   Do not use the disallowed feature(s) in this release.
    CREATE BITMAP INDEX IOTObj_Table_BMI1 ON IOTObj_Table (numberData)
    LOCAL STORAGE (INITIAL 1M PCTINCREASE 0 NEXT 512K) NOLOGGING PARALLEL
    Error at Command Line:99 Column:13
    Error report:
    SQL Error: ORA-00903: invalid table name
    00903. 00000 - "invalid table name"
    7) Creating a secondary local b-tree index is fine, like so...
    SQL> CREATE INDEX IOTObj_Table_I1 ON IOTObj_Table (numberData)
    LOCAL STORAGE (INITIAL 1M PCTINCREASE 0 NEXT 512K) NOLOGGING PARALLEL;
    index IOTOBJ_TABLE_I1 created.
    8) A quick test to ensure object table ok...
    SQL> INSERT INTO IOTObj_Table VALUES (IOT_Type('DEF456',500));
    SQL> 1 rows inserted.
    SQL> SELECT * FROM IOTObj_Table;
    TEXTDATA NUMBERDATA
    DEF456     500

    Thanks Dan,
    the intention is to range partition based on the initial character, so A* -> Text_Part_A, B* -> Text_Part_B, and so on.
    Here's an example, using an empty IOTObj_Table as created previously.
    1) Set up & confirm some test data (two 'D's, one 'N', and two 'Z's)
    SQL> INSERT INTO IOTObj_Table VALUES (IOT_Type('DEF456',500));
    SQL> INSERT INTO IOTObj_Table VALUES (IOT_Type('DDD111',510));
    SQL> INSERT INTO IOTObj_Table VALUES (IOT_Type('N3000',515));
    SQL> INSERT INTO IOTObj_Table VALUES (IOT_Type('ZZ1212',520));
    SQL> INSERT INTO IOTObj_Table VALUES (IOT_Type('Z111X',530));
    SQL> COMMIT;
    SQL> SELECT * FROM IOTObj_Table;
    TEXTDATA NUMBERDATA
    DDD111     510
    DEF456     500
    N3000     515
    Z111X     530
    ZZ1212     520
    2) Just to prove our IOT is enforcing the Primary Key based on the TextData attribute, try to insert a duplicate
    SQL> INSERT INTO IOTObj_Table VALUES (IOT_Type('Z111X',530));
    Error starting at line 141 in command:
    INSERT INTO IOTObj_Table VALUES (IOT_Type('Z111X',530))
    Error report:
    SQL Error: ORA-00001: unique constraint (OCDataSystems.SYS_IOT_TOP_84235) violated
    00001. 00000 - "unique constraint (%s.%s) violated"
    *Cause:    An UPDATE or INSERT statement attempted to insert a duplicate key.
    For Trusted Oracle configured in DBMS MAC mode, you may see
    this message if a duplicate entry exists at a different level.
    *Action:   Either remove the unique restriction or do not insert the key.
    3) Now confirm that our data has been slotted into the range-based partition we expect using the PARTITION clause of SELECT...
    - The two 'D's...
    SQL> SELECT * FROM IOTObj_Table PARTITION (Text_Part_D);
    TEXTDATA NUMBERDATA
    DDD111     510
    DEF456     500
    - The single 'N'...
    SQL> SELECT * FROM IOTObj_Table PARTITION (Text_Part_N);
    TEXTDATA NUMBERDATA
    N3000     515
    - The two 'Z's...
    SQL> SELECT * FROM IOTObj_Table PARTITION (Text_Part_Z);
    TEXTDATA NUMBERDATA
    Z111X     530
    ZZ1212     520
    4) And to wrap up confirm an empty partition
    SELECT * FROM IOTObj_Table PARTITION (Text_Part_W);

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