INI: XOQ-01600: OLAP DML Error "ORA-01438: value larger than specified prec
I have created a Time dimension in AWM 11.1.0.7.0B.
I have added two Hierarchies to it. One Hierarchy has All Years, Year, Week, day. The second hierarchy has All Years, Year, Quarter.
When I maintain the dimension, the following error occurs:
An error has occurred on the server
Error class: Express Failure
Server error descriptions:
INI: Error creating a definition manager, Generic at TxsOqConnection::generic<BuildProcess>
INI: XOQ-01600: OLAP DML Error "ORA-01438: value larger than specified precision allowed for this column
" while executing DML "SYS.AWXML!R11_LOAD_DIM('TIME.ALL_GREGORIAN_YEARS.LEVEL' SYS.AWXML!___R11_LONG_ARG_VALUE(SYS.AWXML!___R11_LONG_ARG_DIM 1) 'TIME.END_DATE.ATTRIBUTE' 'TIME.TIME_SPAN.ATTRIBUTE' 'TIME.LONG_DESCRIPTION.ATTRIBUTE' 'TIME.SHORT_DESCRIPTION.ATTRIBUTE' 'TIME.ALL_GREGORIAN_YEARS_END_DATE.ATTRIBUTE' 'TIME.ALL_GREGORIAN_YEARS_TIME_SPA.ATTRIBUTE' 'TIME.ALL_GREGORIAN_YEARS_LONG_DES.ATTRIBUTE' 'TIME.ALL_GREGORIAN_YEARS_SHORT_DE.ATTRIBUTE' 'TIME.ALL_GREGORIAN_YEARS_TIME_SPA1.ATTRIBUTE' 'TIME.ALL_GREGORIAN_YEARS_TIME_SPA2.ATTRIBUTE' 'TIME.ALL_GREGORIAN_YEARS_TIME_SPA3.ATTRIBUTE' 'TIME.ALL_GREGORIAN_YEARS_LONG_DES1.ATTRIBUTE' 'TIME.ALL_GREGORIAN_YEARS_SHORT_DE1.ATTRIBUTE' 'TIME.ALL_GREGORIAN_YEARS_TIME_SPA4.ATTRIBUTE' 'TIME.ALL_GREGORIAN_YEARS_LONG_DES2.ATTRIBUTE' 'TIME.ALL_GREGORIAN_YEARS_SHORT_DE2.ATTRIBUTE' 'TIME.GREGORIAN_QUARTER_END_DATE.ATTRIBUTE' 'TIME.GREGORIAN_QUARTER_TIME_SPAN.ATTRIBUTE' 'TIME.GREGORIAN_QUAOLAP DML Error "%(1)s" while executing DML "%(2)s", Generic at TxsOqStdFormCommand::execute
at oracle.olapi.data.source.DataProvider.callGeneric(Unknown Source)
at oracle.olapi.data.source.DataProvider.callGeneric(Unknown Source)
at oracle.olapi.data.source.DataProvider.executeBuild(Unknown Source)
at oracle.olap.awm.wizard.awbuild.UBuildWizardHelper$1.construct(Unknown Source)
at oracle.olap.awm.ui.SwingWorker$2.run(Unknown Source)
at java.lang.Thread.run(Thread.java:595)
The most likely explanation is that you have a numeric attribute whose data type precision is less than that of the column it is mapped to. For example if you had an attribute with data type NUMBER(2) and you mapped it to a column with data type NUMBER(5), then you could get this error on load. Note that some of the attributes may not be visible in AWM. The offending SQL statement should be in the OUTPUT column of the CUBE_BUILD_LOG, but you may be able to fix this by just describing the view associated with the dimension. For example, here is the description of a TIME view created in 11.2..
Name Null? Type
DIM_KEY VARCHAR2(60)
LEVEL_NAME VARCHAR2(30)
MEMBER_TYPE VARCHAR2(1)
DIM_ORDER NUMBER
END_DATE DATE
TIME_SPAN NUMBER
LONG_DESCRIPTION VARCHAR2(60 CHAR)
SHORT_DESCRIPTION VARCHAR2(60 CHAR)
MONTH_END_DATE DATE
MONTH_TIME_SPAN NUMBER(5)
MONTH_LONG_DESCRIPTION VARCHAR2(60 CHAR)
MONTH_SHORT_DESCRIPTION VARCHAR2(60 CHAR)
FISCAL_QUARTER_END_DATE DATE
FISCAL_QUARTER_TIME_SPAN NUMBER(5)
FISCAL_QUARTER_LONG_DESC VARCHAR2(60 CHAR)
FISCAL_QUARTER_SHORT_DES VARCHAR2(60 CHAR)
FISCAL_YEAR_END_DATE DATE
FISCAL_YEAR_TIME_SPAN NUMBER(5)
FISCAL_YEAR_LONG_DESCRIP VARCHAR2(60 CHAR)
FISCAL_YEAR_SHORT_DESCRI VARCHAR2(60 CHAR)
CALENDAR_QUARTER_END_DAT DATE
CALENDAR_QUARTER_TIME_SP NUMBER(5)
CALENDAR_QUARTER_LONG_DE VARCHAR2(60 CHAR)
CALENDAR_QUARTER_SHORT_D VARCHAR2(60 CHAR)
CALENDAR_YEAR_END_DATE DATE
CALENDAR_YEAR_TIME_SPAN NUMBER(5)
CALENDAR_YEAR_LONG_DESCR VARCHAR2(60 CHAR)
CALENDAR_YEAR_SHORT_DESC VARCHAR2(60 CHAR)You can get the same information from user_cube_attributes
SQL> select attribute_name, data_precision from user_cube_attributes where dimension_name = 'TIME' and data_type = 'NUMBER';
ATTRIBUTE_NAME DATA_PRECISION
TIME_SPAN
MONTH_TIME_SPAN 5
FISCAL_QUARTER_TIME_SPAN 5
FISCAL_YEAR_TIME_SPAN 5
CALENDAR_QUARTER_TIME_SPAN 5
CALENDAR_YEAR_TIME_SPAN 5
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As CDC is built on top of Oracle streams framework, for better responses you can post this ques under {forum:id=70} category.
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The Apexlib doesn't work, since I have some conditional regions on that particular page!
Thanks for posting your thoughts and hints.
Regards,
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simply create a validation and check the length of user input.
brgds,
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Work: http://www.click-click.at
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SQL Error: ORA-12899: value too large for column
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I'm trying to understand the above error. It occurs when we are migrating data from one oracle database to another:
Error report:
SQL Error: ORA-12899: value too large for column "USER_XYZ"."TAB_XYZ"."COL_XYZ" (actual: 10, maximum: 8)
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I am getting error "ORA-12899: value too large for column".
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This happens randomly not everytime.
select * from v$version
Oracle Database 10g Enterprise Edition Release 10.2.0.4.0 - 64bi
PL/SQL Release 10.2.0.4.0 - Production
CORE 10.2.0.4.0 Production
TNS for Linux: Version 10.2.0.4.0 - Production
NLSRTL Version 10.2.0.4.0 - Production
Table Structure
desc customer
Name Null? Type
CTRY_CODE NOT NULL CHAR(3 Byte)
CO_CODE NOT NULL CHAR(3 Byte)
CUST_NBR NOT NULL NUMBER(10)
CUST_NAME CHAR(40 Byte)
RECORD_STATUS CHAR(1 Byte)
Trigger on the table
CREATE OR REPLACE TRIGGER CUST_INSUPD
BEFORE INSERT OR UPDATE
ON CUSTOMER FOR EACH ROW
BEGIN
IF INSERTING THEN
:NEW.RECORD_STATUS := 'I';
ELSIF UPDATING THEN
:NEW.RECORD_STATUS := 'U';
END IF;
END;
ERROR at line 1:
ORA-01001: invalid cursor
ORA-06512: at "UPDATE_CUSTOMER", line 1320
ORA-12899: value too large for column "CUSTOMER"."RECORD_STATUS" (actual: 3,
maximum: 1)
ORA-06512: at line 1
Edited by: user4211491 on Nov 25, 2009 9:30 PM
Edited by: user4211491 on Nov 25, 2009 9:32 PMSQL> create table customer(
2 CTRY_CODE CHAR(3 Byte) not null,
3 CO_CODE CHAR(3 Byte) not null,
4 CUST_NBR NUMBER(10) not null,
5 CUST_NAME CHAR(40 Byte) ,
6 RECORD_STATUS CHAR(1 Byte)
7 );
Table created.
SQL> CREATE OR REPLACE TRIGGER CUST_INSUPD
2 BEFORE INSERT OR UPDATE
3 ON CUSTOMER FOR EACH ROW
4 BEGIN
5 IF INSERTING THEN
6 :NEW.RECORD_STATUS := 'I';
7 ELSIF UPDATING THEN
8 :NEW.RECORD_STATUS := 'U';
9 END IF;
10 END;
11 /
Trigger created.
SQL> insert into customer(CTRY_CODE,CO_CODE,CUST_NBR,CUST_NAME,RECORD_STATUS)
2 values('12','13','1','Mahesh Kaila','UPD');
values('12','13','1','Mahesh Kaila','UPD')
ERROR at line 2:
ORA-12899: value too large for column "HPVPPM"."CUSTOMER"."RECORD_STATUS"
(actual: 3, maximum: 1)
SQL> insert into customer(CTRY_CODE,CO_CODE,CUST_NBR,CUST_NAME)
2 values('12','13','1','Mahesh Kaila');
1 row created.
SQL> set linesize 200
SQL> select * from customer;
CTR CO_ CUST_NBR CUST_NAME R
12 13 1 Mahesh Kaila I
SQL> update customer set cust_name='tst';
1 row updated.
SQL> select * from customer;
CTR CO_ CUST_NBR CUST_NAME R
12 13 1 tst Urecheck your code once again..somewhere you are using record_status column for insertion or updation.
Ravi Kumar -
Replicat error: ORA-12899: value too large for column ...
Hi,
In our system Source and Target are on the same physical server and in the same Oracle instance. Just different schemes.
Tables on the target were created as 'create table ... as select * from ... source_table', so they have a similar structure. Table names are also similar.
I started replicat, it worked fine for several hours, but when I inserted Chinese symbols into the source table I got an error:
WARNING OGG-00869 Oracle GoldenGate Delivery for Oracle, OGGEX1.prm: OCI Error ORA-12899: value too large for column "MY_TARGET_SCHEMA"."TABLE1"."*FIRSTNAME*" (actual: 93, maximum: 40) (status = 12899), SQL <INSERT INTO "MY_TARGET_SCHEMA"."TABLE1" ("USERID","USERNAME","FIRSTNAME","LASTNAME",....>.
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I've double checked tables structure on the target - it's identical with the source.
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How to fix this error?
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Oracle GoldenGate version: 11.1.1.1
Oracle Database version: 11g Enterprise Edition Release 11.2.0.2.0 - 64bit Production
NLS_LANG: AMERICAN_AMERICA.AL32UTF8
NLS_LENGTH_SEMANTICS='CHAR'
Edited by: DeniK on Jun 20, 2012 11:49 PM
Edited by: DeniK on Jun 23, 2012 12:05 PM
Edited by: DeniK on Jun 25, 2012 1:55 PMI've created the definition files and compared them. They are absolutely identical, apart from source and target schema names:
Source definition file:
Definition for table MY_SOURCE_SCHEMA.TABLE1
Record length: 1632
Syskey: 0
Columns: 30
USERID 134 11 0 0 0 1 0 8 8 8 0 0 0 0 1 0 1 3
USERNAME 64 80 12 0 0 1 0 80 80 0 0 0 0 0 1 0 0 0
FIRSTNAME 64 160 98 0 0 1 0 160 160 0 0 0 0 0 1 0 0 0
LASTNAME 64 160 264 0 0 1 0 160 160 0 0 0 0 0 1 0 0 0
PASSWORD 64 160 430 0 0 1 0 160 160 0 0 0 0 0 1 0 0 0
TITLE 64 160 596 0 0 1 0 160 160 0 0 0 0 0 1 0 0 0
Target definition file:
Definition for table MY_TAEGET_SCHEMA.TABLE1
Record length: 1632
Syskey: 0
Columns: 30
USERID 134 11 0 0 0 1 0 8 8 8 0 0 0 0 1 0 1 3
USERNAME 64 80 12 0 0 1 0 80 80 0 0 0 0 0 1 0 0 0
FIRSTNAME 64 160 98 0 0 1 0 160 160 0 0 0 0 0 1 0 0 0
LASTNAME 64 160 264 0 0 1 0 160 160 0 0 0 0 0 1 0 0 0
PASSWORD 64 160 430 0 0 1 0 160 160 0 0 0 0 0 1 0 0 0
TITLE 64 160 596 0 0 1 0 160 160 0 0 0 0 0 1 0 0 0
Edited by: DeniK on Jun 25, 2012 1:56 PM
Edited by: DeniK on Jun 25, 2012 1:57 PM -
File_To_RT data truncation ODI error ORA-12899: value too large for colum
Hi,
Could you please provide me some idea so that I can truncate the source data grater than max length before inserting into target table.
Prtoblem details:-
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Thanks
AnindyaBhabani wrote:
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ERROR ITMS-9000: "Images larger than 2000000 pixels are not allowed in books
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ERROR ITMS-9000: "Images larger than 2000000 pixels are not allowed in books
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I have an article for you here that can help you with that issue. The article is all about adding images to your books, and can be found here:
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http://support.apple.com/kb/PH2797
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How do you find your blocked numbers in Contacts or on your iphone?
How do you find your blocked numbers in Contacts or on your iphone? Is there a way to get a list of the blocked numbers?
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Remove 0's after decimal.
Hi, I have column value which returns values something like 123456.78 . This is sales information. I want the value to be returned something like this. "123,456". No 0's after decimal. The datatype for field stored in DB is Money. Can you any one he
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Disable "Ledger Group" in FBB1
Hi, I've performed the t code FAGLF101 for Accounts Payable, using the Sort Method "SAP". Using this sort method, the batch input session that is created gets the Ledger Group as "0L", which is the default ledger. In my case, I won't post anything in
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10.4.6 - SLOW INTERNET
I'm going nuts trying to figure this out...but ever since I installed 10.4.6 my internet has been running slower than ever. It's happening in ALL BROWSERS as well as iTunes and anything else that is powered by the internet. I hear this is happening t
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Performance OSX "Snow Leopard" vs. Windows 7
Hello, after a few days of experience with CP5 on OSX I've loaded the Windows Version of CP5 as a part of ELS2. After installation I start CP 5 in a virtual machine. The VM has 2 processors from 4 in core i7 an 2GB RAM of 8GB on a MacBook Pro. Now I