Inserting into Linked table

I am writing some code to copy some data from point A (the client's Oracle database) to point B (the client's DB/2 database). I'm trying to determine the least problematic way of dealing with the inserts to a heterogeneously linked table and updates to the source table.
Working in an ideal world, in one transaction I would insert each row to the linked table and mark the source row as "processed". Each source row produces one target row, and the commit would happen after each row. Will this work and can it be relied upon to commit and/or rollback together, even if the link goes down? My other option, which I've seen done in several pieces of code that we have in our organization, is to perform all actions in local tables, and then at the last minute in a separate transaction, do a bulk copy "insert into tableA select from tableB". Most of these examples are moving data FROM the external table TO our internal database and then processing them.
So my question is, is it always a good idea to do this bulk copy method, or is it mostly necessary only when you're NOT committing after each row? Or is it dependent on what sort of external database you're linking to? If I'm to add an extra "staging" table, then I also have to deal with deleting the rows after they're inserted in to the linked table, and figuring out how to deal with the possibility that this job might be running twice at the same time. So I'd like to avoid it if I can. But if it's all around safer to use an extra table, I will.
Thanks for your thoughts!
Christine Wolak

Kamal, from the example you gave, the table you're inserting into is named "[email protected]", right? That sounds like an Oracle instance. This apparently works fine Oracle-to-Oracle, but not so much when the other side of the link is a different kind of database. In my case, I'm trying to copy the data to a DB2 table. From the text I've seen, the way the "insert into ... select from ..." works, is the TARGET database has to know how to do the "select from" part, and if it's not an Oracle database, there's no guarantee that it can.
I've also found that I cannot even have a distributed transaction of any kind (without buying Oracle's Transparent Gateway Services, I think). I've tried committing my updates of my own table and insert into a remote table from within the same transaction, and I get ORA-02047 (cannot join the distributed transaction).
So it looks like I will be stuck not only copying the rows one by one, but also "crossing my fingers" that my second transaction goes through. Actually, I'm planning something like this:
1. Do my updates in my local table, including setting the "complete" flag to Yes, and commit.
2. Do the insert into the remote table, and commit.
3. If the insert gets an error, change the "complete" flag back to No (so it'll get picked up the next time around), and commit. If THIS step gets an error, I'll log a message indicating that operator intervention is required.
I'm guessing that 99.999% of the time this will run without a hitch, and I think that's pretty much all I can ask for, without buying Transparent Gateway. Unless someone else here as a better suggestion? I'm all ears...
Christine

Similar Messages

How to insert into 2 tables from the same page (with one button link)

Hi,
I have the following 2 tables....
Employees
emp_id number not null
name varchar2(30) not null
email varchar2(50)
hire_date date
dept_id number
PK = emp_id
FK = dept_id
Notes
note_id number not null
added_on date not null
added_by varchar2(30) not null
note varchar2(4000)
emp_id number not null
PK = note_id
FK = emp_id
I want to do an insert into both tables via the application and also via the same page (with one button link). I have made a form to add an employee with an add button - adding an employee is no problem.
Now, on the same page, I have added a html text area in another region, where the user can write a note. But how do I get the note to insert into the Notes table when the user clicks the add button?
In other words, when the user clicks 'add', the employee information should be inserted into the Employees table and the note should be inserted into the Notes table.
How do I go about doing this?
Thanks.

Hi,
These are my After Submit Processes...
After Submit
30     Process Row of NOTES     Automatic Row Processing (DML)     Unconditional
30     Process Row of EMPLOYEES     Automatic Row Processing (DML)     Unconditional
40     reset page     Clear Cache for all Items on Pages (PageID,PageID,PageID)     Unconditional
40     reset page     Clear Cache for all Items on Pages (PageID,PageID,PageID)     Unconditional
40     reset page     Clear Cache for all Items on Pages (PageID,PageID,PageID)     Unconditional
40     reset page     Clear Cache for all Items on Pages (PageID,PageID,PageID)     Unconditional
50     Insert into Tables     PL/SQL anonymous block     Conditional
My pl/sql code is the same as posted earlier.
Upon inserting data into the forms and clicking the add button, I get this error...
ORA-06550: line 1, column 102: PL/SQL: ORA-00904: "NOTES": invalid identifier ORA-06550: line 1, column 7: PL/SQL: SQL Statement ignored
     Error      Unable to process row of table EMPLOYEES.
Is there something wrong with the pl/sql code or is it something else?

Insert data into linked table

Problem when you try to insert data into linked table.
I made the view with all linked table columns (field1 is PK, field2, field3......) plus new primary key field "field1_PK" for tabular form wizard primary key field definition. After submit data on tabular form appears:
"Error in mru internal routine:ORA-2001:Error in MRU: row=1,ORA-00957: duplicate column name ORA-02063:preciding line from "SHEMA_NAME", insert into "field1","field1_PK","field3",........) values (:b1,:b2,:b3.........)
Error Unable to process update.
Is it bug too?

Hi,
Have you tried to do your updates using an INSTEAD OF TRIGGER on your view? An INSTEAD OF TRIGGER allows you to update a non-updateable view.
The following book contains an excellent introduction to this topic.
"Oracle PL/SQL for Dummies"
written by Rosenblum and Dorsey
published by Wiley Publishing Inc.
The following book is also excellant reference that deals with INSTEAD OF TRIGGERS.
"Oracle PL/SQL programming
written by Steven Feuerstein
published by O'Reilly
Hope this helps.
Cheers,
Patrick Cimolini

Link and insert into 2 tables

Hi Everyone,
I am building an application that that contains information about helpdesk calls. I am using 2 tables:
Table 1 contains tracking info- TRK_CALLS
ID -primary key
USER_
ASSIGNED_TO
PROBLEM
SOLUTION
STATUS
EDIT
Table 2 contain date and time info - TRKCALLS_TIME
ID - primary key
CALL_ID - same number as ID in table 1
DATE_
TIME
I have taken the advice that Denes Kubicek gave another poster and created a workspace at apex.oracle.com and places my app in there for others to look at
workspace: kjwebb
username: [email protected]
password: gtmuc
application: calltracking2
I have a report called create/edit call tracking in there that I can either Edit or create an entry into TRK_CALLS. clicking create takes me to a form, after info is entered I have a create button that assigns the PK and inserts info into TRK_CALLS. I then have to click Edit Call Time button to input info on a form that inserts into TRKCALLS_TIME table. I would like to link these tables somehow so that when I go to the (Edit Call Time) form the Call ID is populated with the PK ID from the TRK_CALLS table.
It would be easier to insert this info all in one page but I worked on that for a long time before giving up because I could not get anything to insert into the tables so I have taken this route.
The basic desired outcome is to tie the tables with a PK, ID in table 1 and CALL_ID in table 2. So that they correspond and displayed on the report page.
Please help in any way you can and make changes to my app.
I would not be asking for help unless I have reached the ends of my apex knowledge.
Thanks and please let me know if there are any questions,
Kirk

I can imagine it is pretty obscure when your knowledge of PL/SQL is not (yet) so big.
The statement I wrote ar meant exactly for your situation.
OK, here we go:
First you have created a view in the Object Browser. Suppose it is called trkcalls_view .
Then you go to SQL Workshop > SQL Commands.
You cut the next statement and paste it in the upper white part of the screen, just under the autocommit checkbox. Replace the bold sequence references by the real name of the sequences that are used to populate the ID's of the two tables.
You say Run and the trigger is created.
A trigger on the view is created. Creation of such a trigger is not possible in the Object Browser, so I understand your confusion. This triggers performs when an insert in the view is performed. As you might see in the code, it creates seperate insert statements for both tables.
CREATE OR REPLACE TRIGGER bi_trkcalls_view
INSTEAD OF UPDATE ON trkcalls_view
REFERENCING NEW AS NEW OLD AS OLD
FOR EACH ROW
DECLARE
v_id number;
bv_id2 number;
BEGIN
select sequence1.nextval into v_id from dual;
select sequence2.nextval into v_id2 from dual;
INSERT INTO TRK_CALLS
( ID
, USER_ASSIGNED_TO
, PROBLEM
, SOLUTION
, STATUS
, EDIT
VALUES
( v_id
, :new.user_assigned_to
, :new.problem
, :new.solution
, :new.status
, :new.edit
insert into TRKCALLS_TIME
( id
, call_id
, date_time
values
( v_id2
, v_id
, :new.date_time
end;
END ;good luck,
DickDral

Insert into two tables, how to insert multiple slave records

Hi, I have a problem with insert into two tables wizard.
The wizard works fine and I can add my records, but I need to enter multiple slave table records.
My database:
table: paper
`id_paper` INTEGER(11) NOT NULL AUTO_INCREMENT,
`make` VARCHAR(20) COLLATE utf8_general_ci NOT NULL DEFAULT '',
`model` VARCHAR(20) COLLATE utf8_general_ci NOT NULL DEFAULT '',
`gsm` INTEGER(11) NOT NULL,
PRIMARY KEY (`id_paper`)
table: paper_data
`id_paper_data` INTEGER(11) NOT NULL AUTO_INCREMENT,
`id_paper` INTEGER(11) NOT NULL,
`value` DOUBLE(15,3) NOT NULL,
`nanometer` INTEGER(11) NOT NULL,
PRIMARY KEY (`id_paper_data`)
I need to add multiple fields "value" and "nanometer"
Current form looks like this:
Make:
Model:
Gsm:
Value:
nanometer:
I need it to look like this:
Make:
Model:
Gsm:
Value:
nanometer:
Value:
nanometer:
Value:
nanometer:
Value:
nanometer:
and so on.
The field "id_paper" in table paper_data needs to get same id for entire transaction. Also how do I set default values for each field "nanometer" on my form the must be different (370,380,390 etc)?
Thanks.

you can find an answer here: http://209.85.129.132/search?q=cache:PzQj57dsWmQJ:www.experts-exchange.com/Web_Development /Software/Macromedia_Dreamweaver/Q_23713792.html+Insert+Into+Two+Tables+Wizard&cd=3&hl=lt& ct=clnk&gl=lt
This is a copy of the post:
Hi experts,
Im using ADDT to design a page that needs to insert one record into a master ALBUMS table, along with three records into a GENRES table, all linked by the primary, auto-incremented ALBUMS. ALBUM_ID.
Ive tried many different ways of combining the Insert into Multiple Tables wizard and the insert record wizard with Link Transactions, all with no luck. Either only the album info gets inserted, or a ALBUM_ID cannot be null error from MySQL. Here is the structure of the tables
ALBUMS
ALBUM_ID, INT(11), Primary, Auto_Increment
alb_name, varchar
alb_release, YEAR
USER_ID, int
alb_image, varchar
GENRES
ALBUM_ID, int, NOT NULL
GENRE_ID, int, NOT NULL
ID, int, primary, auto-increment
Many thanks in advance...
==========================================================================================
//remove this line if you want to edit the code by hand
function Trigger_LinkTransactions(&$tNG) {
global $ins_genres;
$linkObj = new tNG_LinkedTrans($tNG, $ins_genres);
$linkObj->setLink("ALBUM_ID");
return $linkObj->Execute();
function Trigger_LinkTransactions2(&$tNG) {
global $ins_genres2;
$linkObj = new tNG_LinkedTrans($tNG, $ins_genres2);
$linkObj->setLink("ALBUM_ID");
return $linkObj->Execute();
function Trigger_LinkTransactions3(&$tNG) {
global $ins_genres3;
$linkObj = new tNG_LinkedTrans($tNG, $ins_genres3);
$linkObj->setLink("ALBUM_ID");
return $linkObj->Execute();
//end Trigger_LinkTransactions trigger
//-----------------------Different Section---------------------//
// Make an insert transaction instance
//Add Record Genre 1
$ins_genres = new tNG_insert($conn_MySQL);
$tNGs->addTransaction($ins_genres);
$ins_genres->registerTrigger("STARTER", "Trigger_Default_Starter", 1, "VALUE", null);
$ins_genres->registerTrigger("BEFORE", "Trigger_Default_FormValidation", 10, $detailValidation);
$ins_genres->setTable("genres");
$ins_genres->addColumn("GENRE_ID", "NUMERIC_TYPE", "POST", "GENRE_ID");
$ins_genres->addColumn("ALBUM_ID", "NUMERIC_TYPE", "VALUE", "");
$ins_genres->setPrimaryKey("ID", "NUMERIC_TYPE");
// Add Record Genre 2
$ins_genres2 = new tNG_insert($conn_MySQL);
$tNGs->addTransaction($ins_genres2);
$ins_genres2->registerTrigger("STARTER", "Trigger_Default_Starter", 1, "VALUE", null);
$ins_genres2->setTable("genres");
$ins_genres2->addColumn("GENRE_ID", "NUMERIC_TYPE", "POST", "GENRE_ID2");
$ins_genres2->addColumn("ALBUM_ID", "NUMERIC_TYPE", "VALUE", "");
$ins_genres2->setPrimaryKey("ID", "NUMERIC_TYPE");
// Add Record Genre 3
$ins_genres3 = new tNG_insert($conn_MySQL);
$tNGs->addTransaction($ins_genres3);
$ins_genres3->registerTrigger("STARTER", "Trigger_Default_Starter", 1, "VALUE", null);
$ins_genres3->setTable("genres");
$ins_genres3->addColumn("GENRE_ID", "NUMERIC_TYPE", "POST", "GENRE_ID3");
$ins_genres3->addColumn("ALBUM_ID", "NUMERIC_TYPE", "VALUE", "");
$ins_genres3->setPrimaryKey("ID", "NUMERIC_TYPE");
=========================================================================================
Hi Aaron,
Nice job!!
$ins_albums->registerTrigger("AFTER", "Trigger_LinkTransactions2", 98);
$ins_albums->registerTrigger("AFTER", "Trigger_LinkTransactions3", 98);
These lines, right? :-( Sorry I forgot to mention that
Thanks a lot for the grading!

Constantly inserting into large table with unique index... Guidance?

Hello all;
So here is my world. We have central to our data monitoring system an oracle database running Oracle Standard One (please don't laugh... I understand it is comical) licensing.
This DB is about 1.7 TB of small record data.
One table in particular (the raw incoming data, 350gb, 8 billion rows, just in the table) is fed millions of rows each day in real time by two to three main "data collectors" or what have you. Data must be available in this table "as fast as possible" once it is received.
This table has 6 columns (one varchar usually empty, a few numerics including a source id, a timestamp and a create time).
The data is collect in chronological order (increasing timestamp) 90% of the time (though sometimes the timestamp may be very old and catch up to current). The other 10% of the time the data can be out of order according to the timestamp.
This table has two indexes, unique (sourceid, timestamp), and a non unique (create time). (FYI, this used to be an IOT until we had to add the second index on create time, at which point a secondary index on create time slowed the IOT to a crawl)
About 80% of this data is removed after it ages beyond 3 months; 20% is retained as "special" long term data (customer pays for longer raw source retention). The data is removed using delete statements. This table is never (99.99% of the time) updated. The indexes are not rebuilt... ever... as a rebuild is about a 20+ hour process, and without online rebuilds since we are standard one, this is just not possible.
Now what we are observing is that the inserts into this table
- Inserts are much slower based on a "wider" cardinality of the "sourceid" of the data being inserted. What I mean is that 10,000 inserts for 10,000 sourceid (regardless of timestamp) is MUCH, MUCH slower than 10,000 inserts for a single sourceid. This makes sense to me, as I understand it that oracle must inspect more branches of the index for uniqueness, and more different physical blocks will be used to store the new index data. There are about 2 million unique sourceId across our system.
- Over time, oracle is requesting more and more ram to satisfy these inserts in a timely matter. My understanding here is that oracle is attempting to hold the leafs of these indexes perpetually buffers. Our system does have a 99% cache hit rate. However, we are seeing oracle requiring roughly 10GB extra ram per quarter to 6 months; we're at about 50gb of ram just for oracle already.
- If I emulate our production load on a brand new, empty table / indexes, performance is easily 10x to 20x faster than what I see when I do the same tests with the large production copies of data.
We have the following assumption: Partitioning this table based on good logical grouping of sourceid, and then timestamp, will help reduce the work required by oracle to verify uniqueness of data, reducing the amount of data that must be cached by oracle, and allow us to handle our "older than 3 month" at a partition level, greatly reducing table and index fragmentation.
Based on our hardware, its going to be about a million dollar hit to upgrade to Enterprise (with partitioning), plus a couple hundred thousand a year in support. Currently I think we pay a whopping 5 grand a year in support, if that, total oracle costs. This is going to be a huge pill for our company to swallow.
What I am looking for guidance / help on, should we really expect partitioning to make a difference here? I want to get that 10x performance difference back we see between a fresh empty system, and our current production system. I also want to limit oracles 10gb / quarter growing need for more buffer cache (the cardinality of sourceid does NOT grow by that much per quarter... maybe 1000s per quarter, out of 2 million).
Also, please I'd appreciate it if there were no mocking comments about using standard one up to this point :) I know it is risky and insane and maybe more than a bit silly, but we make due with what we have. And all the credit in the world to oracle that their "entry" level system has been able to handle everything we've thrown at it so far! :)
Alright all, thank you very much for listening, and I look forward to hear the opinions of the experts.

Hello,
Here is a link to a blog article that will give you the right questions and answers which apply to your case:
http://jonathanlewis.wordpress.com/?s=delete+90%25
As far as you are deleting 80% of your data (old data) based on a timestamp, then don't think at all about using the direct path insert /*+ append */ as suggested by one of the contributors to this thread. The direct path load will not re-use any free space made by the delete. You have two indexes:
(a) unique index (sourceid, timestamp)
(b) index(create time)
Your delete logic (based on arrival time) will smatch your indexes as far as you are always deleting the left hand side of the index; it means you will have what we call a right hand index - In other words, the scattering of the index key per leaf block is certainly catastrophic (there is an oracle iternal function named sys_op_lidbid that will allow you to verify this index information). There is a fairly chance that your two indexes will benefit from a coalesce as already suggested:
           ALTER INDEX indexname COALESCE;This coalesce should be investigated to be done on a regular basis (may be after each 80% delete) You seem to have several sourceid for one timestamp. If the answer is yes you should think about compressing this index
    create index indexname (sourceid, timestamp) compress;
or
    alter index indexname rebuild compress;     You will do it only once. Your index will have a smaller size and may be more efficient than it is actually. The index compression will add an extra CPU work during an insert but it might help improving the overal insert process.
Best Regards
Mohamed Houri

BizTalk 2013 R2 - Oracle client (Insert into Multiple tables) CompositE Transaction

I know there is Composite Transaction of inserting into multiple tables in SQL.
Is there a way where we can have inserts into multiple table at once ? If yes, can anyone please provide step by step procedure to achieve this
MBH

Here is a link on using Oracle DB w/ composite operations:
Performing Composite Operations on Oracle Database by Using BizTalk Server
Rachit
Please mark as answer or vote as helpful if my reply does

How can I insert into a table other than the default table in a form

Hi,
I want to insert into a table with some fields value of a form of another table. I have written insert code On successful submission of that form, but after submit it gives the following error
An unexpected error occurred: ORA-06502: PL/SQL: numeric or value error (WWV-16016)
My code is like this
declare
l_trn_id number;
l_provider_role varchar2(3);
l_provider_id varchar2(10);
begin
l_trn_id := p_session.get_value_as_number(p_block_name=>'DEFAULT',p_attribute_name=>'A_TRANSACTION_ID');
l_provider_id := p_session.get_value_as_varchar2(p_block_name=>'DEFAULT',p_attribute_name=>'A_PROVIDER1');
l_PROVIDER_ROLE := p_session.get_value_as_varchar2(p_block_name=>'DEFAULT',p_attribute_name=>'A_PROVIDER_ROLE1');
if (l_provider_role is not null) and (l_provider_id is not null) then
insert into service_provider_trans_records(service_provider_id,transaction_id,role_type_id)
values(l_provider_id, l_trn_id, l_provider_role);
commit;
end if;
end;
Where 'PROVIDER1' and 'PROVIDER_ROLE1' are not table fields.
How can do that or why this error comes ? Any idea?
Thanks
Sumita

Hi,
When do you get this error? Is it while running or while creating the form.
Here is a sample code which inserts a non-database column dummy into a table called dummy. This is done in successful procedure.
declare
l_dummy varchar2(1000);
begin
l_dummy := p_session.get_value_as_varchar2(p_block_name=>'DEFAULT',
p_attribute_name=>'A_DUMMY');
insert into sjayaram903_1g.dummy values(l_dummy);commit;
end;
Please check in your case if the size of the local variable is enough to hold the values being returned.
Thanks,
Sharmila

Inserting into a table which is created "on the fly" from a trigger

Hello all,
I am trying to insert into a table from a trigger in Oracle form. The table name however, is inputted by the user in am item form.
here is what the insert looks like:
insert into :table_name
values (:value1, :value2);
the problem is that forms does not recognize ::table_name. If I replace :table_name with an actual database table, it works fine. However, I need to insert to a table_name based from oracle form item.
By the way, the table|_name is built on the fly using a procedure before I try to insert into it.
Any suggestion on how can I do that? My code in the trigger is:
declare
dm_drop_tbl(:table_name,'table) // a call to an external procedure to drop the table
dm_create_tbl(:table_name,'att1','att2');
insert into :table_name
values (:value1, :value2);
this give me an error:
encounter "" when the symbol expecting one.....

Hi ,
You should use the FORMS_DDL built_in procedure. Read the on-line documentation of forms ...
Simon

Problem while inserting into a table which has ManyToOne relation

Problem while inserting into a table *(Files)* which has ManyToOne relation with another table *(Folder)* involving a attribute both in primary key as well as in foreign key in JPA 1.0.
Relevent Code
Entities:
public class Files implements Serializable {
@EmbeddedId
protected FilesPK filesPK;
private String filename;
@JoinColumns({
@JoinColumn(name = "folder_id", referencedColumnName = "folder_id"),
@JoinColumn(name = "uid", referencedColumnName = "uid", insertable = false, updatable = false)})
@ManyToOne(optional = false)
private Folders folders;
public class FilesPK implements Serializable {
private int fileId;
private int uid;
public class Folders implements Serializable {
@EmbeddedId
protected FoldersPK foldersPK;
private String folderName;
@OneToMany(cascade = CascadeType.ALL, mappedBy = "folders")
private Collection<Files> filesCollection;
@JoinColumn(name = "uid", referencedColumnName = "uid", insertable = false, updatable = false)
@ManyToOne(optional = false)
private Users users;
public class FoldersPK implements Serializable {
private int folderId;
private int uid;
public class Users implements Serializable {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Integer uid;
private String username;
@OneToMany(cascade = CascadeType.ALL, mappedBy = "users")
private Collection<Folders> foldersCollection;
I left out @Basic & @Column annotations for sake of less code.
EJB method
public void insertFile(String fileName, int folderID, int uid){
FilesPK pk = new FilesPK();
pk.setUid(uid);
Files file = new Files();
file.setFilename(fileName);
file.setFilesPK(pk);
FoldersPK folderPk = new FoldersPK(folderID, uid);
// My understanding that it should automatically handle folderId in files table,
// but it is not…
file.setFolders(em.find(Folders.class, folderPk));
em.persist(file);
It is giving error:
Internal Exception: java.sql.SQLException: Field 'folderid' doesn't have a default value_
Error Code: 1364
Call: INSERT INTO files (filename, uid, fileid) VALUES (?, ?, ?)_
_ bind => [hello.txt, 1, 0]_
It is not even considering folderId while inserting into db.
However it works fine when I add folderId variable in Files entity and changed insertFile like this:
public void insertFile(String fileName, int folderID, int uid){
FilesPK pk = new FilesPK();
pk.setUid(uid);
Files file = new Files();
file.setFilename(fileName);
file.setFilesPK(pk);
file.setFolderId(folderId) // added line
FoldersPK folderPk = new FoldersPK(folderID, uid);
file.setFolders(em.find(Folders.class, folderPk));
em.persist(file);
My question is that is this behavior expected or it is a bug.
Is it required to add "column_name" variable separately even when an entity has reference to ManyToOne mapping foreign Entity ?
I used Mysql 5.1 for database, then generate entities using toplink, JPA 1.0, glassfish v2.1.
I've also tested this using eclipselink and got same error.
Please provide some pointers.
Thanks

Hello,
What version of EclipseLink did you try? This looks like bug https://bugs.eclipse.org/bugs/show_bug.cgi?id=280436 that was fixed in EclipseLink 2.0, so please try a later version.
You can also try working around the problem by making both fields writable through the reference mapping.
Best Regards,
Chris

Diffrence between backend insert and front end insert into a table.

I am developing a conversion program for tax exemption. For this program only ZX_EXEMPTIONS table is used to populate the data and we got confirmation from Oracle also regarding this.For inserting the data into this table we are taking the max of tax_exemption_id which is pk for this table and adding one to it and inserting into the table. But problem here is after inserting from back end we are not able to insert from front end.
It seems backend data is holding the tax_exemption_id which is suppose to reserve by front end data.Please explain the different behavior of populating of tax_exemption_id from front end and back end.

Hi,
i think the problem is that you are using max-value + 1 for tax_exemption_id. But as ZX_EXEMPTIONS is using sequence ZX_EXEMPTIONS_S
for primary key generation, you encounter situation that you are increasing PK Id for this table without increasing sequence value.
When trying to insert rows from front end - which probably uses sequence value - it tries to use a sequence value already used by your backend
process (which generated it by Maxvalue + 1) and would then encounter a primary key violation.
I think you should use sequence mentioned above to generate your PK Ids in backend process as well. And before doing so, check current value
of ZX_EXEMPTIONS_S, as you might need to rebuild the sequence in order to select nextval sucessfully for both frontend and backend.
Regards

How can I get a count at the same time I am inserting into another table

I have a requirement where I have to find out the count(number of records inserted into another table) at the same time I insert into the table:
Like
I am copying records from table B to A, while doing this I have to find out how many records I've inserted since I need this count in subsequent steps
INSERT INTO A
SELECT * FROM B
how can I store the count into any variable while doing above statement
Please advice

No, Warren that doesn't work!
SQL> set serveroutput on
SQL> declare
2     vCtr number := 0;
3 begin
4     insert into emp2
5     select * from emp;
6
7     select count(*)
8       into vCtr
9       from emp2;
10
11     dbms_output.put_line('rows created '||to_char(vCtr));
12 end;
13 /
rows created 15
PL/SQL procedure successfully completed.
SQL> declare
2     vCtr number := 0;
3 begin
4     insert into emp2
5     select * from emp;
6
7     select count(*)
8       into vCtr
9       from emp2;
10
11     dbms_output.put_line('rows created '||to_char(vCtr));
12 end;
13 /
rows created 30
PL/SQL procedure successfully completed.
SQL>

How to extract data from xml and insert into Oracle table

Hi,
I have a large xml file. which will have hundreds of the following transaction tags having column names and there values.
There is a table one of the schema with coulums "actualCostRate","billRate"....etc.
I need to extract the values of these columns and insert into the table
<Transaction actualCostRate="0" billRate="0" chargeable="1" clientID="NikuUK" chargeCode="LCOCD1" externalID="L-RESCODE_UK1-PROJ_UK_CNT_GBP-37289-8" importStatus="N" projectID="TESTPROJ" resourceID="admin" transactionDate="2002-02-12" transactionType="L" units="11" taskID="5017601" inputTypeCode="SALES" groupId="123" voucherNumber="ABCVDD" transactionClass="ABCD"/>
<Transaction actualCostRate="0" billRate="0" chargeable="1" clientID="NikuEU" chargeCode="LCOCD1" externalID="L-RESCODE_US1-PROJ_EU_STD2-37291-4" importStatus="N" projectID="TESTPROJ" resourceID="admin" transactionDate="2002-02-04" transactionType="L" units="4" taskID="5017601" inputTypeCode="SALES" groupId="124" voucherNumber="EEE222" transactionClass="DEFG"/>

Re: Insert from XML to relational table
http://www.google.ae/search?hl=ar&q=extract+data+from+xml+and+insert+into+Oracle+table+&btnG=%D8%A8%D8%AD%D8%AB+Google&meta=

How to insert into a table with a nested table which refer to another table

Hello everybody,
As the title of this thread might not be very understandable, I'm going to explain it :
In a context of a library, I have an object table about Book, and an object table about Subscriber.
In the table Subscriber, I have a nested table modeling the Loan made by the subscriber.
And finally, this nested table refers to the Book table.
Here the code concerning the creation of theses tables :
Book :
create or replace type TBook as object
number int,
title varchar2(50)
Loan :
create or replace type TLoan as object
book ref TBook,
loaning_date date
create or replace type NTLoan as table of TLoan;
Subscriber :
create or replace type TSubscriber as object
sub_id int,
name varchar2(25)
loans NTLoan
Now, my problem is how to insert into a table of TSubscriber... I tried this query, without any success...
insert into OSubscriber values
*(1, 'LEVEQUE', NTLoan(*
select TLoan(ref(b), '10/03/85') from OBook b where b.number = 1)
Of course, there is an occurrence of book in the table OBook with the number attribute 1.
Oracle returned me this error :
SQL error : ORA-00936: missing expression
00936. 00000 - "missing expression"
Thank you for your help

1) NUMBER is a reserved word - you can't use it as identifier:
SQL> create or replace type TBook as object
2 (
3 number int,
4 title varchar2(50)
5 );
6 /
Warning: Type created with compilation errors.
SQL> show err
Errors for TYPE TBOOK:
LINE/COL ERROR
0/0      PL/SQL: Compilation unit analysis terminated
3/1      PLS-00330: invalid use of type name or subtype name2) Subquery must be enclosed in parenthesis:
SQL> create table OSubscriber of TSubscriber
2 nested table loans store as loans
3 /
Table created.
SQL> create table OBook of TBook
2 /
Table created.
SQL> insert
2    into OBook
3    values(
4           1,
5           'No Title'
6          )
7 /
1 row created.
SQL> commit
2 /
Commit complete.
SQL> insert into OSubscriber
2    values(
3           1,
4           'LEVEQUE',
5           NTLoan(
6                  (select TLoan(ref(b),DATE '1985-10-03') from OBook b where b.num = 1)
7                 )
8          )
9 /
1 row created.
SQL> select *
2    from OSubscriber
3 /
    SUB_ID NAME
LOANS(BOOK, LOANING_DATE)
         1 LEVEQUE
NTLOAN(TLOAN(000022020863025C8D48614D708DB5CD98524013DC88599E34C3D34E9B9DBA1418E49F1EB2, '03-OCT-85'))
SQL> SY.

Record not inserting into the table through Forms 10g

Hi all,
I have created a form in 10g(10.1.2.0.2) based on just one table that has 4 columns(col1, col2, col3, col4).
Here col1, col2 and col3 are VARCHAR2 and col4 is date and all the columns are not null columns(There are no primary and foriegn key constrains, which means duplicates are allowed).
My form contains 2 blocks where block 1 has one text item (col1) and 3 buttons (Delete, Save, Exit).
And block2 is a database block and has col2,col3,col4 which are in tabluar layout frame displaying 10 records.
When the form is opened the cursor has to be in block1.col1 for querrying. Here i enter a value in col1, and then when I click on col2 in the block2, then I put execute_query in new_block_instance of block2, which displays the records.
The block2 properties are not updatable, insertable and query is allowed.
Everything is working good until here. But here in the block2 when I want to insert another record into the table, by navigating all the way down to the last empty record and entering the new values for col2, col3 and col4 And then Ctrl+S will display the message "*FRM-40400: Transaction complete: 1 record applied and saved.*" But actually the record is not inserted into the table.
I also disabled the col4 by setting the Enabled property to No, since while inserting new record the date have to be populated into it and it shouldnt be changed by the user. And im populating the sysdate into the new record by setting Intial Value property to *$$DATE$$*.
And another requirement which I could not work arround here is that, the col3 also should be populated with the username of the user while inserting.
please help me...

Hi Sarah,
I do not want to update the existing record. So I kept Udate Allowed to No in property palette for the items in block2.
Do I have to do this property at block level also?
I'm inserting a new record here.
Edited by: Charan on Sep 19, 2011 8:48 AM

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