Int to binary

I was wondering if there is a function for turning an integer into a binary number? Thanks ( tried looking it up but all that came up was binary search and some other odd topics...)
me

int i = 1023;
 // Parse and format to binary
 i = Integer.parseInt("1111111111", 2); // 1023
 String s = Integer.toString(i, 2); // 1111111111
 // Parse and format to octal
 i = Integer.parseInt("1777", 8); // 1023
 s = Integer.toString(i, 8); // 1777
 // Parse and format to decimal
 i = Integer.parseInt("1023"); // 1023
 s = Integer.toString(i); // 1023
 // Parse and format to hexadecimal
 i = Integer.parseInt("3ff", 16); // 1023
 s = Integer.toString(i, 16); // 3ff
 // Parse and format to arbitrary radix <= Character.MAX_RADIX
 int radix = 32;
 i = Integer.parseInt("vv", radix); // 1023
 s = Integer.toString(i, radix); // vv

Similar Messages

How to print an int in binary form ?

Say I have an int storing 5, can I print it out as 00000101 ?
Thank you very much

The simplest way to do this is:
int i = 5;
String s = Integer.toBinaryString(i);
System.out.println("i is: " + s);
For me, that outputs:
i is: 101
Unfortunately, that doesn't get you the padding you require. Is the padding important to you, or just the binary conversion part?

Int to binary converions

Is there a command i can use for converting binary to int or is it just easier to go through it and use the & operator and the >> shift ??

int i = Integer.parseInt("1010101", 2);
Or you have to use the bitwise operators or try with hex values

Small problem - int to binary...

Hey all, I need to create a simple java applet which converts an int into it's binary representation.
Here is the output i need:
Enter an int: (user enters int)
That number in binary is:
Thats all I need. I know it has something to do with a "wrapper class", but thats all I know. :P
Could anyone point me in the right direction plz?

http://java.sun.com/j2se/1.5.0/docs/api/java/lang/Integer.html#parseInt(java.lang.String,%20int)

Conversion int - binary

Hello everybody,
i want to change an integer signed value (on 32 bits) in binary format and do the reverse operation.
So i wrote :
String binIntStr = Integer.toBinaryString(-1610612462);
System.out.println("Binary : "+binIntStr);
System.out.println("Int : "+Integer.parseInt(binIntStr, 2));The conversion of the int to binary runs correctly, but the reverse operation (binary string to int) throws an NumberFormatException.
I don't understand why the operation is well done in one way and is not allowed in the other.
The integer value is in good format (-2147483648 < -1610612462 < 2147483647) so why can't I change the binary string returned by the method toBinaryString in an integer ?

Integer.toBinaryString() returns a string representation of the integer argument as an unsigned integer in base 2
from the API doc
toBinaryString
public static String toBinaryString(int i)Returns a string representation of the integer argument as an unsigned integer in base 2.
The unsigned integer value is the argument plus 232 if the argument is negative; otherwise it is equal to the argument.
This value is converted to a string of ASCII digits in binary (base 2) with no extra leading 0s. If the unsigned magnitude is zero, it is represented by a single zero character '0' ('\u0030');
otherwise, the first character of the representation of the unsigned magnitude will not be the zero character. The characters '0' ('\u0030') and '1' ('\u0031') are used as binary digits.
Parameters:
i - an integer to be converted to a string.
Returns:
the string representation of the unsigned integer value represented by the argument in binary (base 2).so you will have to figure out out to deal with signed values yourself
Message was edited by:
SomeoneElse

How can I transfer binary data from a database to another database?

Hi all.
I want to transfer binary data from a MS SQL Server 2000 to anohter SQL Server 2000.
I created JDBC(table) to JDBC(stored procedure) scenario,and
I uploaded a JPG image file to the sender table using the java program I developed.
The JPG data was transfered to receiver,but the transfered data was broken.
I can't not open the file correctly.
Can XI transfer binary data using JDBC adapter?
The sender table structure is following.
column (data type)
id (int 4)
binary (binary 8000)
flag (int 4)
The receiver stored procedure parameter is following.
parameter (data type)
id (smallint)
binary (binary 8000)
flag (smallint)
Regards.
Yuuki

Hi,
Can XI transfer binary data using JDBC adapter?
Ans: Yes
Supported JDBC Types
http://help.sap.com/saphelp_nw04s/helpdata/en/16/9dc9ac8bc72a48b80e639abaa2e497/frameset.htm
http://help.sap.com/saphelp_nw2004s/helpdata/en/2e/96fd3f2d14e869e10000000a155106/content.htm
Mapping JDBC types to Java types
http://help.sap.com/saphelp_nw04/helpdata/en/7d/79dfa72d1049bc963f4f272bb1638e/frameset.htm
Regards,
Prateek

How to read a C structure with string and int with a java server using sock

I ve made a C agent returning some information and I want to get them with my java server. I ve settled communication with connected socket but I m only able to read strings.
I want to know how can I read strings and int with the same stream because they are sent at the same time:
C pgm sent structure :
char* chaine1;
char* chaine2;
int nb1;
int nb2;
I want to read this with my java stream I know readline methode to get the first two string but after two readline how should I do to get the two int values ?
Any idea would be a good help...
thanks.
Nicolas (France)

Does the server sent the ints in little endian or big endian format?
The class java.io.DataInputStream (with the method readInt()) can be used to read ints as binary from the stream - see if you can use it.

Binary in java

is it possible to declare an int a binary number. and if so, how?
eg.
public static final int BINARY_1 = 1; //1
public static final int BINARY_2 = 10; //2
public static final int BINARY_2 = 11; //3
public static final int BINARY_4 = 100; //4
.....etc

Design an applet for converting numbers between binary, hexadecimal and signed decimal with the following specifications:1.It should allow the user to enter in a number in any of the above number bases and display its equivalent in the other two bases.2.The program should have one user-interface class (i.e. the applet) and one or more other classes modelling the required objects. The user-interface class should only capture user inputs and display results. Other activities should be carried out within the objects created in the applet.3.When displaying a decimal number, it should indicate �+� sign for positive and �-� sign for negative values.
When displaying a binary number, it should have at least one leading �0� for positive and one at least leading �1� for negative values.
Decimal numbers should be grouped in three digits, separated by commas (e.g. 1,234,567). Binary/hexadecimal should be grouped in four bits/digits (e.g. 01,0010,1010 and 1,A97D).
Please e-mail to me,thanks.

Problems with Concatenating Binary Data

Hi
I am experiencing a problem with the unreliable concatenation of binary data.
I have a stored procedure that I wrote to perform cell encryption on long text fields (> 4000 characters in length). This takes the string, splits it into chunks of a set length, encrypts and concatenates the encrypted chunks into a varbinary(max) variable.
It then stores the length of the encrypted chunk at the beginning of the data (the length of output when encrypting strings of a set length is always be the same), e.g.
DECLARE @output VARBINARY(MAX), @length INT
SELECT @length = LEN(@encryptedchunk1)
SELECT @output = CONVERT(binary(8), @length) + @encryptedchunk1 + @encryptedchunk2 + @encryptedchunk3 + ...
So far so good, and when I decrypt the data, I can read the first 8 bytes of data at beginning of the binary data to get the length of the chunk:
-- get the length of the encrypted chunk
SELECT @length = CONVERT(INT, CONVERT(binary(8), LEFT(@encrypteddata, 8)))
-- then remove the first 8 bytes of data
SELECT @encrypteddata = CONVERT(VARBINARY(MAX), RIGHT(@encrypteddata, LEN(@encrypteddata) - 8))
<snip> code to split into chunks of length @length and decrypt
</snip>
This is where I am experiencing an issue. 99.4% of the time, the above code is reliable. However, 0.6% of the time this fails for one of two reasons:
the length is stored incorrectly. The length of the encrypted chunks is usually 4052 and substituting 4052 for the returned value (4051) allows the encrypted chunks to be decrypted.
the encrypted data sometimes starts at offset 8 instead of 9. The @length variable is correctly read at length 8 but only 7 bytes should be removed from the start, e.g.
SELECT @length = CONVERT(INT, CONVERT(binary(8), LEFT(@encrypteddata, 8)))
SELECT @encrypteddata = CONVERT(VARBINARY(MAX), RIGHT(@encrypteddata, LEN(@encrypteddata) - 7))
Has anyone any ideas on why this is happening and how the process can be made more reliable?
Julian

Use datalength, not len. Len() is designed for character strings and will ignore trailing bytes. And count characters. Datalength does exactly what you want: it counts bytes. Look at this:
DECLARE @b varbinary(200)
SELECT @b = 0x4142434420202020
SELECT @b, len(@b), datalength(@b)
Erland Sommarskog, SQL Server MVP, [email protected]

How to convert decimal to binary

example:
source:254254254254
target:11111110111111101111111011111110

With the following you can convert a long type value to a binary String with leading zeros. If you would not like leading zeros you can modify it in a trivial way.
final static char[] coeffs = new char[]{(char)0x30,(char)0x31};
public static String toBinary(long n) {
char[] binary = new char[64];
for(int j=0;j<binary.length;j++) binary[j]=(char)0x30; // If leading zeros are not required, simply omit this line.
int charPointer = binary.length-1;
if(n==0L) return "0";
while (n!=0L){
binary[charPointer--] = coeffs[(int)n&1];
n >>>= 1;
return new String(binary);
}

Help with binary to decimal, binary to hex, and hex to ascii or ascii to hex program

I decided to do a program that will do binary to decimal, binary to hex, and hex to ascii for a project related to a java programming course, which only needs to perform features from chapters 1-6 and 8 of Tony Gaddis's book. The functions work fine as their own main programs out side of this combined effort, so can anyone help me determine why I get the following 41 errrors saying: class, interface, or enum expected as well as any other errors that may show up afterwards because I'm stumped. My flowcharts, which have to be revised after discovering that my previous function were logically incorrect after running them in their own main are attached below as the spec sheet.
My code is as follows and I hope you don't mind the commented lines of unused code because I'm not sure where I want things and what I want at the moment:
import java.util.Scanner;
import java.io.*;
import java.lang.*;
public class BintoDectoHextoAscii
 public static void main(String[] args)throws IOException
 Scanner input = new Scanner(System.in);
 System.out.println("Enter a binary number: ");
 String binary = input.nextLine(); // store input from user
 if (binary == input.nextLine())
 //int i= Integer.parseInt(hex,2);
 //String hexString = Integer.toHexString(i);
 //System.out.println("Hexa decimal: " + hexString);
 //int finaldecimalvalue = binaryToDecimal(hexString);
 int finaldecimalvalue = binaryToDecimal(hexString);
 if (binary != input.nextLine())
 String hexInput; // The variable Bin Input declared as the datatype int to store the Binary value
 // Create a Scanner object for keyboard input.
 //Scanner keyboard = new Scanner(System.in);
 // Get the number of binary files.
 System.out.print("Enter the Hex value: ");
 hexInput = keyboard.nextLine();
 System.out.println("Original String: "+ hexInput);
 //String hexEquivalent = asciiToHex(demoString);
 String hexEquivalent = asciiToHex(hexInput);
 //Hex value of original String
 System.out.println("Hex String: "+ hexEquivalent);
 String asciiEquivalent = hexToASCII(hexEquivalent);
 //ASCII value obtained from Hex value
 System.out.println("Ascii String: "+ asciiEquivalent);String finalhexOutput = HextoAsciiConverter(hexEquivalent);
 if (binary != input.nextLine() && hexInput != keyboard.nextLine())
 BufferedReader binInput = new BufferedReader(new InputStreamReader(System.in));
 System.out.println("Enter the Binary number:");
 String hex = binInput.readLine();
 //String finaldecimalvalue = binaryToDecimal(decimal);
 //long finalhexvalue = BinaryToHexadecimal(num);
 long finalhexvalue = BinaryToHexadecimal();
 public static String BinaryToHexadecimal(String hex)
 //public static void main(String[] args)throws IOException
 //BufferedReader bf= new BufferedReader(new InputStreamReader(System.in));
 //System.out.println("Enter the Binary number:");
 //String hex = binInput.readLine();
 long num = Long.parseLong(hex);
 long rem;
 while(num > 0)
 rem = num % 10;
 num = num / 10;
 if(rem != 0 && rem != 1)
 System.out.println("This is not a binary number.");
 System.out.println("Please try once again.");
 System.exit(0);
 int i= Integer.parseInt(hex,2);
 String hexString = Integer.toHexString(i);
 System.out.println("Hexa decimal: " + hexString);
 return num.tolong();
//int i= Integer.parseInt(hex,2);
//String hexString = Integer.toHexString(i);
//System.out.println("Hexa decimal: " + hexString);
//} // end BintoDectoHextoAsciil
 //public static String HexAsciiConverter(String hextInput)
 // Get the number of binary files.
 //System.out.print("Enter the Hex value: ");
 //hexInput = keyboard.nextLine();
 //System.out.println("Original String: "+ hexInput);
 //String hexEquivalent = asciiToHex(demoString);
 //String hexEquivalent = asciiToHex(hexInput);
 //Hex value of original String
 //System.out.println("Hex String: "+ hexEquivalent);
 //String asciiEquivalent = hexToASCII(hexEquivalent);
 //ASCII value obtained from Hex value
 //System.out.println("Ascii String: "+ asciiEquivalent);
 //} // End function
 private static String asciiToHex(String asciiValue)
 char[] chars = asciiValue.toCharArray();
 StringBuffer hex = new StringBuffer();
 for (int i = 0; i < chars.length; i++)
 hex.append(Integer.toHexString((int) chars[i]));
 return hex.toString();
 private static String hexToASCII(String hexValue)
 StringBuilder output = new StringBuilder("");
 for (int i = 0; i < hexValue.length(); i += 2)
 String str = hexValue.substring(i, i + 2);
 output.append((char) Integer.parseInt(str, 16));
 return output.toString();
 public static String binaryToDecimal(String binary)
 //Scanner input = new Scanner(System.in);
 //System.out.println("Enter a binary number: ");
 //String binary = input.nextLine(); // store input from user
 int[] powers = new int[16]; // contains powers of 2
 int powersIndex = 0; // keep track of the index
 int decimal = 0; // will contain decimals
 boolean isCorrect = true; // flag if incorrect input
 // populate the powers array with powers of 2
 for(int i = 0; i < powers.length; i++)
 powers[i] = (int) Math.pow(2, i);
 for(int i = binary.length() - 1; i >= 0; i--)
 // if 1 add to decimal to calculate
 if(binary.charAt(i) == '1')
 decimal = decimal + powers[powersIndex]; // calc the decimal
 else if(binary.charAt(i) != '0' & binary.charAt(i) != '1')
 isCorrect = false; // flag the wrong input
 break; // break from loop due to wrong input
 } // end else if
 // keeps track of which power we are on
 powersIndex++; // counts from zero up to combat the loop counting down to zero
 } // end for
 if(isCorrect) // print decimal output
 System.out.println(binary + " converted to base 10 is: " + decimal);
 else // print incorrect input message
 System.out.println("Wrong input! It is binary... 0 and 1's like.....!");
 return decimal.toint();
 } // end function
The errors are as follows:
----jGRASP exec: javac BintoDectoHextoAscii.java
BintoDectoHextoAscii.java:65: error: class, interface, or enum expected
 public static String BinaryToHexadecimal(String hex)
 ^
BintoDectoHextoAscii.java:73: error: class, interface, or enum expected
 long rem;
 ^
BintoDectoHextoAscii.java:74: error: class, interface, or enum expected
 while(num > 0)
 ^
BintoDectoHextoAscii.java:77: error: class, interface, or enum expected
 num = num / 10;
 ^
BintoDectoHextoAscii.java:78: error: class, interface, or enum expected
 if(rem != 0 && rem != 1)
 ^
BintoDectoHextoAscii.java:81: error: class, interface, or enum expected
 System.out.println("Please try once again.");
 ^
BintoDectoHextoAscii.java:83: error: class, interface, or enum expected
 System.exit(0);
 ^
BintoDectoHextoAscii.java:84: error: class, interface, or enum expected
 ^
BintoDectoHextoAscii.java:87: error: class, interface, or enum expected
 String hexString = Integer.toHexString(i);
 ^
BintoDectoHextoAscii.java:88: error: class, interface, or enum expected
 System.out.println("Hexa decimal: " + hexString);
 ^
BintoDectoHextoAscii.java:90: error: class, interface, or enum expected
 return num.tolong();
 ^
BintoDectoHextoAscii.java:91: error: class, interface, or enum expected
 ^
BintoDectoHextoAscii.java:124: error: class, interface, or enum expected
 StringBuffer hex = new StringBuffer();
 ^
BintoDectoHextoAscii.java:125: error: class, interface, or enum expected
 for (int i = 0; i < chars.length; i++)
 ^
BintoDectoHextoAscii.java:125: error: class, interface, or enum expected
 for (int i = 0; i < chars.length; i++)
 ^
BintoDectoHextoAscii.java:125: error: class, interface, or enum expected
 for (int i = 0; i < chars.length; i++)
 ^
BintoDectoHextoAscii.java:128: error: class, interface, or enum expected
 ^
BintoDectoHextoAscii.java:130: error: class, interface, or enum expected
 ^
BintoDectoHextoAscii.java:135: error: class, interface, or enum expected
 for (int i = 0; i < hexValue.length(); i += 2)
 ^
BintoDectoHextoAscii.java:135: error: class, interface, or enum expected
 for (int i = 0; i < hexValue.length(); i += 2)
 ^
BintoDectoHextoAscii.java:135: error: class, interface, or enum expected
 for (int i = 0; i < hexValue.length(); i += 2)
 ^
BintoDectoHextoAscii.java:138: error: class, interface, or enum expected
 output.append((char) Integer.parseInt(str, 16));
 ^
BintoDectoHextoAscii.java:139: error: class, interface, or enum expected
 ^
BintoDectoHextoAscii.java:141: error: class, interface, or enum expected
 ^
BintoDectoHextoAscii.java:144: error: class, interface, or enum expected
 public static String binaryToDecimal(String binary)
 ^
BintoDectoHextoAscii.java:150: error: class, interface, or enum expected
 int powersIndex = 0; // keep track of the index
 ^
BintoDectoHextoAscii.java:151: error: class, interface, or enum expected
 int decimal = 0; // will contain decimals
 ^
BintoDectoHextoAscii.java:152: error: class, interface, or enum expected
 boolean isCorrect = true; // flag if incorrect input
 ^
BintoDectoHextoAscii.java:155: error: class, interface, or enum expected
 for(int i = 0; i < powers.length; i++)
 ^
BintoDectoHextoAscii.java:155: error: class, interface, or enum expected
 for(int i = 0; i < powers.length; i++)
 ^
BintoDectoHextoAscii.java:155: error: class, interface, or enum expected
 for(int i = 0; i < powers.length; i++)
 ^
BintoDectoHextoAscii.java:159: error: class, interface, or enum expected
 for(int i = binary.length() - 1; i >= 0; i--)
 ^
BintoDectoHextoAscii.java:159: error: class, interface, or enum expected
 for(int i = binary.length() - 1; i >= 0; i--)
 ^
BintoDectoHextoAscii.java:159: error: class, interface, or enum expected
 for(int i = binary.length() - 1; i >= 0; i--)
 ^
BintoDectoHextoAscii.java:166: error: class, interface, or enum expected
 else if(binary.charAt(i) != '0' & binary.charAt(i) != '1')
 ^
BintoDectoHextoAscii.java:169: error: class, interface, or enum expected
 break; // break from loop due to wrong input
 ^
BintoDectoHextoAscii.java:170: error: class, interface, or enum expected
 } // end else if
 ^
BintoDectoHextoAscii.java:174: error: class, interface, or enum expected
 } // end for
 ^
BintoDectoHextoAscii.java:180: error: class, interface, or enum expected
 else // print incorrect input message
 ^
BintoDectoHextoAscii.java:185: error: class, interface, or enum expected
 return decimal.toint();
 ^
BintoDectoHextoAscii.java:186: error: class, interface, or enum expected
 } // end function
 ^
41 errors
----jGRASP wedge2: exit code for process is 1.
----jGRASP: operation complete.

so can anyone help me determine why I get the following 41 errrors saying: class, interface, or enum expected as well as any other errors that may show up afterwards because I'm stumped.
Yes - YOU CAN!
My code is as follows and I hope you don't mind the commented lines of unused code because I'm not sure where I want things and what I want at the moment:
Excellent! Commenting out code is EXACTLY how you troubleshoot problems like yours.
Comment out sections of code until the problem goes away. Then start adding back ONE SECTION of code at a time until the problem occurs. When it does you have just FOUND the problem.
If you do that you wind up with code that looks like this:
import java.util.Scanner;
import java.io.*;
import java.lang.*;
public class BintoDectoHextoAscii {
 public static void main(String[] args)throws IOException {
 Scanner input = new Scanner(System.in);
 System.out.println("Enter a binary number: ");
 String binary = input.nextLine(); // store input from user
 public static String BinaryToHexadecimal(String hex) { } // end function
Notice ANYTHING UNUSUAL?
You have a complete CLASS definition followed by a method definition.
Methods have to be INSIDE the class - you can NOT define methods on their own.
Write modular code.
Write EMPTY methods - just the method signature and maybe a RETURN NULL if you need to return something.
Then add calls to those empty methods.
When everything compiles and runs find you can start adding code to the methods ONE METHOD AT A TIME.
Test compile and run after you add the code for each method.

Conversion to binary

I really need a bit of code that will convert an int to binary. Can anyone help me with this??

Cheers mark, certainly not how i had planned to do
it, was going to set up [32], store the remainder in
it, then read it backwards.I suppose you could do that, but it strikes me as sort of reinventing the wheel... :-)
Mark

Printing Binary Numbers in SP

I am trying to print binary numbers in my output.
Below is the expected output
1 0x5F6AB40860296D4DB07C346FA12E25FD
2 0x5F6AB40860296D4DB07C346FA12E25FD
Below is the output i am getting
-1590811137
CREATE
TABLE Testbinary(
[ID] [int]
NOT
NULL,
[yVolumeUnitID] [binary]
(16)
NOT
NULL
insert
into Testbinary
values(1,0x5F6AB40860296D4DB07C346FA12E25FD)
insert
into Testbinary
values(2,0x5F6AB40860296D4DB07C346FA12E25FD)
select
from Testbinary
delete Testbinary
select yVolumeUnitID
from dbo.MdPriceDesc
alter
proc vol
as
declare
@ID
int,
@VolumeID
binary(16),
@out
varchar(100)
begin
select @ID=ID,
@VolumeID=yVolumeUnitID
from Testbinary
set
@out = @ID+''+@VolumeID
print
(@out)
end
exec vol

You have some implicit conversion going on. Your INT column is ADDED to your VARBINARY column by
@out = @ID+''+@VolumeID
DECLARE @table TABLE (id INT, number VARBINARY(MAX))
INSERT INTO @table (id, number) VALUES
(1, 0x5F6AB40860296D4DB07C346FA12E25FD),
(2, 0x5F6AB40860296D4DB07C346FA12E25FD)
declare @vb VARBINARY(MAX), @int INT
SELECT @vb = number, @int = id
FROM @table
PRINT @vb
PRINT @int+@vb
PRINT CAST(@int AS NVARCHAR)+''+master.sys.fn_varbintohexstr(@vb)
Don't forget to mark helpful posts, and answers. It helps others to find relevant posts to the same question.

Checking and Converting binary, octal, decimal, and hex

Hi,
I have a classroom project which will need to validate that data entered in a text is of a certain type with a keyListener, and then convert that value to the other 3 types.
I know character.isDigit will handle the decimal case, and that I can then use Integer.otString methods to convert to binary, octal, and hex, but what about the other cases?
Thanks

OK, this isn't working. If I've already established
that the string entered into, for example, the
integer-only textfield is a valid integer, I should be
able to simply use integer.parseint(s, 2) to convert
it into binary, right?Not exactly. You should be able to use Integer.parseInt(s, 2) to return the result of converting it from binary representation. You appear to think that this affects whatever "s" refers to, which is not the case. Note also, that method returns an int which is the decimal value in question.
When you are thinking of int variables, be careful not to think of them as "decimal" or "binary". They are neither. They are just numbers. "Decimal" and "binary" are text representations of numbers, so those concepts can only be applied to strings.
Integer.parseInt(s, 2);
txtBin.setText(s);So here you want to assume that the input is a string that represents a number in decimal, and you want to find the string that represents the number in binary. Like this:// convert string in decimal representation to number
int dec = Integer.parseInt(s);
// convert int to binary representation as string:
String binary = Integer.toBinaryString(dec);
// write that to the text field
txtBin.setText(binary);You could use a one-liner to do that, but you'll need the "dec" variable to set the other text boxes.
Rembering why I hate OO...All of what I said there is true in just about all computer languages, OO or otherwise.
PC²

Changing one character in a string...how hard can it be...???

Hey guys,
I posted something the other day about changing a binary string to one complement. Well, now I want to change that again to the two's complement of the same number.
The (messy) code I got so far is as follows:
import java.util.*;
class twosComplement {
public static void main(String[] args) {
      Scanner reader = new Scanner(System.in);
      String binary;
      String i = "0";
      String j = "1";
      System.out.println("Enter a binary String:");
      binary = reader.nextLine();
   //   int x = 15;
   // String binary = Integer.toBinaryString(x);
   // binary = ("00000000"+binary).substring(8-binary.length());
    System.out.println("Your binary number is " +binary);
    String complement = binary.replaceAll("0","x").replaceAll("1","0").replaceAll("x","1");
    System.out.println("One's complement of your binary number is " +complement);
    int n = 0;
    int k = binary.length()-n;
    String m = charAt(k);
    if (charAt(k).equals(i)) binary.replace(charAt(k), j);
    else n++;
    System.out.println(binary);
//    do {k++; }
//    while (charAt(k).equals(i))
    private static String charAt(int k) {
        throw new UnsupportedOperationException("Not yet implemented");
    }the bit at the bottom is something netbeans kindly offered to create for me, it cut out a few syntax errors but didn't quite get the program to work.
I'm pretty sure the root of my troubles is coming from the use of the "charAt" method, which as far as i know, would be better used with arrays, but I don't know of another way to sort this stuff...
any help would be muchly appreciated.
Aaron.

ok. The following is a section from the original code (see above). I was hoping this code would take a binary string (ie, '1010101') and change the least significant bit which is a '0' to a '1'. The following section is my attempt at solving this problem, but as I run it, I encounter errors. I've been studying java for 2 months. I would like to know if anybody knows WHY this isn't working, and could offer an alternative method (as I've already stated, I think the use of the method 'charAt' is the main problem)
int n = 0;
    int k = binary.length()-n;
    String m = charAt(k);
    if (charAt(k).equals(i)) binary.replace(charAt(k), j);
    else n++;
    }Is that better?

Int to binary

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