Interesting SQL Question
I have a SQL query problem. I need expert's advice on this.
I have following Table (Retail) in the Database.
Retailer_id Number (36)
HighNo char (10)
LowNo char (10)
HighNo and LowNo columns can have digits and regular characters. Sample Data: 48A, 100, 10021.
My query supposed to get retailer_ids in a certain range of High and Lownos.
For example, between 1000 and 1020 or between 28A and 48B.
Only way to do this is
Select Retailer_id
from Retail
where LowNo <= :mylow
AND HighNo>= :myhigh
AND LENGTH (RTRIM(LowNo) ) = LENGTH (:mylow)
AND LENGTH (RTRIM (HighNo) ) = LENGTH (:myHigh)
Is there any better way?
Thanks in advance
null
I have a SQL query problem. I need expert's advice on this.
I have following Table (Retail) in the Database.
Retailer_id Number (36)
HighNo char (10)
LowNo char (10)
HighNo and LowNo columns can have digits and regular characters. Sample Data: 48A, 100, 10021.
My query supposed to get retailer_ids in a certain range of High and Lownos.
For example, between 1000 and 1020 or between 28A and 48B.
Only way to do this is
Select Retailer_id
from Retail
where LowNo <= :mylow
AND HighNo>= :myhigh
AND LENGTH (RTRIM(LowNo) ) = LENGTH (:mylow)
AND LENGTH (RTRIM (HighNo) ) = LENGTH (:myHigh)
Is there any better way?
Thanks in advance
null
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Sql question : TRUNCATE vs Delete
hi
this is sql question, i don't know where i should post it, so here it is.
i just want to know the best usage of each. both commands delete records in a table, one deletes all, and the other can do the same plus option to delete specified records. if i just want to purge the table. which one is better and why? thanksthis is crucial to my design, i need to be able to
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TRUNCATE
Caution: You cannot roll back a TRUNCATE statement.
Purpose
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See Also:
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must have DROP ANY TABLE system privilege. -
Urgent SQL question : how to flip vertical row values to horizontal ?
Hello, Oracle people !
I have an urgent SQL question : (simple for you)
using SELECT statement, how to convert vertical row values to horizontal ?
For example :
(Given result-set)
MANAGER COLUMN1 COLUMN2 COLUMN3
K. Smith ......1
K. Smith ...............1
K. Smith ........................1
(Needed result-set)
MANAGER COLUMN1 COLUMN2 COLUMN3
K. Smith ......1 .......1 .......1
I know you can, just don't remeber how and can't find exactly answer I'm looking for. Probably using some analytic SQL function (CAST OVER, PARTITION BY, etc.)
Please Help !!!
Thanx !
Steve.scott@ORA92> column vice_president format a30
scott@ORA92> SELECT f.VICE_PRESIDENT, A.DAYS_5, B.DAYS_10, C.DAYS_20, D.DAYS_30, E.DAYS_40
2 FROM (select t2.*,
3 row_number () over
4 (partition by vice_president
5 order by days_5, days_10, days_20, days_30, days_40) rn
6 from t2) f,
7 (SELECT T2.*,
8 row_number () over (partition by vice_president order by days_5) RN
9 FROM T2 WHERE DAYS_5 IS NOT NULL) A,
10 (SELECT T2.*,
11 row_number () over (partition by vice_president order by days_10) RN
12 FROM T2 WHERE DAYS_10 IS NOT NULL) B,
13 (SELECT T2.*,
14 row_number () over (partition by vice_president order by days_20) RN
15 FROM T2 WHERE DAYS_20 IS NOT NULL) C,
16 (SELECT T2.*,
17 row_number () over (partition by vice_president order by days_30) RN
18 FROM T2 WHERE DAYS_30 IS NOT NULL) D,
19 (SELECT T2.*,
20 row_number () over (partition by vice_president order by days_40) RN
21 FROM T2 WHERE DAYS_40 IS NOT NULL) E
22 WHERE f.VICE_PRESIDENT = A.VICE_PRESIDENT (+)
23 AND f.VICE_PRESIDENT = B.VICE_PRESIDENT (+)
24 AND f.VICE_PRESIDENT = C.VICE_PRESIDENT (+)
25 AND f.VICE_PRESIDENT = D.VICE_PRESIDENT (+)
26 AND f.VICE_PRESIDENT = E.VICE_PRESIDENT (+)
27 AND f.RN = A.RN (+)
28 AND f.RN = B.RN (+)
29 AND f.RN = C.RN (+)
30 AND f.RN = D.RN (+)
31 AND f.RN = E.RN (+)
32 and (a.days_5 is not null
33 or b.days_10 is not null
34 or c.days_20 is not null
35 or d.days_30 is not null
36 or e.days_40 is not null)
37 /
VICE_PRESIDENT DAYS_5 DAYS_10 DAYS_20 DAYS_30 DAYS_40
Fedele Mark 35473 35209
Fedele Mark 35479 35258
Schultz Christine 35700
South John 35253
Stack Kevin 35701 35604 35402 35115
Stack Kevin 35705 35635 35415 35156
Stack Kevin 35706 35642 35472 35295
Stack Kevin 35707 35666 35477
Stack Kevin 35667 35480
Stack Kevin 35686
Unknown 35817 35698 35596 35363 35006
Unknown 35702 35597 35365 35149
Unknown 35724 35599 35370 35155
Unknown 35600 35413 35344
Unknown 35601 35451 35345
Unknown 35602 35467
Unknown 35603 35468
Unknown 35607 35475
Unknown 35643 35508
Unknown 35644
Unknown 35669
Unknown 35684
Walmsley Brian 35725 35598
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An interesting synchronization question
hey all, I have an interesting synchronization question to ask you.
Suppose that I have 20 tasks and 8 worker threads, each worker is assigned a task by the main thread, and then main thread suspends until one worker has finished its task. Then main thread create another task and handles to a new worker thread until all tasks are finished.
so code in main thread is something like this.
boolean has_more_task, has_more_worker;
do {
if (has_more_task && has_more_worker)
* create new thread and assign it a new task
else if ( has_more_task && !has_more_worker)
wait();
else if ( !has_more_task && has_more_worker)
wait();
} while (has_more_task || has_more_worker)the problem is that I don't quite familiar with synchronized key word. so I don't know how to share a synchronized vaiable between main thread and worker thread. can anybody do me a help?
Remember that main thread should be waken up by either of the 8 worker threads !!you can follow producer consumer conept
create a queue. main thread will push task in queue.
and worker threads will consumer task from queue.
you just need to synchronize operation on queue.
when there is no task in queue then worker thread will notify to main thread and
will call wait().
then main thread again put the more task in queue and send notification signal to worker thread and then call wait().
Class JobQueue
//should be called by worker thread
public synchronized getNextTask()
//shoule be invoked by main thread
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} -
SQL Question - Interesting One
I need to write a SINGLE SQL statement which has two different
queries, if the first query retrieves records then there is no
need to execute the second one, if the first query doesn't
retrieve the records then I need to make use of second query to
retrieve records.
Is it possible to do in a SINGLE SQL statement? I want to use it
in building a View, i.e, the reason why I am looking for SINGLE
SQL statement
For example,
First Query :- Select Ename from Emp where Deptno=10 and Sal=100;
If this query can retrieve records then I need not execute the
second query
Second Query :- Select Ename from Emp where Deptno=10;
Any help much appreciated?
Thanks,
VenuJohn,
My understanding of the requirements is that, if there are rows
where deptno = 10 and sal = 100, then the query should return
only those rows that meet that criteria. However, if there are
no rows where deptno = 10 and sal = 100, then the query should
return all rows where deptno = 10, regardless of the sal.
I included some tests and results below. In the first test, I
used the emp demo table with test data that did not include any
rows where deptno = 10 and sal = 100. I then demonstrated a
query that correctly returned 3 rows where deptno = 10. I then
ran your query which incorrectly resulted in no rows returned.
Then I added a row where deptno = 10 and sal = 100 and re-ran
both queries and they both correctly returned only the 1 row
where deptno = 10 and sal = 100.
In the next test, I created a table similar to your table and
inserted the sample data that you provided, which did not
include any rows where ft_pct = 30. I ran both queries and they
both correctly returned 14 rows where job_no = 'EG01'. Then, I
added a row where ft_pct = 30 and re-ran both queries. My query
correctly returned only the one row where ft_pct = 30. Your
query incorrectly returned 15 rows, which included the original
14 and the one I added, instead of just the one I added.
The manner in which your query performed with your data is what
I expected it to do. However, I don't understand why it seems
to behave differently with the emp demo data. With one table it
produces the wrong results under one condition and with the
other table it produces the wrong results under the other
condition.
Barbara
SQL> -- test using emp demo table:
SQL> -- table structure:
SQL> DESC emp
Name Null? Type
EMPNO NOT NULL NUMBER(4)
ENAME VARCHAR2(10)
JOB VARCHAR2(9)
MGR NUMBER(4)
HIREDATE DATE
SAL NUMBER(7,2)
COMM NUMBER(7,2)
DEPTNO NUMBER(2)
SQL> DELETE FROM emp
2 WHERE deptno = 10
3 AND sal = 100
4 /
1 row deleted.
SQL> COMMIT
2 /
Commit complete.
SQL> -- test data without sal = 100:
SQL> SELECT ename, deptno, sal
2 FROM emp
3 /
ENAME DEPTNO SAL
SMITH 20 800
ALLEN 30 1600
WARD 30 1250
JONES 20 2975
MARTIN 30 1250
BLAKE 30 2850
CLARK 10 2450
SCOTT 20 3000
KING 10 5000
TURNER 30 1500
ADAMS 20 1100
JAMES 30 950
FORD 20 3000
MILLER 10 1300
14 rows selected.
SQL> -- query with correct results:
SQL> SELECT ename, deptno, sal
2 FROM emp
3 WHERE deptno = 10
4 AND sal = 100
5 UNION
6 SELECT ename, deptno, sal
7 FROM emp
8 WHERE deptno = 10
9 AND NOT EXISTS
10 (SELECT ename, deptno, sal
11 FROM emp
12 WHERE deptno = 10
13 AND sal = 100)
14 /
ENAME DEPTNO SAL
CLARK 10 2450
KING 10 5000
MILLER 10 1300
SQL> -- QUERY WITH WRONG RESULT:
SQL> -- ???????????????????????
SQL> SELECT ename, deptno, sal
2 FROM emp
3 WHERE (deptno=10 and sal=100)
4 OR deptno=10
5 /
no rows selected
SQL> -- ???????????????????????
SQL> -- ABOVE RESULT IS WRONG
SQL> INSERT INTO emp (empno, ename, deptno, sal)
2 VALUES (9999, 'TEST', 10, 100)
3 /
1 row created.
SQL> COMMIT
2 /
Commit complete.
SQL> -- test data with sal = 100
SQL> SELECT ename, deptno, sal
2 FROM emp
3 /
ENAME DEPTNO SAL
SMITH 20 800
ALLEN 30 1600
WARD 30 1250
JONES 20 2975
MARTIN 30 1250
BLAKE 30 2850
CLARK 10 2450
SCOTT 20 3000
KING 10 5000
TURNER 30 1500
ADAMS 20 1100
JAMES 30 950
FORD 20 3000
MILLER 10 1300
TEST 10 100
15 rows selected.
SQL> -- query with correct results:
SQL> SELECT ename, deptno, sal
2 FROM emp
3 WHERE deptno = 10
4 AND sal = 100
5 UNION
6 SELECT ename, deptno, sal
7 FROM emp
8 WHERE deptno = 10
9 AND NOT EXISTS
10 (SELECT ename, deptno, sal
11 FROM emp
12 WHERE deptno = 10
13 AND sal = 100)
14 /
ENAME DEPTNO SAL
TEST 10 100
SQL> -- query with correct results:
SQL> SELECT ename, deptno, sal
2 FROM emp
3 WHERE (deptno=10 and sal=100)
4 OR deptno=10
5 /
ENAME DEPTNO SAL
TEST 10 100
SQL> -- test using org_t table:
SQL> CREATE TABLE org_t
2 (org_cd VARCHAR2 (5) NOT NULL,
3 job_no VARCHAR2 (4) NOT NULL,
4 ft_pct NUMBER (3) NOT NULL)
5 /
Table created.
SQL> INSERT INTO org_t
2 VALUES ('03538', 'EG01', 40)
3 /
1 row created.
SQL> INSERT INTO org_t
2 VALUES ('06763', 'EG01', 40)
3 /
1 row created.
SQL> INSERT INTO org_t
2 VALUES ('08026', 'EG01', 40)
3 /
1 row created.
SQL> INSERT INTO org_t
2 VALUES ('08105', 'EG01', 40)
3 /
1 row created.
SQL> INSERT INTO org_t
2 VALUES ('08200', 'EG01', 40)
3 /
1 row created.
SQL> INSERT INTO org_t
2 VALUES ('08232', 'EG01', 40)
3 /
1 row created.
SQL> INSERT INTO org_t
2 VALUES ('08233', 'EG01', 40)
3 /
1 row created.
SQL> INSERT INTO org_t
2 VALUES ('08286', 'EG01', 40)
3 /
1 row created.
SQL> INSERT INTO org_t
2 VALUES ('08909', 'EG01', 40)
3 /
1 row created.
SQL> INSERT INTO org_t
2 VALUES ('08984', 'EG01', 40)
3 /
1 row created.
SQL> INSERT INTO org_t
2 VALUES ('09073', 'EG01', 40)
3 /
1 row created.
SQL> INSERT INTO org_t
2 VALUES ('09723', 'EG01', 1)
3 /
1 row created.
SQL> INSERT INTO org_t
2 VALUES ('09724', 'EG01', 100)
3 /
1 row created.
SQL> INSERT INTO org_t
2 VALUES ('09752', 'EG01', 1)
3 /
1 row created.
SQL> COMMIT
2 /
Commit complete.
SQL> -- test data without ft_pct = 30:
SQL> SELECT org_cd, job_no, ft_pct
2 FROM org_t
3 /
ORG_C JOB_ FT_PCT
03538 EG01 40
06763 EG01 40
08026 EG01 40
08105 EG01 40
08200 EG01 40
08232 EG01 40
08233 EG01 40
08286 EG01 40
08909 EG01 40
08984 EG01 40
09073 EG01 40
09723 EG01 1
09724 EG01 100
09752 EG01 1
14 rows selected.
SQL> -- query with correct results:
SQL> SELECT org_cd, job_no, ft_pct
2 FROM org_t
3 WHERE job_no = 'EG01'
4 AND ft_pct = 30
5 UNION
6 SELECT org_cd, job_no, ft_pct
7 FROM org_t
8 WHERE job_no = 'EG01'
9 AND NOT EXISTS
10 (SELECT org_cd, job_no, ft_pct
11 FROM org_t
12 WHERE job_no = 'EG01'
13 AND ft_pct = 30)
14 /
ORG_C JOB_ FT_PCT
03538 EG01 40
06763 EG01 40
08026 EG01 40
08105 EG01 40
08200 EG01 40
08232 EG01 40
08233 EG01 40
08286 EG01 40
08909 EG01 40
08984 EG01 40
09073 EG01 40
09723 EG01 1
09724 EG01 100
09752 EG01 1
14 rows selected.
SQL> -- query with correct results:
SQL> SELECT org_cd,job_no,ft_pct
2 FROM org_t
3 WHERE (job_no = 'EG01' and ft_pct = 30)
4 OR job_no = 'EG01'
5 /
ORG_C JOB_ FT_PCT
03538 EG01 40
06763 EG01 40
08026 EG01 40
08105 EG01 40
08200 EG01 40
08232 EG01 40
08233 EG01 40
08286 EG01 40
08909 EG01 40
08984 EG01 40
09073 EG01 40
09723 EG01 1
09724 EG01 100
09752 EG01 1
14 rows selected.
SQL> INSERT INTO org_t
2 VALUES ('99999', 'EG01', 30)
3 /
1 row created.
SQL> COMMIT
2 /
Commit complete.
SQL> -- test with ft_pct = 30:
SQL> -- query with correct results:
SQL> SELECT org_cd, job_no, ft_pct
2 FROM org_t
3 WHERE job_no = 'EG01'
4 AND ft_pct = 30
5 UNION
6 SELECT org_cd, job_no, ft_pct
7 FROM org_t
8 WHERE job_no = 'EG01'
9 AND NOT EXISTS
10 (SELECT org_cd, job_no, ft_pct
11 FROM org_t
12 WHERE job_no = 'EG01'
13 AND ft_pct = 30)
14 /
ORG_C JOB_ FT_PCT
99999 EG01 30
SQL> -- QUERY WITH WRONG RESULT:
SQL> -- ???????????????????????
SQL> SELECT org_cd,job_no,ft_pct
2 FROM org_t
3 WHERE (job_no = 'EG01' and ft_pct = 30)
4 OR job_no = 'EG01'
5 /
ORG_C JOB_ FT_PCT
03538 EG01 40
06763 EG01 40
08026 EG01 40
08105 EG01 40
08200 EG01 40
08232 EG01 40
08233 EG01 40
08286 EG01 40
08909 EG01 40
08984 EG01 40
09073 EG01 40
09723 EG01 1
09724 EG01 100
09752 EG01 1
99999 EG01 30
15 rows selected.
SQL> -- ???????????????????????
SQL> -- ABOVE RESULT IS WRONG -
I have seen the following in some sql, but not sure of the difference.
select abc, NULL from xyz where .....
select abc, to_char(NULL) from xyz where ....
my question is there a difference between NULL and TO_CHAR(NULL) ?
Thanks.BluShadow wrote:
Looks like someone was trying to cast the null to a varchar2 datatype so that SQL knew the datatype of the column. In that case they should have used the CAST function...
Blu:
Just out of curiosity, any particular reason for the preference for cast instead of to_datatype(null)? I often use that construct, particularly in union type queries. The cast is sematically meaningless in a union query since the column will get the size of the largest column in the query.
SQL> set null null
SQL> select *
2 from (select 1 id, null c1, to_char(null) c2, cast(null as varchar2(10)) c3 from dual
3 union all
4 select 2, 'Hello there', 'Hello there', 'Hello there' from dual);
ID C1 C2 C3
1 null null null
2 Hello there Hello there Hello there
SQL> create view v as
2 select *
3 from (select 1 id, null c1, to_char(null) c2, cast(null as varchar2(10)) c3 from dual
4 union all
5 select 2, 'Hello there', 'Hello there', 'Hello there' from dual);
View created.
SQL> desc v;
Name Null? Type
ID NUMBER
C1 VARCHAR2(11)
C2 VARCHAR2(11)
C3 VARCHAR2(11)About the only place where I would use an explicit cast is if I was "hiding" the content of a column in a view, but needed to maintain the same structure as the table.
John -
Hello. I work for Clarian Health in Indianapolis and am trying to learn as much as possible about the SQL databases, both AWDB and HDS so that I can handle the reporting for our Revenue Cycle Customer Service.
I am currently working my way through the Database Schema Handbook for Cisco Unified ICM /Contact Center Enterprise & Hosted. I’m also reviewing the explanation pages that are available for the reports on WebView. During my reviews, I have noticed a few things that confuse me.
My questions are:
1. Why do a majority of the tables on our SQL Server start with “t_”?
2. Why do some of the tables have data on the AWDB server but not on the HDS server, and vice versa? (Examples: t_Agent and t_Agent_Team and t_Agent_Team_Member and t_Person are blank on the HDS database but not blank on the AWDB database; but the t_Agent_Logout is blank on the AWDB database and not blank on the HDS database)
3. When data is moved to the HDS server every 30 minutes, is it also removed from the corresponding AWDB table?
4. In review of the agent26: Agent Consolidated Daily Report syntax info located on the WebView, 1 of the calculations uses the LoggedOnTimeToHalf from the Agent_Half_Hour table while the remaining calculations uses the same field from the Agent_Skill_Group_Half_Hour table. Can you please tell me why this is? Why would all of the percent calculations not use the data from the same table? (The % of time Agent paused and/or put a task on hold uses the Agent_Half_Hour Table. All other % calculations uses the same field from the Agent_Skill_Group_Half_Hour Table.)
5. Also in reviewing the agent26: Agent Consolidated Daily Report syntax info, I noticed that it contains the Skill_Group table, the Agent_Half_Hour table and the Media_Routing_Domain table. Both the Skill Group table and the Agen_Half_Hour table contain links to the Media_Routing_Domain table. Which relationship/join is actually utilized for this report?
6. Why doesn't the LoggedOnTimeToHalf field on both the Agent_Half_Hour table and the Agent_Skill_Group_Half_Hour table have the same value in them?
7. On the agent_26: Agent Consolidated Daily Report syntax explanation page, the Agent State Times: Log on Duration says that it is derived using the Agent_Half_Hour.LoggedOnTimeToHalf field, but when i convert this field to HH:MM:SS, it does not match the actual WebView report. But, when I use the Agent_Skill_Group_Half_Hour.LoggedOnTimeToHalfHour, it does match. Which one is correct?
8. On the agent_26: Agent Consolidated Daily Report, why does the Completed Tasks: Transfer Out contain both the TransferredOutCallsToHalf and the NetTransferredOutCallsToHalf fields? What's the difference between the two? What Transfer out data writes to each field?
Thank you.
Angie Combest
Clarian Health
[email protected]You need to be careful when looking at the three databases - Logger, AW, HDS - which use the same schema. But many of what appear to be tables in the AW are really views into the t_ tables in the HDS - the data is not there in the AW DB. You are right to look at the schema - but check with SQL Enterprise to understand a bit more.
In essence, the AW DB is for configuration data and real-time data. The HDS is for historical data. You can query the AW DB for (say) Call_Type_Half_Hour data and join with the Call_Type table to resolve the call type ID into its name - but the data is really in the HDS through the view.
The DB design is quite complex and sophisticated - many things are not obvious.
Keep up your research.
Regards,
Geoff -
SQL question- on how to handle groups of records at a time.
Hi,
I have a sql that looks like the following:
insert into INVALID_DATES_TMP
(id, gid, created, t_rowid, updated)
select id, gid, created, rowid, updated
from TABLE1
where fix_invalid_date_pkg.is_date_invalid('TABLE1', 'CREATED', ROWID) = 'Y';
COMMIT;
What the above sql does is selects all rows from TABLE1 where the CREATED column
has invalid dates and inserts them into invalid_dates_tmp table. So we can process/fix
those invalid dates from the temp table. Problem is our DBA said Table1 can have
millions of rows so the above sql can be very database intensive. So, I need to
figure out another way that may handle chunks of rows at a time from table1.
Any ideas are appreciated!
ThankYou,
Radhika.Hallo,
in general INSERT AS SELECT is the fastest method to insert into the table.
Probably you can use direct load ? (Hint APPEND).
Other options (INSERT IN LOOP or BULK + FORALL) are slower.
I think, this method is optimal.
Another question is, the function itself. It is not clear, whether it searches the invalid dates optimal. I suppose strong, that function uses dynamic SQL.
Why ? It is better to search static . Or you use this function for many other columns ? Could you post the function also ?
Regards
Dmytro -
Parent - child table issue wrt to count - SQL question
I have a scenario:
There are 2 tables (parent and child). lets say, case summary table and task level dimension table.
for every case id in case summary table, there would be multiple tasks in task level dim table with a flag indicator set to 1 for all tasks.
but while counting the number of cases active with flag indicator 1 (ofcourse when joining case summary table with task dimension table), for a case id only 1 instance of task needs to be accounted (even though it has more than one task , for counting active cases, the flag ind corresponding to a task in a case if set to 1 , then the case is considered active)..but while joining and taking count of case ids with flag indicator as 1, you get the count of every task row of a case which is incorrect logically. how to discard the rest of child records of a case in child table (task dimension table)?
I am not sure how to achieve this in sql query
Kindly help!
Case summary table
case id, busininess_unit, agent_name
1001, admin, Ram
1002, Finance, Sam
task table
case id, task_id,task_name, flag_indicator
1001, 1, 'New', 1
1001,2, 'Open',1
1001,3,'In progress',1
1002, 4, 'New', 1
(In fact task_id is not a big deal... even you can assume task id doesn't exist..only task name ... )
now my question... if my query should get the current active cases (ind=1); as per above it should essentially give 2... but my query gives me 4..you know the reason why.. but how do i get the correct count?
Thanks!may be you need just this:
select count(distinct case_id) from task
where indicator = 1;
If this is not what you are looking for, please elaborate and tell us the expected output and rest of the details as mentioned in FAQ Re: 2. How do I ask a question on the forums?: -
Hi,
I am working on a SQL, please help ms with the question
below .... thanks
(1)Increase by 10% salary of these captain pilots who have
traveled more than 800,000 miles.
Routes | | Flights | |Pilots |
| | | | |
#routeID | | #flightNO | |#pilotID |
depAirportID | | airplaneNO| |*name |
arrAirportID |_______/| pilotID |\___________|*hours_in_air|
length | \| routeID |/ |*grade |
______________| |_____________| |*salary |
|____________|If the length column in routes is in hours, and it represents
additional hours to those shown in hours_in_air in pilots, then
the following should work:
UPDATE pilots
SET salary = salary * 1.1
WHERE pilotid in (SELECT a.pilotid
FROM pilots a,
(SELECT b.pilotid,sum(c.length) new_hours
FROM flights b, routes c
WHERE b.routeid = c.routeid
GROUP BY b.pilotid) d
WHERE a.pilotid = d.pilotid and
new_hours + hours_in_air >= 80000)I suspect that you probably need to add additional criteria to
the sub-query from flights and routes to take into account only
flights since the hours_in_air column from pilots was last
updated. However, your table structures do not indicate any
date sensitivity. If the table flights is emptied every time
hours_in_air is updated, then the query above will work. -
SQL Question (Select rows with multiple records)
Hello Gurus,
I am learning SQL and have a question. Thanks for your time and help.
I have 2 tables TABLE_AA and TABLE_BB. Both tables have two columns ID, DATA.
TABLE_AA is connected to TABLE_BB through ID field (TABLE_AA.AA_DATA = TABLE_BB.BB_DATA)
TABLE_AA
~~~~~~~
AA_ID______AA_DATA
~~~~~~~~~~~~~~~~
1111_______XXXX
2222_______QQQQ
3333_______ZZZZZ
4444_______PPPPP
~~~~~~~
TABLE_BB
~~~~~~~
BB_ID BB_DATA
~~~~~~~~~~~~~~~~
1111_______AAAA
2222_______BBBB
3333_______CCCC
3333_______DDDD
4444_______EEEE
I am looking to get those AA_ID values that have multiple in TABLE_BB for their parent reference in TABLE_BB.
So, from the above example, the sql should return the following as AA_ID 3333 has more than 1 reference value in BB_ID
AA_ID_____BB_ID
~~~~~~~~~~
3333______CCCC
3333______DDDDHi,
It's working fine. !!
14:10:05 topgun>With a As
14:10:06 2 (
14:10:06 3 Select 1111 c1, 'AAAA' c2 From dual Union All
14:10:06 4 Select 2222 , 'BBBB' From dual Union All
14:10:06 5 Select 3333 , 'CCCC' From dual Union All
14:10:06 6 Select 4444 , 'DDDD' From dual
14:10:06 7 ), b As
14:10:06 8 (
14:10:06 9 Select 1111 c1,'AAAA' c2 From dual Union All
14:10:06 10 Select 2222 , 'BBBB' From dual Union All
14:10:06 11 Select 3333 , 'CCCC' From dual Union All
14:10:06 12 Select 3333 , 'DDDD' From dual Union All
14:10:06 13 Select 4444 , 'EEEE' From dual
14:10:06 14 )
14:10:06 15 Select c1,
14:10:06 16 c2
14:10:06 17 From
14:10:06 18 (
14:10:06 19 Select a.c1,
14:10:06 20 b.c2,
14:10:06 21 Count(*) over (Partition By a.c1 Order By a.c1) cnt
14:10:06 22 From a,
14:10:06 23 b
14:10:06 24 Where a.c1 = b.c1
14:10:06 25 )
14:10:06 26 Where cnt = 2;
C1 C2
3333 CCCC
3333 DDDD- Pavan Kumar N -
SQL question for to get a top customer
Hi All,
I am prasanna. I have a question on SQL,to get a top customer based on year and customer name.I written query like this. But i got an error.
select calendar_year,cust_first_name,max(sum(amount_sold)) from sales,times,customers where sales.cust_id=customers.cust_id and times.time_id=sales.time_id group by calendar_year,cust_first_name
The error is like this:
*Error starting at line 1 in command:
select calendar_year,cust_first_name,max(sum(amount_sold)) from sales,times,customers where sales.cust_id=customers.cust_id and times.time_id=sales.time_id group by calendar_year,cust_first_name
Error at Command Line:1 Column:7
Error report:
SQL Error: ORA-00937: not a single-group group function
00937. 00000 - "not a single-group group function"*
*Cause:
Action:
Thanks inadvace
Regards,
prasannaIt is not clear what you want. Code below will return a customer with highest total amout sold regardless of year:
select calendar_year,
cust_first_name,
total_amount_sold max_amount_sold
from (
select calendar_year,
cust_first_name,
sum(amount_sold) total_amount_sold,
row_number() over(order by sum(amount_sold) desc) rn
from sales,
times,
customers
where sales.cust_id=customers.cust_id
and times.time_id=sales.time_id
group by calendar_year,
cust_first_name
where rn = 1
/Keep in mind, if more than one customer has that highest total amount sold and you want all such customers:
select calendar_year,
cust_first_name,
total_amount_sold max_amount_sold
from (
select calendar_year,
cust_first_name,
sum(amount_sold) total_amount_sold,
rank() over(order by sum(amount_sold) desc) rn
from sales,
times,
customers
where sales.cust_id=customers.cust_id
and times.time_id=sales.time_id
group by calendar_year,
cust_first_name
where rn = 1
/And if you want top customer for each calendar year:
select calendar_year,
cust_first_name,
total_amount_sold max_amount_sold
from (
select calendar_year,
cust_first_name,
sum(amount_sold) total_amount_sold,
row_number() over(partition by calendar_year order by sum(amount_sold) desc) rn
from sales,
times,
customers
where sales.cust_id=customers.cust_id
and times.time_id=sales.time_id
group by calendar_year,
cust_first_name
where rn = 1
/Keep in mind, if more than one have that highest total amount sold and you want all such customers:
select calendar_year,
cust_first_name,
total_amount_sold max_amount_sold
from (
select calendar_year,
cust_first_name,
sum(amount_sold) total_amount_sold,
rank() over(partition by calendar_year order by sum(amount_sold) desc) rn
from sales,
times,
customers
where sales.cust_id=customers.cust_id
and times.time_id=sales.time_id
group by calendar_year,
cust_first_name
where rn = 1
/SY.
Edited by: Solomon Yakobson on Dec 22, 2011 9:24 AM -
Hi,
I need to select the set of records only in Table A, but not in Table B. I think that the correct SQL is:
select k~vbeln
into data
from vbak as k
inner join vbfa as f on kvbeln = fvbelv
where f~vbelv is null.
But the following message appears: u201CNo fields from the right-hand table of a LEFT OUTER JOIN may appear in the WHERE condition: u201CF~VBELBu201Du201D.
Thanks in advance,
Ricard.Hi Oscar & William,
first of all: The database meaning of NULL is that for the field in question no value is stored for an existing record.
In SAP tables we rarely have any NULL values. Only if you extend an existing table, i.e. append a new field, the database will expand the structure but not store INITIAL values for the new field in all records.
Second, just a hint: although the SAP example uses the mystifying ALIAS (AS) addition for joins, it does not help except reducing the code transparency:
SELECT vbak~vbeln
INTO lw_data
FROM vbak
INNER JOIN vbfa ON vbak~vbeln = vbfa~vbelv
WHERE vbfa~vbelv IS NULL.
<you can do your process here>
ENDSELECT.
Is 100 % the same. Nevertheless it will never retrieve a single record because vbelv is never stored as a NULL value.
I think this can be solved using a subquery
DATA : lt_data TYPE table of vbak-vbeln.
SELECT vbeln
INTO lt_data
FROM vbak
WHERE NOT EXISTS
( SELECT * FROM vbfa WHERE vbelv = vbak~vbeln ).
<you can do your process here>
ENDSELECT.
To be honest: I did not try the code, never played with subqueries though I should do so.
Regards,
Clemens -
Gentlemen,
I have a table in Locator that is made of of polygons (loaded via MapInfo EasyLoader). What I need to do is to send Oracle a latitude and longitude and have Oracle return the polygon in which that location falls in. I am new to loator and so this is probably an easy question. I have been experimenting with SQL statements and I tried the following:
Select MUSYM From ENCLASS_USER.SOILMU_A_IA001
Where SDO_INSIDE(sdo_geometry(2001, 8307, sdo_point_type(-94.53825,41.38343, NULL),null,null),GEOLOC) = 'TRUE'
The error returned indicates the "interface not supportrd without a spatial index". The table has a spatial index, however I think that the problem is with the latitude and longitude portion of the SQL. In the above statement, MUSYM is the value of the column in the polygon table I need returned and GEOLOC is the SDO_GEOMETRY Column. The Lat/Long coordinates are -94.53825,41.38343 in the example above.
How do I construct this SQL so that it will work?
Thansk for your help,
Tim Fast
Pioneer Hi-Bred International, Inc.The SQL that I am using is:
Select MUSYM From ENCLASS_USER.SOILMU_A_IA001
Where SDO_INSIDE
(GEOLOC,sdo_geometry(2001, 8307, sdo_point_type(-94.542208,41.383796, NULL),null,null)) = 'TRUE'
It should return the MUSYM of "370B"
I don't know how to send you the sample rows but here are three rows in which the first one is the polygon that should be returned. The columns are "|" delimited when exported form Oracle.
AREASYMBOL|SPATIALVER|MUSYM|MUKEY|MI_STYLE|MI_PRINX|GEOLOC
IA001|0|370B|402176||1|(2003, 8307, (-94.54199904, 41.38330203, ), (1, 1003, 1, , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , ), (-94.54315104, 41.38333398, -94.54303116, 41.38323597, -94.543029, 41.38314201, -94.54290912, 41.383044, -94.54279212, 41.38304598, -94.54267188, 41.38294797, -94.54232088, 41.38294896, -94.54184208, 41.38256304, -94.541724, 41.38256502, -94.54160484, 41.38246701, -94.54148784, 41.38246899, -94.54136796, 41.38237197, -94.54125096, 41.38237296, -94.54077612, 41.38198803, -94.54077504, 41.38188903, -94.54030596, 41.38150302, -94.54018896, 41.381505, -94.53960684, 41.38102098, -94.53948984, 41.38102296, -94.53902904, 41.38063704, -94.53856212, 41.38063902, -94.53844404, 41.38073496, -94.53844116, 41.380929, -94.53878784, 41.381217, -94.53890412, 41.38121601, -94.53902004, 41.38131303, -94.53913704, 41.381316, -94.53936996, 41.38150698, -94.53937104, 41.38179498, -94.53960396, 41.38179597, -94.53995784, 41.38208397, -94.53996108, 41.38227801, -94.54067892, 41.38285401, -94.54056516, 41.38295004, -94.54056804, 41.38304904, -94.54092804, 41.38333704, -94.54104504, 41.38333497, -94.54128588, 41.38353, -94.54140216, 41.38352901, -94.54164192, 41.383719, -94.54164912, 41.38391196, -94.54153608, 41.38400898, -94.54130316, 41.384007, -94.541076, 41.38420401, -94.54119588, 41.38429698, -94.54119912, 41.38439598, -94.541319, 41.38448904, -94.54132188, 41.38458804, -94.54144104, 41.38468101, -94.54144392, 41.38478001))
IA001|0|370C2|402178||2|(2003, 8307, (-94.53918312, 41.38067601, ), (1, 1003, 1, , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , ), (-94.53523392, 41.378121, -94.535001, 41.37812397, -94.53488616, 41.37802704, -94.53465288, 41.37803001, -94.53453696, 41.377932, -94.53407112, 41.37793398, -94.53395304, 41.37803001, -94.53395304, 41.37812496, -94.53418416, 41.37831999, -94.53417984, 41.37861204, -94.53429504, 41.37870996, -94.53429396, 41.378805, -94.53440916, 41.37890202, -94.53440304, 41.37928902, -94.53428496, 41.37939, -94.53382092, 41.37939198, -94.53370716, 41.37929397, -94.53335904, 41.37929397, -94.53324204, 41.37939099, -94.53324096, 41.37948999, -94.53358404, 41.37977799, -94.53427884, 41.37977799, -94.53439584, 41.37968097, -94.53451212, 41.37967998, -94.53474792, 41.37948297, -94.53521196, 41.37948099, -94.53532608, 41.379579, -94.535208, 41.37967503, -94.53520404, 41.37987303, -94.53531888, 41.379966, -94.53543408, 41.37996897, -94.53566988, 41.37977304, -94.53601908, 41.37977196, -94.53613284, 41.37986997, -94.53625092, 41.37976899, -94.53636684, 41.37977196, -94.53659616, 41.37996303, -94.536594, 41.38006203, -94.53670812, 41.38016004, -94.53670092, 41.38054704, -94.53658284, 41.38064298, -94.53634992, 41.38064199, -94.53623292, 41.38074198, -94.53600108, 41.38074099, -94.535766, 41.38093296, -94.53588084, 41.38103097, -94.53669408, 41.38102899, -94.53692808, 41.38083702, -94.53727692, 41.38083603, -94.53739212, 41.380929))
IA001|0|570C2|402192||3|(2003, 8307, (-94.54121496, 41.38369497, ), (1, 1003, 1, , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , , ), (-94.53887784, 41.38449498, -94.53875688, 41.38439697, -94.53863988, 41.38439904, -94.53852108, 41.38430103, -94.53817188, 41.38430103, -94.53805992, 41.38439697, -94.53794292, 41.38439904, -94.53770208, 41.38420896, -94.53746988, 41.38420698, -94.53735, 41.38411401, -94.537233, 41.38411104, -94.53711312, 41.38401798, -94.53653208, 41.38401699, -94.53629088, 41.383827, -94.53582612, 41.38382799, -94.53571488, 41.38392402, -94.53571884, 41.38401897, -94.53584016, 41.38411599, -94.53584304, 41.38421103, -94.53620484, 41.38449903, -94.537134, 41.38449498, -94.53725388, 41.38459299, -94.53725892, 41.38468704, -94.53737916, 41.38478496, -94.53738312, 41.38487901, -94.537503, 41.38497702, -94.53819996, 41.38497702, -94.53831984, 41.385069, -94.53843612, 41.38506801, -94.53855492, 41.38516503, -94.53867084, 41.38516404, -94.53891096, 41.38535898, -94.53902688, 41.385357, -94.539384, 41.385645, -94.53949992, 41.38564401, -94.53961188, 41.38554798, -94.53972816, 41.385546, -94.53995388, 41.38535403, -94.54007016, 41.385357, -94.54018284, 41.38526097, -94.54099392, 41.38525899, -94.54111308, 41.38535196, -94.54122612, 41.38525602, -94.54134204, 41.38525899, -94.54156884, 41.38506603, -94.54156308, 41.38487298, -94.54144392, 41.38478001, -94.54144104, 41.38468101, -94.54132188, 41.38458804, -94.541319, 41.38448904))
Tim Fast
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