Is it possible to distinct based on individual column ?

This is the sample data i have , on Oracle 11G ,Release 1.
WITH T AS
(SELECT '001' ID,TO_DATE('16-08-2011','dd-mm-yyyy') DT FROM DUAL UNION
SELECT '002' ID,TO_DATE('16-08-2011','dd-mm-yyyy') DT FROM DUAL UNION ALL
SELECT '003' ID,TO_DATE('16-08-2011','dd-mm-yyyy') DT FROM DUAL UNION ALL
SELECT '004' ID,TO_DATE('16-08-2011','dd-mm-yyyy') DT FROM DUAL UNION ALL
SELECT '005' ID,TO_DATE('16-08-2011','dd-mm-yyyy') DT FROM DUAL UNION ALL
SELECT '005' ID,TO_DATE('16-08-2011','dd-mm-yyyy') DT FROM DUAL UNION ALL
SELECT '005' ID,TO_DATE('16-09-2011','dd-mm-yyyy') DT FROM DUAL UNION ALL
SELECT '006' ID,TO_DATE('16-08-2011','dd-mm-yyyy') DT FROM DUAL UNION ALL
SELECT '006' ID,TO_DATE('16-09-2011','dd-mm-yyyy') DT FROM DUAL
SELECT DISTINCT ID,DT FROM T;From the above query as expected i got all those rows that have distinct ID and DT column . Here a total of 8 rows.
It is also important to note that distinct applies on whole column of a row at time and not on the individual column ,as explained in this example.
Is there any way to get all those rows whose one column do not contain repeated data.
e.g., select ID and DT where ID column do not repeat with same value.

Depends on what you want to do exactly.
But analytics can probably help you out.
E.g.
SQL> WITH T AS
2 (SELECT '001' ID,TO_DATE('16-08-2011','dd-mm-yyyy') DT FROM DUAL UNION
3   SELECT '002' ID,TO_DATE('16-08-2011','dd-mm-yyyy') DT FROM DUAL UNION ALL
4   SELECT '003' ID,TO_DATE('16-08-2011','dd-mm-yyyy') DT FROM DUAL UNION ALL
5   SELECT '004' ID,TO_DATE('16-08-2011','dd-mm-yyyy') DT FROM DUAL UNION ALL
6   SELECT '005' ID,TO_DATE('16-08-2011','dd-mm-yyyy') DT FROM DUAL UNION ALL
7   SELECT '005' ID,TO_DATE('16-08-2011','dd-mm-yyyy') DT FROM DUAL UNION ALL
8   SELECT '005' ID,TO_DATE('16-09-2011','dd-mm-yyyy') DT FROM DUAL UNION ALL
9   SELECT '006' ID,TO_DATE('16-08-2011','dd-mm-yyyy') DT FROM DUAL UNION ALL
10   SELECT '006' ID,TO_DATE('16-09-2011','dd-mm-yyyy') DT FROM DUAL
11 )
12 SELECT id
13 ,      dt
14 FROM
15 (SELECT id
16   ,      dt
17   ,      row_number() over (partition by id order by dt) rn
18   FROM T)
19 WHERE rn = 1;
ID DT
001 16-AUG-11
002 16-AUG-11
003 16-AUG-11
004 16-AUG-11
005 16-AUG-11
006 16-AUG-11
6 rows selected.
SQL>
SQL> WITH T AS
2 (SELECT '001' ID,TO_DATE('16-08-2011','dd-mm-yyyy') DT FROM DUAL UNION
3   SELECT '002' ID,TO_DATE('16-08-2011','dd-mm-yyyy') DT FROM DUAL UNION ALL
4   SELECT '003' ID,TO_DATE('16-08-2011','dd-mm-yyyy') DT FROM DUAL UNION ALL
5   SELECT '004' ID,TO_DATE('16-08-2011','dd-mm-yyyy') DT FROM DUAL UNION ALL
6   SELECT '005' ID,TO_DATE('16-08-2011','dd-mm-yyyy') DT FROM DUAL UNION ALL
7   SELECT '005' ID,TO_DATE('16-08-2011','dd-mm-yyyy') DT FROM DUAL UNION ALL
8   SELECT '005' ID,TO_DATE('16-09-2011','dd-mm-yyyy') DT FROM DUAL UNION ALL
9   SELECT '006' ID,TO_DATE('16-08-2011','dd-mm-yyyy') DT FROM DUAL UNION ALL
10   SELECT '006' ID,TO_DATE('16-09-2011','dd-mm-yyyy') DT FROM DUAL
11 )
12 SELECT id
13 ,      dt
14 FROM
15 (SELECT id
16   ,      dt
17   ,      count(*) over (partition by id) cn
18   FROM T)
19 WHERE cn = 1;
ID DT
001 16-AUG-11
002 16-AUG-11
003 16-AUG-11
004 16-AUG-11

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Hi
I have a table with three columns and I would like to display distinct values in each column. Could any one please help me to get the output.
col1     col2     col3
====     ====     ====
a     1     x
a     2     y
a     3      z
a     4      u
b     5      v
b     6      x
b     7      x
b     9      x
b     10     y
b     11     y
b     12     y
b     13     y
b     14     x
b     15     y
b     16     z
b     17     u
b     18     v
b     19     x
b     20     x
c     21     x
c     22     y
c     23     y
c     24     y
c     25     y
c     26     x
c     27     y
c     28     z
Output needed
===========
col1     col2     col3
====     ====     ====
a     1     x
b     2     y
c     3     z
     4     u
     5     v
     6
     7
     9
     10
     11
     12
     13
     14
     15
     16
     17
     18
     19
     20
     21
     22
     23
     24
     25
     26
     27
     28
Thanks
Vasanth

but the only drawback - you need to know the column, comprising the biggest amount of distinct values beforehand.No. There is no any difference in which column will be chosen as "based".
For demo purposes I've added extra row number column to show full generality and symmetry of the approach:
exec dbms_random.seed(0)
with t as ( select chr(ascii('a') + dbms_random.value(0, 3)) as c1,
                   trunc(dbms_random.value(1, 20))           as c2,
                   chr(ascii('u') + dbms_random.value(0, 6)) as c3
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                   lag(to_number(null), 1, c2) over (partition by c2 order by null) as c2,
                   lag(          null, 1, c3) over (partition by c3 order by null) as c3
              from t
   tt2 as ( select tt1.*,
                   row_number() over (order by c1) as rn1,
                   row_number() over (order by c2) as rn2,
                   row_number() over (order by c3) as rn3,
                   rownum rn
              from tt1
   tt3 as ( select case when rn1 > rn
                        then last_value(c1) over (order by rn1 range between abs(rn1 - rn) preceding
                                                                         and abs(rn1 - rn) preceding)
                        else last_value(c1) over (order by rn1 range between abs(rn - rn1) following
                                                                         and abs(rn - rn1) following)
                   end as c1,
                   case when rn2 > rn
                        then last_value(c2) over (order by rn2 range between abs(rn2 - rn) preceding
                                                                         and abs(rn2 - rn) preceding)
                        else last_value(c2) over (order by rn2 range between abs(rn - rn2) following
                                                                         and abs(rn - rn2) following)
                   end as c2,
                   case when rn3 > rn
                        then last_value(c3) over (order by rn3 range between abs(rn3 - rn) preceding
                                                                         and abs(rn3 - rn) preceding)
                        else last_value(c3) over (order by rn3 range between abs(rn - rn3) following
                                                                         and abs(rn - rn3) following)
                   end as c3
              from tt2
select c1, c2, c3 from tt3
where c1 || c2 || c3 is not null
order by c1, c2, c3
C1            C2 C3
a              1 u
b              3 v
c              4 w
               5 x
               7 y
               8 z
               9
              11
              13
              15
              16
              17
              19
13 rows selected.P.S. Thanks to [url http://www.sql.ru/forum/actualthread.aspx?bid=3&tid=482506&hl=over+range#4785373]Vladimir Sitnikov for the demo of the approach.

Eliminate Data based on a column

Hello All,
I am in very weird situation. I have to filter data based on a column. For example, my data is like :
Col1       Col2        Col3       Col4
A1         A              B           C
A2         A              B            D
A3         A              B            E
F           G              H             I
J            K               L             M
I have to filter data based on col1 which has the maximum if Col2 and Col3 have same value. So the o/p of above data will be if (A3> A2 > A1) as Col2 and Col3 have same value A and B:
Col1       Col2            Col3       Col4
A3             A              B            E
F              G               H             I
J               K               L             M
Please suggest.

Hi,
One way to do that is a Top-N Query . Since you didn't post your table, I'll use scott.emp to illustrate. Ename, deptno, job and hiredate in scott.emp correspond to col1, col2, col3 and co4l (respectively) in your table.
WITH got_r_num AS
SELECT ename, deptno, job, hiredate
, ROW_NUMBER () OVER ( PARTITION BY deptno, job
               ORDER BY      ename   DESC
       ) AS r_num
FROM scott.emp
SELECT ename, deptno, job, hiredate
FROM got_r_num
WHERE r_num = 1
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Hi,
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<Query>
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<ElementPath IgnoreNamespaces="True">*</ElementPath>
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Sam.

Hi Sam,
By code, the CAML language doesn’t have any reserved word (or tag) to set this particular filter to remove duplicate results.
In this case, we could use the custom code to get distinct records.
Here are the detailed steps:
1.         Create a hidden parameter that gets all the records in one field.
Note: Please create another dataset that is same of the main dataset. This dataset is used for the parameter.
2.         Create a function that used to remove the duplicate records.
Here is the code:
Public Shared Function RemoveDups(ByVal items As String) As String
Dim noDups As New System.Collections.ArrayList()
Dim SpStr
SpStr = Split(items ,",")
For i As Integer=0 To Ubound(Spstr)
If Not noDups.Contains(SpStr(i).Trim()) Then
noDups.Add(SpStr(i).Trim())
End If
Next
Dim uniqueItems As String() = New String(noDups.Count-1){}
noDups.CopyTo(uniqueItems)
Return String.Join(",", uniqueItems)
End Function
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Please set the available value to be =Split(Code.RemoveDups(JOIN(Parameters!ISSUE_STATUS_TEMP.Value, ",")), ",")
And the default value to be the value you what such as the first value:
=Split(Code.RemoveDups(JOIN(Parameters!ISSUE_STATUS_TEMP.Value, ",")), ",").(0)
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5.         In the “Filters” tab, set the filter to be:
Expression: <The field to be filter>
Operator: =
Value: =Parameters!Region.Value
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Thanks,
Jin
Jin Chen - MSFT

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http://www.cleverworkarounds.com/2013/09/23/how-to-filter-on-a-managed-metadata-column-via-rest-in-sharepoint-2013/comment-page-1/
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http://platinumdogs.me/2013/03/14/sharepoint-adventures-with-the-rest-api-part-1/
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Linda Li
Linda Li
TechNet Community Support

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mahongue wrote:
Is it possible to switch the rows and columns of a table? The reason I ask is
that it would be easier for me to input the data with the number at the top
of a column and the fields going down. But it would be easier to read the
data with the number on the left and the fields going to the right. Is it
possible to switch a table in this way?
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Table 1
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========
1   o   p   q
2   r   s   t
3   u   v   w
Table 2
    A   B   C
========
1   o   r   u
2   p   s   v
3   q   t   w
You are right - it would be nice to have a menu item to magically transpose a selected block of cells. But there isn't one. So...
One way to solve this is to use the index() and transpose() functions to accomplish row and column cell transposition. If you are going to use a 1:1 cell correspondence and change the header columns and rows also, you can use this:
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where Table # and <range> is substituted as in the following fashion:
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Cautions:
o The target table must match the swapped cell length and width dimension. For example, if the original data range is 6 columns wide by 4 rows deep, then the corresponding table or range to hold the transposition must be 4 columns wide by 6 rows deep.
o If your transposed data block is to be offset from the origin of the new table, then you will need to include a subtractive offset into your cell formula, since in the transpose() function the data in the master data range is referenced from its position with the master range, not its cell position in the table. Such an offset is necessary because this example formula uses the target row and column numbers to arrive at indexed positions.
For example, if the new data range is to be offset one column to the right and one row below from the target table's origin then you must subtract (-1) from the cell and from the column references in the formula:
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If someone has a better solution I'd be glad to hear of it.

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as an dynamic lov, I don't seem to be able to execute this statement
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Hello again,
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Here's my latest version plus an alternative, which both seem to work fine:
create or replace function "GET_PMR_LOV"
(pmr_id in NUMBER)
return VARCHAR2
is
cur INTEGER := DBMS_SQL.OPEN_CURSOR;
fdbk INTEGER;
l_pmr_id NUMBER(9) := pmr_id;
l_stmnt VARCHAR2(1000);
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DBMS_SQL.PARSE (cur, 'select pmr.lov_query from paramaters pmr where pmr.ID ' || '= :L_PMR_ID', DBMS_SQL.NATIVE);
DBMS_SQL.BIND_VARIABLE (cur, 'L_PMR_ID', l_pmr_id);
DBMS_SQL.DEFINE_COLUMN (cur, 1, l_stmnt, 1000);
fdbk := DBMS_SQL.EXECUTE (cur);
fdbk := DBMS_SQL.FETCH_ROWS (cur);
IF fdbk > 0 THEN
DBMS_SQL.COLUMN_VALUE (cur, 1, l_stmnt);
return (l_stmnt);
ELSE
return null;
END IF;
DBMS_SQL.CLOSE_CURSOR (cur);
END;
create or replace function "GET_PMR_LOV2"
(pmr_id in NUMBER)
return VARCHAR2
is
l_pmr_id NUMBER(9) := pmr_id;
l_stmnt VARCHAR2(1000);
BEGIN
EXECUTE IMMEDIATE 'select pmr.lov_query from parameters pmr where pmr.ID = :1'
INTO l_stmnt USING l_pmr_id;
return l_stmnt;
END;
The error-message remains the same, unable to bind :p41_param_id !

Is it possible to distinct based on individual column ?

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