Is it possible to separate U32 value into four U8 values?
Hello all...
I'm working on a project where I need to use electronic load and set it on different values..To communicate with electronic load I need to give commands in HEX format... The format I have to use is an array of U8 with 26 byte... Each byte is dedicated for some purpose... Like
1st byte - start bit
2nd byte - address
3rd byte - command
4th byte - the lowest byte of voltage value
5th byte - the lower byte of voltage value
6th byte - the higher byte of voltage value
7th byte - the highest byte of voltage value
and the manual says
"represent voltage by 4 bytes of HEX. Lower byte are in the front location, higher bytes are in the latter location. For example : voltage is 16.000V, HEX code is 0X00003E80, 4th byte 0X80, 5th byte is 0X3E, 6th byte is 0X00, 7th byte is 0X00."
in program I'm taking input voltage from user which in decimal format like 16V... Now rest work should done by software i.e. converting into HEX n separating it into 4 bytes... Enter into array...
my problem is I'm not able to separate it from U32 to U8. Can anyone please help me...?
thank you.
Solved!
Go to Solution.
Rupali wrote:
"represent voltage by 4 bytes of HEX. Lower byte are in the front location, higher bytes are in the latter location. For example : voltage is 16.000V, HEX code is 0X00003E80, 4th byte 0X80, 5th byte is 0X3E, 6th byte is 0X00, 7th byte is 0X00."
I don't know how you get from 16V to x00003E80, so most likely the manual would provide more information on the details.
If the voltage is actually 4byte SGL (16 (SGL) is however x41800000), you would simply make one small modification as shown here.
In any case, this should get you enough ideas to get started. Good luck!
Message Edited by altenbach on 07-20-2009 05:59 AM
LabVIEW Champion . Do more with less code and in less time .
Attachments:
FlattenData2.png 25 KB
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