Is this the fastest way to create a single color bufferedImage?

Question

Here is my code but it's slow sometimes. Is there a better way?
BufferedImage bi = new BufferedImage(1600,1200, BufferedImage.TYPE_INT_RGB);
int[] rgbs = new int[1600*1200];
for (int j =0; j<1600*1200; j++)
   rgbs[j] = Color.RED;
bi.setRGB(0,0,1600,1200,rgbs,0,1600);

Answer 1

This will be even faster.
int w = 1600;
int h = 1200;
int masks[] = new int[4];
rv[0] = 0xff0000; // red
rv[1] = 0x00ff00; // green
rv[2] = 0x0000ff; // blue
rv[3] = 0xff000000; // alpha
SampleModel sm = new SinglePixelPackedSampleModel(DataBuffer.TYPE_INT,
                                                  w, h, masks);
final int rawData[] = new int[w * h];
DataBufferInt db = new DataBufferInt(rawData, rawData.length);
WritableRaster ras = Raster.createWritableRaster(sm, db, null);
ColorSpace cs = ColorSpace.getInstance(ColorSpace.CS_sRGB);
ColorModel cm = new DirectColorModel(cs, 32, masks[0], masks[1],
                                     masks[2], masks[3],
                                     false,
                                     DataBuffer.TYPE_INT);
BufferedImage  img = new BufferedImage(cm, ras, false, null);
int value = 0xffff0000; // opaque red.
int l = rawData.length;
// Set the image to solid color of the value
for(int i = 0; i < rawData.length; i++)
    rawData[i] = value;