It can be done in C++, can it be done in Java?

Question

Hi
In C++, the following code will change a to 2.
int a = 1;
int *b = &a;
    *b = 2;How can this be done in Java?
My reason is that I implemented SortedSet so that it creates and maintains a binary tree (Assignment pre-requisite).
If the subSet method is called, it returns a portion of the Tree!
How can i get it to return this portion so that any changes which are made to this subSet are automatically reflected in the original Tree? (Just trying to be a geek and get extra brownie points)
Thanx
Tecknick

Answer 1

public class MyInt {
public int sss;
public MyInt myInt = null; // only reference
public MyInt( ){
} // default constructor
} // class MyInt ends here..
// here now..
public MyInt a = new MyInt( );
a.myInt = a; // very Clever
a.sss = 1; // Your ---------------> int a = 1;
public MyInt b = a.myInt; // your
------------------> *b = &a;
b.sss = 2; // Your -----------------> *b = 2;
What is the point of the member field myInt here? The example code gives the effect of just using MyInt myInt = this; and not setting the value in the client code. Why would you ever need to explicitely give an object a reference to itself? You would get exactly the same results (and clearer code) if it wasn't present:
public class MyInt {
  public int value;
  public MyInt(int value) {
    this.value = value;
  public static void main(String[] argv) {
    MyInt a = new MyInt(1);
    a.value = 1;
    MyInt b = a;
    b.value = 2; //Since a == b, a.value is now equal to 2 as well.
}Notice that this is now the same idea as was posted by rabbit3000 earlier - it just doesn't use accessor methods (up to you if you decide you want to) - all it is, is a mutable version ot java.lang.Integer. I couldn't see a good reason for a default constructor, so I took that out too.