Java access to protected methods

Hi,
I use a java toolkit, and want to access a class (Morphy) in it.
There is only one constructor function for class Morphy:
Morphy(WordNet wn).
And here is the doc of the class Morphy.
http://nlp.stanford.edu/nlp/javadoc/wn/doc/danbikel/wordnet/Morphy.html
As some methods in this class are protected, and I will call them.
Here is my code:
import danbikel.wordnet.WordNet;
import danbikel.wordnet.Morphy;
public class wn extends Morphy {
public void test(){
wn a=new wn();
a.morphWord("running","v"); // it is a protected method in Morphy
It just report an compile error: cannot find symbol: symbol : constructor Morphy().
Can anyone tell me how to fix the problem? I don't know how to add the constructor in my code.
Thanks a lot in advance.

Read [this tutorial|http://java.sun.com/docs/books/tutorial/java/IandI/super.html] from "subclass constructors" and then think about what
wn a=new wn();tries to do what it can't do.

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    need to be stored once centrally (in the superclass) and are then automatically available to subclasses.
    Subclasses also profit immediately from changes (although the changes can also render them invalid!).
    Inheritance provides very strong links between the superclass and the subclass. The subclass must
    possess detailed knowledge of the implementation of the superclass, particularly for redefinition, but also in
    order to use inherited components.
    Even if, technically, the superclass does not know its subclasses, the
    subclass often makes additional requirements of the superclass, for example, because a subclass needs
    certain protected components or because implementation details in the superclass need to be changed in
    the subclass in order to redefine methods.
    The basic reason is that the developer of a (super)class cannot
    normally predict all the requirements that subclasses will later need to make of the superclass.
    Inheritance provides an extension of the visibility concept: there are protected components. The visibility of
    these components lies between that of the public components (visible to all users, all subclasses, and the class itself), and private (visible only to the class itself). Protected components are visible to and can be used by all subclasses and the class itself.
    Subclasses cannot access the private components  particularly attributes) of the superclass. Private
    components are genuinely private. This is particularly important if a (super)class needs to make local
    enhancements to handle errors: it can use private components to do this without knowing or invalidating
    subclasses.
    Create your class inse24 and inherit this CL_GUI_TEXTEDIT
    class in yours. You can then access the protected methods.
    Hope this is helpful, <REMOVED BY MODERATOR>
    Edited by: Runal Singh on Feb 8, 2008 1:08 PM
    Edited by: Alvaro Tejada Galindo on Feb 19, 2008 2:19 PM

  • Protected methods not so protected

    Hi,
    I thought that a protected method could be called only by the methods of
    the same class or the methods of a descendant class.
    So I have been a bit surprised when I constated that a class
    of a given package can access the protected method of all the classes in the same package !! I thought that this behaviour was reserved to the method with no access modifiers.
    Example :
    package mypackage;
    * A first class with a protected method
    public class HasProtectedMethod {
    protected void iAmProtected() {
    System.out.print("I am protected");
    * Another class in the same package trying to access the protected
    * method of the first class
    package com.akazi.flowmind.modeling.gui;
    import com.akazi.flowmind.modeling.gui.dialog.HasProtectedMethod;
    public class Test {
    static public void main(String[] args) {
    new Test().callProtected();
    public void callProtected() {
    HasProtectedMethod method = new HasProtectedMethod();
    method.iAmProtected();
    This code is perfectly compiling and running under JBuilder6 and I wonder if this is correct...

    This is very odd to me.
    In my application, I've got a bunch of classes with subclasses, and I want the protected methods to be accessible only to the subclasses, not to the rest of the stuff in the package.
    Is there no way to keep these protected methods and member variables safe, other than to make a package for each superclass? That means that the client application I am writing will baloon from one package to around 46. Ugh.
    So should I just give up on data hiding for now? Did I design this thing all wrong? Maybe we're supposed to use lots and lots of packages. What do people do?
    --- Eric

  • Why Java doesn't allow to reduce the accessibility of a method du

    Why Java compiler does not allow to reduce the accessibility of a method during inheritance?
    ( Eg; If the base class has a public method and if that method is overridden in child class but
    with defuault access, it gives compile error)
    Supposed answer:
    Because in the runtime, it cannot check the access modifier.
    Suppose A is the base class. It has a method fun() as public.
    B is the derived class of A.
    Suppose in some other class (say C) there is a method myFun() which takes A as parameter and
    calls the fun() method of A. So that method can take B
    also as parameter (As it is derived from A).
    So if the fun() method's accessibility is reduced in B, whether "that can
    be called in C or not" is not known. that is why compiler does not
    allow the reduce the accessibility of a method during inheritance.
    Member variables do not have this problem as they can be checked at
    compile time.
    Is this explanation correct?

    You can give private access, sort of... you could fake it, if the goal is to prevent someone from doing what the method does. Of course, they could (as long as A isn't abstract) create their own A and do whatever they want.
    class A {
       public void doThis() {
    class B extends A {
       public void doThis() {
          // explicitly do nothing
    }But I think generally, this shouldn't be a problem. I'm not sure if it's something that is common for creating an API to subclass another class to hide the superclass's methods. Usually you are adding functionality to a subclass that is for more specific things then the superclass supports. I mention creating an API because if it's just for some application class, then you are writing it, so use or not use the methods as you want. It's APIs for library type classes that other people would use, and if you are extending the library, and really need people not to call methods for some reason, document it. Maybe a good place for an assertion?

  • How to use protected method in jsp code

    Could anyone tell me how to use protected method in jsp code ...
    I declare a Calendar class , and I want to use the isTimeSet method ,
    But if I write the code as follows ..
    ========================================================
    <%
    Calendar create_date = Calendar.getInstance();
    if (create_date.isTimeSet) System.out.println("true");
    %>
    ============================================================
    when I run this jsp , it appears the error wirtten "isTimeSet has protected access in java.util.Calendar"

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    MyCalendar extends Calendar
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  • Not sure how to use protected method in arraylisy

    Hi,
    Im wondering how to use the removeRange method in java arraylist, its a protected method which returns void.
    http://java.sun.com/j2se/1.3/docs/api/java/util/ArrayList.html#removeRange(int,%20int)
    So if my class extends Arraylist i should be able to call the method but the compiler states that it still has protected access in arraylist. Does this mean im still overriding the method in arraylist ? A little explanation of whats happeneing would be appreciated as much as an answer
    thanks

    In this codefinal class myClass extends java.util.ArrayList {
        private ArrayList array = new ArrayList();
        public myClass(ArrayList ary){
            for(int i=0;i<7;i++) {
                array.add(ary.get(i));
            ary.removeRange(0,7)
    }You are defining a class called myClass which extends ArrayList.
    You have a member variable called array which is an ArrayList
    You have a constructor which takes a parameter called ary which is an ArrayList
    Since ary is an ArrayList, you cannot call it's removeRange() method unless myClass is in the java.util package. Do not put your class in the java.util package.
    It seems like what you want to do is to move the items in one ArrayList to another ArrayList rather than copying them. I wrote a program to do this. Here it isimport java.util.*;
    public class Test3 {
      public static void main(String[] args) {
        MyClass myClass = new MyClass();
        for (int i=0; i<5; i++) myClass.add("Item-"+i);
        System.out.println("------ myClass loaded -------");
        for (int i=0; i<myClass.size(); i++) System.out.println(myClass.get(i));
        MyClass newClass = new MyClass(myClass);
        System.out.println("------ newClass created -------");
        for (int i=0; i<newClass.size(); i++) System.out.println(newClass.get(i));
        System.out.println("------ myClass now contains -------");
        for (int i=0; i<myClass.size(); i++) System.out.println(myClass.get(i));
    class MyClass extends java.util.ArrayList {
        public MyClass() {}
        public MyClass(MyClass ary){
            for(int i=0;i<ary.size();i++) add(ary.get(i));
            ary.removeRange(0,ary.size());
    }You should notice now that I don't create an ArrayList anywhere. Everything is a MyClass. By the way, class names are normally capitalized, variable names are not. Hence this line
    MyClass myClass = new MyClass();
    In the code above I create an empty MyClass and then populate it with 5 items and then print that list. Then I create a new MyClass using the constructor which takes a MyClass parameter. This copies the items from the parameter list into the newly created MyClass (which is an ArrayList) and then removes the items from the MyClass passed as a parameter. Back in the main() method, I then print the contents of the two MyClass objects.
    One thing which may be a little confusing is this line.
    for(int i=0;i<ary.size();i++) add(ary.get(i));
    the add() call doesn't refer to anything. What it really refers to is the newly created MyClass object which this constructor is building. This newly created object is the 'this' object. So the line above could be rewritten as
    for(int i=0;i<ary.size();i++) this.add(ary.get(i));
    Hopefully this helps a little. The problems you seem to be having are associated with object oriented concepts. You might try reading this
    http://sepwww.stanford.edu/sep/josman/oop/oop1.htm

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