Java .class files - Moving the Main Class .class file to a new location
Novice question....so much so that I hope it's even coherent...
In a Java program which references many associated .class files (e.g. bicycleMain.class, bicycleSub1.class, bicycleSub2.class, etc....), do the associated .class files always have to be located in the same directory as the Main .class file?
What I'm getting at is - If I've developed an application consisting of several .class files on my own Windows PC and I want to put the compiled application out on our Windows File Server so that anyone can execute my application, how would I go about doing this?
Say I put the compiled .class files in H:\PROJECTS\JAVA\COMPILED\, will other people be able to execute the application from their PCs by simply issuing the command line:
'java h:\projects\java\compiled\bicycleMain'
Any insights would be very helpful in getting me oriented. Thanks in advance.
Interesting...so are you saying the command line might look something like this:
java -classpath h:\projects\java\compiled bicycleMain
And if I want other people to be able to execute the application without specifying the -classpath option then they would need to manually update the ClassPath environment variable on their individual PCs first?
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AppleScript: copy a file to a new location, changing its name
I want to copy a selected file to a new location and change its name, both location and name adjustable by the user. It would seem natural to me (a neophyte) to use the Duplicate and Choose File Name commands to do this, so this is the module I came up with:
tell application "Finder"
set myFile to the selection
set textsAlias to alias "Campidoglio:Users:jeffreyjdean:Dropbox:Tinctoris:Editing Software:TextToJS:texts:"
set fileForConversion to choose file name default name "shortname.txt" default location textsAlias
try
duplicate document file myFile to fileForConversion with replacing
on error
display dialog "Error: Unable to save file."
end try
end tell
This doesn't work. The error dialog comes up and this is the result report:
tell application "Finder"
get selection
--> {document file "12 De inventione et usu musice.txt" of folder "Edited texts" of folder "Desktop" of folder "jeffreyjdean" of folder "Users" of startup disk}
choose file name default name "shortname.txt" default location alias "Campidoglio:Users:jeffreyjdean:Dropbox:Tinctoris:Editing Software:TextToJS:texts:"
--> file "Campidoglio:Users:jeffreyjdean:Dropbox:Tinctoris:Editing Software:TextToJS:texts:shortname.txt"
-- 'core'\'clon'{ 'insh':'furl'("file://localhost/Users/jeffreyjdean/Dropbox/Tinctoris/Editing%20 Software/TextToJS/texts/shortname.txt"), 'alrp':'true'("true"), '----':'obj '{ 'form':'indx', 'want':'docf', 'seld':[ 'obj '{ 'form':'name', 'want':'docf', 'seld':'utxt'("12 De inventione et usu musice.txt"), 'from':'obj '{ 'form':'name', 'want':'cfol', 'seld':'utxt'("Edited texts"), 'from':'obj '{ 'form':'name', 'want':'cfol', 'seld':'utxt'("Desktop"), 'from':'obj '{ 'form':'name', 'want':'cfol', 's…
--> error number -1700 from {document file "12 De inventione et usu musice.txt" of folder "Edited texts" of folder "Desktop" of folder "jeffreyjdean" of folder "Users" of startup disk} to integer
display dialog "Error: Unable to save file."
--> {button returned:"OK"}
end tell
Result:
{button returned:"OK"}
Why is it telling me it can't duplicate a file to an integer? According to the AS Language Guide, the result of Choose File Name is "The selected location, as a file." How does this become an integer in my script?
That may be a side show. What I really want to work out is how to achieve the aim stated at the beginning: take a selected file (that part is working OK) and duplicate it to an arbitrary location with an arbitrary new name, decided by the user. What's the best way to go about this?
TIA,
Jeff
Message was edited by: Jeffrey DeanI think you're misinterpreting the error message.
It's not complaining about your 'Choose File Name', per se.
There are two problems with your script.
First, you:
set myFile to the selection
As far as the Finder is concerned, 'selection' is a list. It's always a list, even if only one item is selected - heck, it's still a list if no files are selected... just an empty list.
So that's the first thing the script is complaining about - you are using a list that you're trying to coerce to a file. Can't happen.
You have a couple of options here, depending on what you want to do.
You can tell the Finder to duplicate a list - it will simply duplicate all the files in the list. It has no problem with that, although you're going to run into problems when you try to set the file name(s). This highlights one of the design flaws with your script - how do you know the user only has one thing selected? At the very least you should check how many items are selected and react accordingly.
The other option is to iterate through the list, duplicating each file in turn. Again, it's not clear what you want/expect the outcome to be here - since you include 'with replacing', you'd likely end up with one file (the last one in the list) as being the named file and all other duplicates lost.
The third option is to expect there to be one item selected, and just act upon the first one - thereby ignoring multiple selections, although it's undefined as to which item is 'first' in the list.
Your call.
Once you get over the issue of identifying what you want to duplicate, the second issue with your script is how you're calling duplicate. You cannot duplicate one file to another file name. The duplicate command expects (demands?) a directory as the 'to' parameter, not a file name.
In other words, you can duplicate a file to a new directory. You cannot duplicate it to a new file name - at least not in one step. In order to do that you need to duplicate the file, then change its name (or use a shell script to do it 'under the hood').
This is complicated by the fact that it's the rename that requires you to check for duplicates, which you have to do manually.
So given the above, and assuming you expect/want one item to be selected, your script should look more like:
tell application "Finder"
set myFile to item 1 of (get selection) -- ignore multiple selections
set textsAlias to alias "Campidoglio:Users:jeffreyjdean:Dropbox:Tinctoris:Editing Software:TextToJS:texts:"
set fileForConversion to choose file name default name "shortname.txt" default location textsAlias
set fDir to do shell script "/usr/bin/dirname " & POSIX path of fileForConversion
set fName to do shell script "/usr/bin/basename " & POSIX path of fileForConversion
try
set newFile to duplicate myFile to POSIX file fDir with replacing
if (exists file fName of folder fDir) then
delete file fName of folder fDir
end if
set name of newFile to fName
on error
display dialog "Error: Unable to save file."
end try
end tell
Incidentally, this is something that could be much more easily done with a shell command, since the shell isn't as sensitive about file paths and data types. -
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Hi,
Where is the .java.policy file located. Do I have to create it? Do I have to use any editor for this? Please help me.
Thank you,
Regards
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That didn't help me. I am talking about the bar that looks like this the one in the picture. I know how to remove items from my bookmarks, but the items on this little menu/link bar are not all a part of my bookmarks, which makes me wonder if this is the bookmarks toolbar.
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Wait for download to complete, then copy the file to a new location
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I added a couple of things like subfolder recusion ( by tweaking scripts I found) .
Would you be kind enough to look this over and see if it's ok or needs fixing?
Thanks for any help,
ec
[code]
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End If
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ReDim Preserve vFolder(UBound(vFolder) + 1)
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[/code] -
A script for copying smilar files to a new location
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The script sees a file name like "ABC**FGH**.tif", it should search the source location and copy the files having filenames with at least this characters e.g. "ABC02FGH02.tif", "ABC03FGH04.tif" should be copied since it has
contains "ABC**FGH**.tif".
Please help.Learn how to use wildcards in file names. '*' is for any number of characters and'?' is for one character.
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Start by using DIR
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I AM CONCERNED THAT SOMEONE IS TRYING TO HACK INTO MY BANK ACCOUNT
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Do we have to separate java source files and class files after compiled..
Hi,
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I have compiled java source files into a package and tried to use but the classes can not be found. Should I separate class and source files after compiled with packages names. I hope you understand what i mean.
Thank you
So JagYou can choose to separate the source files or not. It sounds like your problem has to do with Classpath and packages.
If the file c:\base\compute\engine\mysourcefile.java starts with the statement "package engine;" then the fully qualified name of the class is is engine.mysourcefile. If the file c:\base\compute\client\mysourcefile.java starts with the statement "package client;" then its fully qualified name is client.mysourcefile.
In your source files, whenever you refer to a class from another class, the compiler needs the fully qualified class name. You can either import the class or use the fully qualified name. In order for the compiler to find the class, the c:\base\compute directory must be in the Classpath (assuming the package definitions from above).
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In tomcat, I want to know JSP files, Servlets, and Java classes
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Please advise. thanks!!!<servlet-mapping>
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Hi ..... can somebody plz tell me
How to call a Java Class from another Java Class assuming both in the same Package??
I want to call the entire Java Class (not any specific method only........I want all the functionalities of that class)
Please provide me some slotuions!!
Waiting for some fast replies!!
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Smita MohantyHi Smita,
you just need to create an object of that class,thats it. Then you will be able to execute each and every method.
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you have developed A.java and B.java, both are in same package.
in implementaion of B.java
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Hi,
Firstly i'm newbie programmer with little experience, so please help me if u can.
I have found an example on how to create java classes from WSDL under maven:
(...)<taskdef classname="org.codehaus.xfire.gen.WsGenTask" name="wsgen">(...)
I've created the below java class and I create new object of this class: UploadChunk up = new UploadChunk()
and up.setSomething(123) etc....
I have some service for which I have to prepare soap request manually - suitable for my service requests.
I'm doing it using dom4j to create xml documents and i rewrite values to it from my variable up.
I wonder if it is possible to do it automatically - I have UploadChunk object and I want do use xFire library somehow to produce ready or almost ready soap request. I want to do it in my code, no some ant or maven task.
So I propably need a couple line of code, when I have:
up.setSomething(123);
//////CONVERTION - CAN U TELL ME HOW TO DO THAT PLEASE? I haven't found the way :( it seems I need your help.
//////Document result =....
callService(result,namespace,qname);
import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlType;
* <p>Java class for UploadChunk complex type.
* <p>The following schema fragment specifies the expected content contained within this class.
* <pre>
* <complexType name="UploadChunk">
* <complexContent>
* <restriction base="{http://www.w3.org/2001/XMLSchema}anyType">
* <sequence>
* <element name="SessionID" type="{http://www.w3.org/2001/XMLSchema}string" minOccurs="0"/>
* <element name="InputFileName" type="{http://www.w3.org/2001/XMLSchema}string" minOccurs="0"/>
* <element name="Buffer" type="{http://www.w3.org/2001/XMLSchema}base64Binary" minOccurs="0"/>
* <element name="Offset" type="{http://www.w3.org/2001/XMLSchema}long"/>
* <element name="BytesRead" type="{http://www.w3.org/2001/XMLSchema}int"/>
* </sequence>
* </restriction>
* </complexContent>
* </complexType>
* </pre>
@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "UploadChunk", propOrder = {
"sessionID",
"inputFileName",
"buffer",
"offset",
"bytesRead"
public class UploadChunk {
@XmlElement(name = "SessionID")
protected String sessionID;
@XmlElement(name = "InputFileName")
protected String inputFileName;
@XmlElement(name = "Buffer")
protected byte[] buffer;
@XmlElement(name = "Offset")
protected long offset;
@XmlElement(name = "BytesRead")
protected int bytesRead;
* Gets the value of the sessionID property.
* @return
* possible object is
* {@link String }
public String getSessionID() {
return sessionID;
* Sets the value of the sessionID property.
* @param value
* allowed object is
* {@link String }
public void setSessionID(String value) {
this.sessionID = value;
* Gets the value of the inputFileName property.
* @return
* possible object is
* {@link String }
public String getInputFileName() {
return inputFileName;
* Sets the value of the inputFileName property.
* @param value
* allowed object is
* {@link String }
public void setInputFileName(String value) {
this.inputFileName = value;
* Gets the value of the buffer property.
* @return
* possible object is
* byte[]
public byte[] getBuffer() {
return buffer;
* Sets the value of the buffer property.
* @param value
* allowed object is
* byte[]
public void setBuffer(byte[] value) {
this.buffer = ((byte[]) value);
* Gets the value of the offset property.
public long getOffset() {
return offset;
* Sets the value of the offset property.
public void setOffset(long value) {
this.offset = value;
* Gets the value of the bytesRead property.
public int getBytesRead() {
return bytesRead;
* Sets the value of the bytesRead property.
public void setBytesRead(int value) {
this.bytesRead = value;
}Hi,
Can u Please post the WSDL..here. I remember long back i resolved this kind of issue...when i was getting "*parameters is already defined in - - -*" while using ClientGen.
Once i will get the WSDL may be i can recall it...
If u have any problem in Posting the WSDL..in Forums .. then let me know I will send my E-Mail Address...
As far as i remember ..it usually happens when we Run ClientGen task of WLS81 ON the WebService/WSDL generated by WebLogic 9.x or Above. Please let me know if this is the Case with you as well... . I remember there is a Patch for it...for WLS8 ClientGen task...I dont remember the Patch Number Exactly.
Just For testing:
Just Use WLS9.x ClientGen task On the Same WSDL
<taskdef name="clientgen" classname="weblogic.wsee.tools.anttasks.ClientGenTask" />
I am sure you will not see this issue... because the issue is there only with WLS8 Clientgen...
Thanks
Jay SenSharma
http://jaysensharma.wordpress.com (WebLogic Wonders Are Here)
Edited by: Jay SenSharma on Jan 8, 2010 4:32 PM
Edited by: Jay SenSharma on Jan 8, 2010 4:34 PM
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