Java inheritance problem

Question

class Super {
public void method1() {
method2();
private void method2() {
System.out.println("Method2.....Super");
class Sub extends Super {
private void method2() {
System.out.println("Method2.....Sub");
public static void main(String [] a) {
Super sup = new Super();
sup.method1();
output :- Method2.....Super
Hi,
Can anyone explain why this program executes method2() from super class ? I thought method2() from the Sub class should be executed.

Answer 1

sprizor wrote:
DrLaszloJamf is correct.
If you don't want method2 public but you still want to be able to override/use it in subclasses, make it protected instead.I wrote "method2 can not be private". It can be public, protected or the default access level (when Super and Sub are defined in the same package).
I strongly recommend using the @Override attribute which will generate a compile-time error if you fail to override correctly:
class Super {
    public void method1() {
        method2();
    void method2() {
        System.out.println("Method2.....Super");
class Sub extends Super {
    @Override void method2() {
        System.out.println("Method2.....Sub");
    public static void main(String[] a) {
        Super sup = new Sub();
        sup.method1();
}